A114362 Numerator of zeta(4n)/zeta(2n)^2 (with a(0)=2 instead of -2).
2, 2, 6, 691, 7234, 523833, 3545461365, 3392780147, 15418642082434, 26315271553053477373, 261082718496449122051, 2530297234481911294093, 39265823582984723803743892829, 61628132164268458257532691681
Offset: 0
Examples
2/1, 2/5, 6/7, 691/715, 7234/7293, 523833/524875, 3545461365/3547206349, ...
Links
- Seiichi Manyama, Table of n, a(n) for n = 0..158
- Winfried Kohnen, Transcendence conjectures about periods of modular forms and rational structures on spaces of modular forms, Proceedings of the Indian Academy of Sciences-Mathematical Sciences, Vol. 99, No. 3 (1989), pp. 231-233.
- Herbert Wilf, Problem 11068, The American Mathematical Monthly, Vol. 111, No. 3 (2004), p. 259; Think Rationally, Solution to Problem 11068 by Kenneth E. Schilling, ibid., Vol. 112, No. 9 (2005), pp. 844-845.
Programs
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Mathematica
a[n_] := Numerator[Zeta[4*n]/Zeta[2*n]^2]; a[0] = 2; Array[a, 14, 0] (* Amiram Eldar, Mar 04 2023 *)
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PARI
z(n)=bernfrac(2*n)*(-1)^(n - 1)*2^(2*n-1)/(2*n)!; a(n)=if(n<1,2,numerator(z(2*n)/z(n)^2))
Formula
Product_{p primes} (p^{2n}-1)/(p^{2n}+1) = zeta(4n)/zeta(2n)^2.
For n > 0, a(n) = Numerator((D(n) - N(n)) / (D(n) + N(n))), where N(n) = A348829(n) and D(n) = A348830(n). See my comments and formulas in A348829. - Thomas Ordowski, Jan 05 2022
From Amiram Eldar, Mar 04 2023: (Start)
a(n)/A114363(n) = -2*B(4*n)/(binomial(4*n,*2n)*B(2*n)) = -2*(A027641(4*n)/A027642(4*n))/(A000984(2*n)*A027641(2*n)/A027642(2*n)), for n >= 1, where B(n) is the n-th Bernoulli number.
A114363(n)/a(n) = Sum_{x in Q+} 1/f(x)^(2*n), for n >= 1, where Q+ is the set of the positive rational numbers, and if x = k/m in lowest terms, then f(x) = k*m (Wilf, 2004). (End)
Comments