A344423 a(n) = 10^(2*n+2) + 111*10^n + 1.
212, 11111, 1011101, 100111001, 10001110001, 1000011100001, 100000111000001, 10000001110000001, 1000000011100000001, 100000000111000000001, 10000000001110000000001, 1000000000011100000000001, 100000000000111000000000001, 10000000000001110000000000001
Offset: 0
Links
- Index entries for linear recurrences with constant coefficients, signature (111,-1110,1000).
Programs
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PARI
a(n) = 10^(2*n+2) + 111*10^n + 1
Formula
G.f.: -(13100*x^2 - 12421*x + 212)/(1000*x^3 - 1110*x^2 + 111*x - 1). - Jinyuan Wang, May 22 2021
a(n) = 111*a(n-1) - 1110*a(n-2) + 1000*a(n-3). - Wesley Ivan Hurt, May 22 2021
E.g.f.: exp(x)*(1 + 111*exp(9*x) + 100*exp(99*x)). - Stefano Spezia, May 22 2021
Comments