A080839
Number of positive increasing integer sequences of length n with Gilbreath transform (that is, the diagonal of leading successive absolute differences) given by {1,1,1,1,1,...}.
Original entry on oeis.org
1, 1, 1, 2, 6, 27, 180, 1786, 26094, 559127, 17535396, 804131875, 53833201737
Offset: 1
The table below shows that {1,2,4,6,10} is one of the 6 sequences of length 5 that satisfy the stated condition:
1
2 1
4 2 1
6 2 0 1
10 4 2 2 1
A363002
Number of positive nondecreasing integer sequences of length n whose Gilbreath transform is (1, 1, ..., 1).
Original entry on oeis.org
1, 1, 1, 2, 5, 17, 82, 573, 5839, 86921, 1890317, 60013894, 2778068147
Offset: 0
For n = 4, the a(4) = 5 sequences are:
(1, 2, 2, 2),
(1, 2, 2, 4),
(1, 2, 4, 4),
(1, 2, 4, 6),
(1, 2, 4, 8).
A363004
Number of sequences of n distinct positive integers whose Gilbreath transform is (1, 1, ..., 1).
Original entry on oeis.org
1, 1, 1, 1, 2, 7, 40, 355, 4819, 99242, 3049155, 138762035
Offset: 0
For n = 5, the a(5) = 7 sequences are:
(1, 2, 4, 6, 8),
(1, 2, 4, 6, 10),
(1, 2, 4, 8, 6),
(1, 2, 4, 8, 10),
(1, 2, 4, 8, 12),
(1, 2, 4, 8, 14),
(1, 2, 4, 8, 16).
A363005
Number of sequences of n distinct integers whose Gilbreath transform is (1, 1, ..., 1).
Original entry on oeis.org
1, 1, 2, 4, 12, 56, 416, 4764, 84272, 2278740, 92890636, 5659487836
Offset: 0
For n = 4, the following 6 sequences, together with the sequences obtained by replacing each term x by 2-x in each of these sequences, have Gilbreath transform (1, 1, 1, 1), so a(4) = 12.
(1, 2, 0, -4),
(1, 2, 0, -2),
(1, 2, 0, 4),
(1, 2, 4, 0),
(1, 2, 4, 6),
(1, 2, 4, 8).
A366032
Difference d between the least odd integer that would disprove Gilbreath's conjecture and prime(n).
Original entry on oeis.org
2, 4, 2, 10, 6, 10, 6, 6, 12, 16, 16, 16, 8, 12, 10, 30, 20, 26, 34, 20, 28, 18, 26, 30, 36, 24, 28, 26, 30, 88, 54, 68, 44, 64, 46, 46, 48, 40, 36, 52, 32, 64, 46, 66, 36, 66, 94, 72, 66, 76, 60, 54, 56, 70, 58, 66, 74, 72, 76, 56, 84, 80, 88, 70, 92, 104, 78, 86, 100, 84, 66, 86, 84, 86, 96
Offset: 3
The first term of the sequence is a(3) = 2 (offset is 3)
We start with the first 2 primes and instead of the third prime, we choose k=7.
2,3 --> 2,3,7 instead of 2,3,5
1 1,4 1,2
3 1
.
k=7 is the least odd integer that disproves the conjecture. So, a(3) = k-prime(3) = 7 - 5 = 2.
.
2,3,5,7,11 --> 2,3,5,7,11,23 instead of 2,3,5,7,11,13
1,2,2,4 1,2,2,4,12 1,2,2,4,2
1,0,2 1,0,2,8 1,0,2,2
1,2 1,2,6 1,2,0
1 1,4 1,2
3 1
k=23 is the least odd integer that disproves the conjecture. So, a(6) = k-prime(6) = 23 - 13 = 10.
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Table[(k=Prime@n;While[Nest[Abs@*Differences,Join[Prime@Range@n,{k}],n]=={1},k=k+2];k)-NextPrime@Prime@n,{n,2,100}]
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isok(v) = my(nb=#v); for (i=1, nb-1, v = vector(#v-1, k, abs(v[k+1]-v[k]));); v[1] == 1;
a(n) = my(v = primes(n-1), k=prime(n)); while (isok(concat(v, k)), k+=2); k - prime(n); \\ Michel Marcus, Sep 28 2023
Showing 1-5 of 5 results.
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