cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A373340 Number of permutations of symmetric group S_n with an odd number of cycles of length 2 or more.

Original entry on oeis.org

0, 0, 1, 5, 20, 84, 424, 2680, 20544, 182336, 1816448, 19963008, 239511040, 3113532928, 43589194752, 653837290496, 10461395173376, 177843714539520, 3201186853912576, 60822550206644224, 1216451004093038592, 25545471085864681472, 562000363888824811520
Offset: 0

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Examples

			a(0)=0 due to the sole permutation in S_0 being the empty permutation, with 0 non-fixed point cycles, not an odd number.
a(1)=0 due to the sole permutation in S_1 being the fixed point (1), with 0 non-fixed point cycles, not an odd number.
a(2)=1 due to 1 permutation in S_2 with an odd number of non-fixed point cycles: (12), with 1 non-fixed point cycle.
a(3)=5 due to 5 permutations in S_3 with an odd number of non-fixed point cycles: (12)(3),(13)(2),(23)(1),(123),(132), all with 1 non-fixed point cycle.
		

Crossrefs

Cf. A373339 (even case), A000142, A001710, A036289.
Row sums of triangle A373418.

Programs

  • PARI
    a(n) = n!/2 + (n-2)*2^(n-2); \\ Michel Marcus, Jun 05 2024

Formula

a(n) = n!/2 + (n-2)*2^(n-2) = A001710(n) + A036289(n-2).
a(n) = A000142(n) - A373339(n).
E.g.f.: (1/(1 - x) - exp(2*x)*(1 - x))/2. - Stefano Spezia, Jun 05 2024

A373417 Triangle T(n,k) for the number of permutations in symmetric group S_n with (n-k) fixed points and an even number of non-fixed point cycles. Equivalent to the number of cycles of n items with cycle type defined by non-unity partitions of k<=n that contain an even number of parts.

Original entry on oeis.org

1, 1, 0, 1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 3, 1, 0, 0, 0, 15, 20, 1, 0, 0, 0, 45, 120, 130, 1, 0, 0, 0, 105, 420, 910, 924, 1, 0, 0, 0, 210, 1120, 3640, 7392, 7413, 1, 0, 0, 0, 378, 2520, 10920, 33264, 66717, 66744, 1, 0, 0, 0, 630, 5040, 27300, 110880, 333585, 667440, 667476
Offset: 0

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Comments

A343418(n) + a(n) = A098825(n) = partial derangement "rencontres" triangle.
A343418(n) - a(n) = (k-1) * binomial(n,k) = A127717(n-1,k-1).
Difference of 1st and 2nd leading diagonals (n > 0).
T(n,n) - T(n,n-1) = -1,0,0,3,5,10,14,21,27,36,44,...
= (-1) + (1+0) + (3+2) + (5+4) + (7+6) + (9+8) + ...
Cf. A176222(n) with 2 terms -1,0 prepended (moving its offset from 3 to 1).

Examples

			Triangle array T(n,k):
  n:  {k<=n}
  0:  {1}
  1:  {1, 0}
  2:  {1, 0, 0}
  3:  {1, 0, 0, 0}
  4:  {1, 0, 0, 0,   3}
  5:  {1, 0, 0, 0,  15,   20}
  6:  {1, 0, 0, 0,  45,  120,   130}
  7:  {1, 0, 0, 0, 105,  420,   910,    924}
  8:  {1, 0, 0, 0, 210, 1120,  3640,   7392,   7413}
  9:  {1, 0, 0, 0, 378, 2520, 10920,  33264,  66717,  66744}
  10: {1, 0, 0, 0, 630, 5040, 27300, 110880, 333585, 667440, 667476}
T(n,0) = 1 due to sole permutation in S_n with n fixed points, namely the identity permutation, with 0 non-fixed point cycles, an even number. (T(0,0)=1 relies on S_0 containing an empty permutation.)
T(n,1) = 0 due to no permutations in S_n with (n-1) fixed points.
T(n,2) = T(n,3) = 0 due to only non-unity partitions of 2 and 3 being of odd length, namely the trivial partitions (2),(3).
Example:
T(4,4) = 3 since S_4 contains 3 permutations with 0 fixed points and an even number of non-fixed point cycles, namely the derangements: (12)(34),(13)(24),(14)(23).
Worked Example:
T(7,6) = 910 permutations in S_7 with 1 fixed point and an even number of non-fixed point cycles.
T(7,6) = 910 possible (4,2)- and (3,3)-cycles of 7 items.
N(n,y) = possible y-cycles of n items.
N(n,y) = (n!/(n-k)!) / (M(y) * s(y)).
y = partition of k<=n with q parts = (p_1, p_2, ..., p_i, ..., p_q)
s.t. k = Sum_{i=1..q} p_i.
Or:
y = partition of k<=n with d distinct parts, each with multiplicity m_j = (y_1^m_1, y_2^m_2, ..., y_j^m_j, ..., y_d^m_d)
s.t. k = Sum_{j=1..d} m_j*y_j.
M(y) = Product_{i=1..q} p_i = Product_{j=1..d} y_j^m_j.
s(y) = Product_{j=1..d} m_j! ("symmetry of repeated parts").
Note: (n!/(n-k)!) / s(y) = multinomial(n, {m_j}).
Therefore:
T(7,6) = N(7,y=(4,2)) + N(7,y=(3^2))
       = (7!/(4*2)) + (7!/(3^2)/2!)
       = 7! * (1/8 + 1/18)
       = 5040 * (13/72)
T(7,6) = 910.
		

Crossrefs

Cf. A373418 (odd case), A373339 (row sums), A216778 (main diagonal).

Programs

  • Maple
    b:= proc(n, t) option remember; `if`(n=0, t, add(expand(`if`(j>1, x^j, 1)*
          b(n-j, irem(t+signum(j-1), 2)))*binomial(n-1, j-1)*(j-1)!, j=1..n))
        end:
    T:= n-> (p-> seq(coeff(p, x, i), i=0..n))(b(n, 1)):
    seq(T(n), n=0..10);  # Alois P. Heinz, Jun 04 2024
  • Mathematica
    Table[Table[n!/(n-k)!/2 * (Sum[(-1)^j/j!, {j, 0, k}] - ((k - 1)/k!)), {k, 0, n}], {n, 0, 10}]

Formula

T(n,k) = (n!/(n-k)!/2) * (Sum_{j=0..k} (-1)^j/j! - (k-1)/k!) Cf. Sum_{j=0..k} (-1)^j/j! = A053557(k) / A053556(k).

A374419 Triangle read by rows: T(n,k) = number of permutations in symmetric group S_n with an even number of non-fixed point cycles, without k<=n particular fixed points.

Original entry on oeis.org

1, 1, 0, 1, 0, 0, 1, 0, 0, 0, 4, 3, 3, 3, 3, 36, 32, 29, 26, 23, 20, 296, 260, 228, 199, 173, 150, 130, 2360, 2064, 1804, 1576, 1377, 1204, 1054, 924, 19776, 17416, 15352, 13548, 11972, 10595, 9391, 8337, 7413, 180544, 160768, 143352, 128000, 114452, 102480, 91885, 82494, 74157, 66744
Offset: 0

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Examples

			Triangle array T(n,k) begins:
  n: {k<=n}
  0:  {1}
  1:  {1,       0}
  2:  {1,       0,       0}
  3:  {1,       0,       0,       0}
  4:  {4,       3,       3,       3,       3}
  5:  {36,      32,      29,      26,      23,      20}
  6:  {296,     260,     228,     199,     173,     150,     130}
  7:  {2360,    2064,    1804,    1576,    1377,    1204,    1054,   924}
T(n,0) = A373339(n) = the number of permutations in S_n without k=0 particular fixed points (i.e., not filtered, so all permutations) with an even number of cycles.
T(n,n) = A216778(n) = the number of permutations in S_n without k=n particular fixed points (i.e., filtered down to just the derangements) with an even number of cycles.
T(4,1<=k<=4) = 3 because S_4 contains 3 permutations with an even number of non-fixed point cycles without k=1,2,3 or 4 particular fixed points, namely the 3 (2,2)-cycles: (12)(34), (13)(24), (14)(23).
T(4,0) = 4 is one more than the above because it includes the permutation without k=0 particular fixed points, i.e., the identity permutation of 4 fixed points.
		

Crossrefs

Cf. A374420 (odd case), A216778 (main diagonal), A373339 (first column).

Programs

  • Mathematica
    Table[Table[1/2*(Sum[(-1)^j*Binomial[k, j]*(n - j)!, {j, 0, k}] + 2^(n - k - 1)*(2 - n - k)), {k, 0, n}], {n, 0, 10}]

Formula

T(n,k) = T(n,k-1) - T(n-1,k-1) with T(n,0) = A373339(n).
T(n,k) = (1/2) * (Sum_{j=0..k} (-1)^j * binomial(k,j) * (n-j)! + 2^(n-k-1)*(2-n-k)).
Showing 1-3 of 3 results.