cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-6 of 6 results.

A366438 The number of divisors of the exponentially odd numbers (A268335).

Original entry on oeis.org

1, 2, 2, 2, 4, 2, 4, 4, 2, 2, 4, 4, 2, 2, 4, 4, 2, 8, 4, 4, 2, 8, 2, 6, 4, 4, 4, 2, 4, 4, 8, 2, 8, 2, 4, 2, 4, 2, 8, 4, 8, 4, 4, 2, 2, 4, 4, 8, 2, 4, 8, 2, 2, 4, 4, 8, 2, 4, 2, 4, 4, 4, 8, 2, 4, 4, 4, 4, 12, 2, 2, 8, 2, 8, 8, 4, 2, 2, 8, 4, 2, 8, 4, 4, 4, 16, 4
Offset: 1

Views

Author

Amiram Eldar, Oct 10 2023

Keywords

Comments

1 is the only odd term in this sequence.

Crossrefs

Programs

  • Mathematica
    f[n_] := Module[{e = FactorInteger[n][[;; , 2]]}, If[AllTrue[e, OddQ], Times @@ (e + 1), Nothing]]; f[1] = 1; Array[f, 150]
  • PARI
    lista(max) = for(k = 1, max, my(e = factor(k)[, 2], isexpodd = 1); for(i = 1, #e, if(!(e[i] % 2), isexpodd = 0; break)); if(isexpodd, print1(vecprod(apply(x -> x+1, e)), ", ")));
    
  • Python
    from math import prod
    from itertools import count, islice
    from sympy import factorint
    def A366438_gen(): # generator of terms
        for n in count(1):
            f = factorint(n).values()
            if all(e&1 for e in f):
                yield prod(e+1 for e in f)
    A366438_list = list(islice(A366438_gen(),30)) # Chai Wah Wu, Oct 10 2023

Formula

a(n) = A000005(A268335(n)).

A366440 The sum of divisors of the cubefree numbers (A004709).

Original entry on oeis.org

1, 3, 4, 7, 6, 12, 8, 13, 18, 12, 28, 14, 24, 24, 18, 39, 20, 42, 32, 36, 24, 31, 42, 56, 30, 72, 32, 48, 54, 48, 91, 38, 60, 56, 42, 96, 44, 84, 78, 72, 48, 57, 93, 72, 98, 54, 72, 80, 90, 60, 168, 62, 96, 104, 84, 144, 68, 126, 96, 144, 72, 74, 114, 124, 140
Offset: 1

Views

Author

Amiram Eldar, Oct 10 2023

Keywords

Crossrefs

Programs

  • Mathematica
    f[p_, e_] := (p^(e+1)-1)/(p-1); s[n_] := Module[{fct = FactorInteger[n]}, If[AllTrue[fct[[;;, 2]], # < 3 &], Times @@ f @@@ fct, Nothing]]; s[1] = 1; Array[s, 100]
  • PARI
    lista(max) = for(k = 1, max, my(f = factor(k), iscubefree = 1); for(i = 1, #f~, if(f[i, 2] > 2, iscubefree = 0; break)); if(iscubefree, print1(sigma(f), ", ")));
    
  • Python
    from sympy import mobius, integer_nthroot, divisor_sigma
    def A366440(n):
        def f(x): return n+x-sum(mobius(k)*(x//k**3) for k in range(1, integer_nthroot(x,3)[0]+1))
        m, k = n, f(n)
        while m != k:
            m, k = k, f(k)
        return divisor_sigma(m) # Chai Wah Wu, Aug 06 2024

Formula

a(n) = A000203(A004709(n)).
Sum_{k=1..n} a(k) ~ c * n^2, where c = 15*zeta(3)/(2*Pi^2) = A082020 * A002117 / 2 = 0.913453711751... .
The asymptotic mean of the abundancy index of the cubefree numbers: Limit_{m->oo} (1/m) * Sum_{k=1..m} a(k)/A004709(k) = 15/Pi^2 = 1.519817... (A082020).

A366536 The number of unitary divisors of the cubefree numbers (A004709).

Original entry on oeis.org

1, 2, 2, 2, 2, 4, 2, 2, 4, 2, 4, 2, 4, 4, 2, 4, 2, 4, 4, 4, 2, 2, 4, 4, 2, 8, 2, 4, 4, 4, 4, 2, 4, 4, 2, 8, 2, 4, 4, 4, 2, 2, 4, 4, 4, 2, 4, 4, 4, 2, 8, 2, 4, 4, 4, 8, 2, 4, 4, 8, 2, 2, 4, 4, 4, 4, 8, 2, 4, 2, 8, 4, 4, 4, 2, 8, 4, 4, 4, 4, 4, 2, 4, 4, 4, 2, 8
Offset: 1

Views

Author

Amiram Eldar, Oct 12 2023

Keywords

Comments

The number of unitary divisors of the squarefree numbers (A005117) is the same as the number of divisors of the squarefree numbers (A072048), because all the divisors of a squarefree number are unitary.

Crossrefs

Programs

  • Mathematica
    f[n_] := Module[{e = FactorInteger[n][[;; , 2]]}, If[AllTrue[e, # < 3 &], 2^Length[e], Nothing]]; f[1] = 1; Array[f, 150]
  • PARI
    lista(max) = for(k = 1, max, my(e = factor(k)[, 2], iscubefree = 1); for(i = 1, #e, if(e[i] > 2, iscubefree = 0; break)); if(iscubefree, print1(2^(#e), ", ")));
    
  • Python
    from sympy.ntheory.factor_ import udivisor_count
    from sympy import mobius, integer_nthroot
    def A366536(n):
        def f(x): return n+x-sum(mobius(k)*(x//k**3) for k in range(1, integer_nthroot(x,3)[0]+1))
        m, k = n, f(n)
        while m != k:
            m, k = k, f(k)
        return udivisor_count(m) # Chai Wah Wu, Aug 05 2024

Formula

a(n) = A034444(A004709(n)).

A366537 The sum of unitary divisors of the cubefree numbers (A004709).

Original entry on oeis.org

1, 3, 4, 5, 6, 12, 8, 10, 18, 12, 20, 14, 24, 24, 18, 30, 20, 30, 32, 36, 24, 26, 42, 40, 30, 72, 32, 48, 54, 48, 50, 38, 60, 56, 42, 96, 44, 60, 60, 72, 48, 50, 78, 72, 70, 54, 72, 80, 90, 60, 120, 62, 96, 80, 84, 144, 68, 90, 96, 144, 72, 74, 114, 104, 100, 96
Offset: 1

Views

Author

Amiram Eldar, Oct 12 2023

Keywords

Crossrefs

Programs

  • Mathematica
    s[n_] := Module[{f = FactorInteger[n], e}, e = f[[;;, 2]]; If[AllTrue[e, # < 3 &], Times @@ (1 + Power @@@ f), Nothing]]; s[1] = 1; Array[s, 100]
  • PARI
    lista(max) = for(k = 1, max, my(f = factor(k), e = f[, 2], iscubefree = 1); for(i = 1, #e, if(e[i] > 2, iscubefree = 0; break)); if(iscubefree, print1(prod(i = 1, #e, 1 + f[i, 1]^e[i]), ", ")));
    
  • Python
    from sympy.ntheory.factor_ import udivisor_sigma
    from sympy import mobius, integer_nthroot
    def A366537(n):
        def f(x): return n+x-sum(mobius(k)*(x//k**3) for k in range(1, integer_nthroot(x,3)[0]+1))
        m, k = n, f(n)
        while m != k:
            m, k = k, f(k)
        return udivisor_sigma(m) # Chai Wah Wu, Aug 05 2024

Formula

a(n) = A034448(A004709(n)).
Sum_{k=1..n} a(k) ~ c * n^2 / 2, where c = zeta(3)^2 * Product_{p prime} (1 + 1/p^2 - 2/p^3 + 1/p^4 - 1/p^5) = 1.665430860774244601005... .
The asymptotic mean of the unitary abundancy index of the cubefree numbers: Limit_{m->oo} (1/m) * Sum_{k=1..m} a(k)/A004709(k) = c / zeta(3) = 1.38548421160152785073... .

A358039 a(n) is the Euler totient function phi applied to the n-th cubefree number.

Original entry on oeis.org

1, 1, 2, 2, 4, 2, 6, 6, 4, 10, 4, 12, 6, 8, 16, 6, 18, 8, 12, 10, 22, 20, 12, 12, 28, 8, 30, 20, 16, 24, 12, 36, 18, 24, 40, 12, 42, 20, 24, 22, 46, 42, 20, 32, 24, 52, 40, 36, 28, 58, 16, 60, 30, 36, 48, 20, 66, 32, 44, 24, 70, 72, 36, 40, 36, 60, 24, 78, 40
Offset: 1

Views

Author

Amiram Eldar, Oct 29 2022

Keywords

Comments

The analogous sequence with squarefree numbers is A049200.

Crossrefs

Programs

  • Mathematica
    EulerPhi[Select[Range[100], Max[FactorInteger[#][[;; , 2]]] < 3 &]]
  • Python
    from sympy import mobius, integer_nthroot, totient
    def A358039(n):
        def f(x): return n+x-sum(mobius(k)*(x//k**3) for k in range(1, integer_nthroot(x,3)[0]+1))
        m, k = n, f(n)
        while m != k:
            m, k = k, f(k)
        return totient(m) # Chai Wah Wu, Aug 06 2024

Formula

a(n) = A000010(A004709(n)).
Sum_{k=1..n} a(k) = (c/(2*zeta(3)))*n^2 + O(n^(3/2+eps)), where c = Product_{p prime} (1 - (p+1)/(p^3+p^2+1)) = 0.62583324412633345811... (Weiyi, 2004).
From Amiram Eldar, Oct 09 2023: (Start)
Sum_{n>=1} 1/(A004709(n)*a(n)) = Product_{p prime} (1 + (p^2+1)/((p-1)*p^3)) = 2.14437852780769816048... .
Sum_{n>=1} 1/a(n)^2 = Product_{p prime} (1 + (p^2+1)/((p-1)^2*p^2)) = 3.26032746607943673536... . (End)

A366441 The number of divisors of the 5-rough numbers (A007310).

Original entry on oeis.org

1, 2, 2, 2, 2, 2, 2, 2, 3, 2, 2, 4, 2, 2, 2, 2, 3, 2, 4, 2, 2, 4, 2, 2, 2, 4, 2, 2, 4, 2, 4, 4, 2, 2, 2, 2, 2, 2, 4, 4, 3, 4, 2, 2, 4, 2, 2, 4, 4, 2, 2, 4, 2, 4, 2, 2, 3, 2, 6, 2, 2, 4, 4, 2, 2, 2, 2, 4, 4, 4, 2, 4, 4, 4, 2, 2, 2, 2, 4, 2, 2, 6, 4, 2, 4, 2, 4
Offset: 1

Views

Author

Amiram Eldar, Oct 10 2023

Keywords

Crossrefs

Programs

  • Mathematica
    a[n_] := DivisorSigma[0, 2*Floor[3*n/2] - 1]; Array[a, 100]
  • PARI
    a(n) = numdiv((3*n)\2 << 1 - 1)
    
  • Python
    from sympy import divisor_count
    def A366441(n): return divisor_count((n+(n>>1)<<1)-1) # Chai Wah Wu, Oct 10 2023

Formula

a(n) = A000005(A007310(n)).
Sum_{k=1..n} a(k) ~ (log(n) + 2*gamma - 1 + 2*log(6)) * n / 3, where gamma is Euler's constant (A001620).
Showing 1-6 of 6 results.