cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-5 of 5 results.

A324879 Numbers k such that A324863(k) is equal to A324874(k).

Original entry on oeis.org

1, 9, 15, 16, 21, 27, 35, 39, 55, 57, 64, 75, 77, 85, 87, 90, 91, 95, 99, 105, 111, 115, 119, 125, 129, 133, 143, 147, 155, 159, 161, 175, 183, 185, 189, 195, 201, 203, 205, 209, 213, 221, 235, 237, 243, 245, 253, 256, 259, 265, 267, 275, 285, 287, 295, 299, 301, 303, 319, 321, 323, 325, 335, 339, 341, 351, 355, 363, 365
Offset: 1

Views

Author

Antti Karttunen, Mar 27 2019

Keywords

Comments

In range 1..10000, there are only three such numbers k for which A324868(k) == A000120(A324866(k)): 1, 9, 125. See A324201.

Crossrefs

Subsequences: A324201, A324880 (even terms).

Programs

A324880 Even numbers k such that A324863(k) = A324874(k).

Original entry on oeis.org

16, 64, 90, 256, 484, 490, 750, 756, 810, 988, 1000, 1024, 1296, 1440, 2116, 2622, 2662, 3630, 3710, 4004, 4116, 4624, 4896, 4900, 5880, 6426, 6724, 6760, 7290, 7744, 7840, 7920, 8100, 8924, 9604, 10000
Offset: 1

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Author

Antti Karttunen, Mar 27 2019

Keywords

Comments

Of 36 such numbers found in the range 1..10000, the following ten: 90, 490, 750, 810, 2622, 2662, 3630, 3710, 6426, 7290, are such that a positive integer of the form 4m+1 is produced when A156552 is applied to them: 45, 105, 117, 189, 225, 405, 765, 2205, 2565, 262185 (when sorted into ascending order). See also A324647.

Crossrefs

Programs

  • PARI
    for(n=1,10000,if(!(n%2)&&A324863(n)==A324874(n), print1(n,", ")));

A324863 Binary length of A324866(n), where A324866(n) = A156552(n) OR (A323243(n) - A156552(n)).

Original entry on oeis.org

0, 1, 2, 2, 3, 3, 4, 3, 3, 4, 5, 4, 6, 5, 4, 4, 7, 4, 8, 5, 5, 6, 9, 5, 5, 7, 4, 6, 10, 5, 11, 5, 6, 8, 5, 5, 12, 9, 7, 6, 13, 6, 14, 7, 5, 10, 15, 6, 6, 5, 8, 8, 16, 5, 6, 7, 9, 11, 17, 6, 18, 12, 6, 6, 7, 7, 19, 9, 10, 6, 20, 6, 21, 13, 5, 10, 6, 8, 22, 7, 6, 14, 23, 7, 8, 15, 11, 8, 24, 6, 7, 11, 12, 16, 9, 7, 25, 6, 7, 6, 26, 9, 27, 9, 6
Offset: 1

Views

Author

Antti Karttunen, Mar 21 2019

Keywords

Comments

Differs from A324861 [binary length of A324876(n)] for the first time at n=50.
Provided that the maximal value that A324861(d) attains among divisors d of n is attained an odd number of times, then a(n) gives that maximal value. It is conjectured that this always holds. Among n = 1..10000, there are only two such cases, where the maximal value occurs more than once among the divisors: 3675 and 7623, where it occurs three times in both (see the examples).

Examples

			For n = 50, we have A156552(50) = 25 and A323243(50) = 31. Taking bitwise-OR (A003986) of 25 and 31-25 = 6, we get 31, in binary "11111", with length 5, thus a(50) = 5.
The rest of examples pertain to the conjectured interpretation of this sequence:
Divisors of 8 are [1, 2, 4, 8]. A324861 applied to these gives values [0, 1, 2, 3], of which the largest is 3, thus a(8) = 3.
Divisors of 25 are [1, 5, 25]. A324861 applied to these gives values [0, 3, 5], of which the largest is 5, thus a(25) = 5.
Divisors of 50 are [1, 2, 5, 10, 25, 50]. A324861 applied to these gives values [0, 1, 3, 4, 5, 4], of which the largest is 5, thus a(50) = 5.
Divisors of 88 are [1, 2, 4, 8, 11, 22, 44, 88]. A324861 applied to these gives values [0, 1, 2, 3, 5, 6, 7, 8], of which the largest is 8, thus a(88) = 8.
Divisors of 3675 are [1, 3, 5, 7, 15, 21, 25, 35, 49, 75, 105, 147, 175, 245, 525, 735, 1225, 3675]. A324861 applied to these gives values [0, 2, 3, 4, 4, 5, 5, 5, 6, 4, 6, 5, 6, 5, 8, 7, 8, 8], of which the largest is 8 (occurs three times), thus a(3675) = 8.
Divisors of 7623 are [1, 3, 7, 9, 11, 21, 33, 63, 77, 99, 121, 231, 363, 693, 847, 1089, 2541, 7623]. A324861 applied to these gives values [0, 2, 4, 3, 5, 5, 6, 6, 6, 7, 7, 7, 6, 8, 6, 9, 9, 9], of which the largest is 9 (occurs three times), thus a(7623) = 9.
		

Crossrefs

Differs from A252464 for the first time at n=25, A324870 gives the differences.

Programs

Formula

a(1) = 0; for n > 1, a(n) = A070939(A324866(n)) = 1 + A000523(A324866(n)).
a(A000040(n)) = n.
a(n) = Max_{d|n} A324861(d) [conjectured].

A324862 a(n) is the binary length of A324878(n).

Original entry on oeis.org

0, 0, 0, 1, 0, 1, 0, 0, 3, 0, 0, 1, 0, 1, 4, 4, 0, 3, 0, 0, 5, 1, 0, 0, 0, 1, 4, 1, 0, 4, 0, 4, 0, 1, 5, 4, 0, 1, 7, 0, 0, 5, 0, 1, 4, 1, 0, 4, 0, 0, 2, 1, 0, 4, 6, 0, 9, 1, 0, 0, 0, 1, 5, 6, 0, 1, 0, 1, 0, 5, 0, 5, 0, 1, 5, 1, 6, 7, 0, 4, 0, 1, 0, 1, 8, 1, 11, 0, 0, 6, 7, 1, 0, 1, 9, 5, 0, 1, 7, 5, 0, 2, 0, 0, 6
Offset: 1

Views

Author

Antti Karttunen, Mar 21 2019

Keywords

Crossrefs

Programs

Formula

If A324878(n) = 0, a(n) = 0, otherwise a(n) = A070939(A324878(n)) = 1 + A000523(A324878(n)).
a(p) = 0 for all primes p.

A324881 Number of nonleading zeros in binary representation of A324398, where A324398(n) = A156552(n) AND (A323243(n) - A156552(n)).

Original entry on oeis.org

0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 3, 2, 0, 0, 0, 0, 4, 0, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 3, 2, 0, 0, 5, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 0, 4, 0, 7, 0, 0, 0, 0, 0, 1, 3, 0, 0, 0, 0, 0, 0, 0, 3, 0, 0, 4, 0, 5, 0, 0, 0, 2, 0, 0, 0, 6, 0, 9, 0, 0, 4, 5, 0, 0, 0, 8, 2, 0, 0, 5, 3, 0, 0, 0, 0, 4
Offset: 1

Views

Author

Antti Karttunen, Mar 27 2019

Keywords

Examples

			For n=4, A324398(4) = 1, in binary "1", thus a(4) = 0.
For n=9, A324398(9) = 6, in binary "110", thus a(9) = 1.
For n=16, A324398(16) = 9, in binary "1001", thus a(16) = 2.
		

Crossrefs

Programs

Formula

a(n) = A080791(A324398(n)) = A324874(n) - A324868(n).
a(p) = 0 for all primes p.
Showing 1-5 of 5 results.