cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A346878 Sum of the divisors, except for the largest, of the n-th positive even number.

Original entry on oeis.org

1, 3, 6, 7, 8, 16, 10, 15, 21, 22, 14, 36, 16, 28, 42, 31, 20, 55, 22, 50, 54, 40, 26, 76, 43, 46, 66, 64, 32, 108, 34, 63, 78, 58, 74, 123, 40, 64, 90, 106, 44, 140, 46, 92, 144, 76, 50, 156, 73, 117, 114, 106, 56, 172, 106, 136, 126, 94, 62, 240, 64, 100, 186, 127
Offset: 1

Views

Author

Omar E. Pol, Aug 20 2021

Keywords

Comments

Sum of aliquot divisors (or aliquot parts) of the n-th positive even number.
a(n) has a symmetric representation.

Examples

			For n = 5 the 5th even number is 10 and the divisors of 10 are [1, 2, 5, 10] and the sum of the divisors of 10 except for the largest is 1 + 2 + 5 = 8, so a(5) = 8.
		

Crossrefs

Programs

  • Mathematica
    a[n_] := DivisorSigma[1, 2*n] - 2*n; Array[a, 100] (* Amiram Eldar, Aug 20 2021 *)
  • PARI
    a(n) = sigma(2*n) - 2*n; \\ Michel Marcus, Aug 20 2021
  • Python
    from sympy import divisors
    def a(n): return sum(divisors(2*n)[:-1])
    print([a(n) for n in range(1, 65)]) # Michael S. Branicky, Aug 20 2021
    

Formula

a(n) = A001065(2*n).
a(n) = 1 + A346880(n).
Sum_{k=1..n} a(k) = (5*Pi^2/24 - 1) * n^2 + O(n*log(n)). - Amiram Eldar, Mar 17 2024

A347154 Sum of all divisors, except the largest of every number, of the first n positive even numbers.

Original entry on oeis.org

1, 4, 10, 17, 25, 41, 51, 66, 87, 109, 123, 159, 175, 203, 245, 276, 296, 351, 373, 423, 477, 517, 543, 619, 662, 708, 774, 838, 870, 978, 1012, 1075, 1153, 1211, 1285, 1408, 1448, 1512, 1602, 1708, 1752, 1892, 1938, 2030, 2174, 2250, 2300, 2456, 2529, 2646, 2760
Offset: 1

Views

Author

Omar E. Pol, Aug 20 2021

Keywords

Comments

Sum of all aliquot divisors (or aliquot parts) of the first n positive even numbers.
Partial sums of the even-indexed terms of A001065.
a(n) has a symmetric representation.

Crossrefs

Programs

  • Mathematica
    s[n_] := DivisorSigma[1, 2*n] - 2*n; Accumulate @ Array[s, 100] (* Amiram Eldar, Aug 20 2021 *)
  • PARI
    a(n) = sum(k=1, n, k*=2; sigma(k)-k); \\ Michel Marcus, Aug 20 2021
    
  • Python
    from sympy import divisors
    from itertools import accumulate
    def A346878(n): return sum(divisors(2*n)[:-1])
    def aupton(nn): return list(accumulate(A346878(n) for n in range(1, nn+1)))
    print(aupton(51)) # Michael S. Branicky, Aug 20 2021
    
  • Python
    from math import isqrt
    def A347154(n): return (t:=isqrt(m:=n>>1))**2*(t+1) - sum((q:=m//k)*((k<<1)+q+1) for k in range(1,t+1))-3*((s:=isqrt(n))**2*(s+1) - sum((q:=n//k)*((k<<1)+q+1) for k in range(1,s+1))>>1)-n*(n+1) # Chai Wah Wu, Nov 02 2023

Formula

a(n) = n + A346870(n).
a(n) = (5*Pi^2/24 - 1) * n^2 + O(n*log(n)). - Amiram Eldar, May 15 2023

A346877 Sum of the divisors, except for the largest, of the n-th odd number.

Original entry on oeis.org

0, 1, 1, 1, 4, 1, 1, 9, 1, 1, 11, 1, 6, 13, 1, 1, 15, 13, 1, 17, 1, 1, 33, 1, 8, 21, 1, 17, 23, 1, 1, 41, 19, 1, 27, 1, 1, 49, 19, 1, 40, 1, 23, 33, 1, 21, 35, 25, 1, 57, 1, 1, 87, 1, 1, 41, 1, 29, 65, 25, 12, 45, 31, 1, 47, 1, 27, 105, 1, 1, 51, 25, 35, 81, 1, 1, 81, 37
Offset: 1

Views

Author

Omar E. Pol, Aug 20 2021

Keywords

Comments

Sum of aliquot divisors (or aliquot parts) of the n-th odd number.
a(n) has a symmetric representation.

Examples

			For n = 5 the 5th odd number is 9 and the divisors of 9 are [1, 3, 9] and the sum of the divisors of 9 except for the largest is 1 + 3 = 4, so a(5) = 4.
		

Crossrefs

Programs

  • Mathematica
    a[n_] := DivisorSigma[1, 2*n - 1] - 2*n + 1; Array[a, 100] (* Amiram Eldar, Aug 20 2021 *)
    Total[Most[Divisors[#]]]&/@Range[1,161,2] (* Harvey P. Dale, Sep 29 2024 *)
  • PARI
    a(n) = sigma(2*n-1) - (2*n-1); \\ Michel Marcus, Aug 20 2021
  • Python
    from sympy import divisors
    def a(n): return sum(divisors(2*n-1)[:-1])
    print([a(n) for n in range(1, 79)]) # Michael S. Branicky, Aug 20 2021
    

Formula

a(n) = A001065(2*n-1).
a(n) = A057427(n-1) + A346879(n).
G.f.: Sum_{k>=0} (2*k + 1) * x^(3*k + 2) / (1 - x^(2*k + 1)). - Ilya Gutkovskiy, Aug 20 2021
Sum_{k=1..n} a(k) = (Pi^2/8 - 1)*n^2 + O(n*log(n)). - Amiram Eldar, Mar 17 2024
Showing 1-3 of 3 results.