A343700 a(n) is the number of preference profiles in the stable marriage problem with n men and n women such that there are no pairs of people who rank each other first.
0, 2, 9984, 28419102720, 175302739963548794880, 5801674463718565478400000000000000, 2113937863028052653298578438638220083200000000000000, 15500609395854457241550377325238753195602871153217230602240000000000000000
Offset: 1
Keywords
Examples
For n=2, suppose A and B are the men and C and D are the women, then the only two possibilities are the following: a) A prefers C, C prefers B, B prefers D, and D prefers A; 2) A prefers D, D prefers B, B prefers C, and C prefers A.
Links
- Michael De Vlieger, Table of n, a(n) for n = 1..22
- Matvey Borodin, Eric Chen, Aidan Duncan, Tanya Khovanova, Boyan Litchev, Jiahe Liu, Veronika Moroz, Matthew Qian, Rohith Raghavan, Garima Rastogi, and Michael Voigt, Sequences of the Stable Matching Problem, arXiv:2201.00645 [math.HO], 2021.
Programs
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Mathematica
Table[Total[ Table[(-1)^i Binomial[n, i]^2 (n - 1)!^(2 i) i! n!^(2 n - 2 i), {i, 0, n}]], {n, 10}]
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PARI
a(n) = sum(i=0, n, ((-1)^i * binomial(n, i)^2 * (n - 1)!^(2*i) * i! * n!^(2*n - 2*i))); \\ Michel Marcus, Jan 20 2023
Formula
a(n) = Sum_{i = 0..n} ((-1)^i * binomial(n, i)^2 * (n - 1)!^(2i) * i! * n!^(2n - 2i)).
Comments