cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A373804 Primes in A374965 sorted into increasing order.

Original entry on oeis.org

3, 19, 103, 283, 313, 331, 463, 733, 751, 757, 1093, 1153, 1213, 1453, 1543, 1783, 2083, 2251, 2371, 2467, 2671, 2707, 2803, 3733, 3823, 7603, 7723, 8221, 9013, 9661, 14983, 15277, 15607, 16363, 16381, 16843, 17923, 19483, 20287, 21061, 22093, 23173, 24421, 24841, 25903, 27211, 28411
Offset: 1

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Author

N. J. A. Sloane, Aug 08 2024

Keywords

Comments

Since we know the first 350199 terms of A374965, and A374965(350199) = 5026186 starts a new doubling chain, we know that any subsequent prime is greater than 5026186. This implies that the terms in the b-file, which are < 5026186, are correct. Of course, if the sequence reaches a Riesel number (cf. A076337) there will be no more primes after that point.
Note that, as can be seen from the b-file in A375028, A374965 contains many primes greater than 5026186 among the first 350199 terms, including one prime with 102410 digits. But these large primes cannot be added to the present b-file until more is discovered about primes following term 350199.

Crossrefs

A177331 Prime numbers p such that (p*2^k-1)/3 is composite for all even k or all odd k.

Original entry on oeis.org

557, 743, 919, 1163, 3257, 3301, 4817, 5209, 5581, 6323, 6421, 6983, 7457, 7793
Offset: 1

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Author

T. D. Noe, May 08 2010

Keywords

Comments

This sequence consists of the primes >3 for which A177330 is zero. k is even when p=1 (mod 6); k is odd when p=5 (mod 6). This problem is similar to that of finding Sierpinski and Riesel numbers (see A076336 and A076337). Compositeness of (p*2^k-1)/3 for all even or all odd k is established by finding a finite set of primes such that at least one member of the set divides each term. For p <= 7797, the set of primes is {3,5,7,13}.

A236321 Conjectured number of Riesel numbers less than 10^n.

Original entry on oeis.org

0, 0, 0, 0, 0, 5, 65, 668, 6711
Offset: 1

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Author

Arkadiusz Wesolowski, Jan 22 2014

Keywords

Crossrefs

Formula

a(n) ~ A236320(n).

A237880 Conjectured number of distinct integers < 10^n that are Sierpiński or Riesel or simultaneously Sierpiński and Riesel numbers.

Original entry on oeis.org

0, 0, 0, 0, 1, 16, 134, 1345, 13420
Offset: 1

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Author

Arkadiusz Wesolowski, Feb 14 2014

Keywords

Crossrefs

Formula

a(n) = A236320(n) + A236321(n) for n <= 9.

Extensions

Definition clarified by Arkadiusz Wesolowski, Jun 05 2021

A273987 Smallest Riesel number to base n.

Original entry on oeis.org

509203, 63064644938, 9, 346802, 84687, 408034255082, 14, 4, 10176, 862, 25, 302, 4, 36370321851498, 9, 86, 246, 144, 8, 560, 4461, 476, 4, 36, 149, 8, 144, 4, 1369, 134718, 10, 16, 6, 287860, 4, 7772, 13, 4, 81, 8, 15137, 672, 4, 22564, 8177, 14, 3226, 36, 16
Offset: 2

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Author

Tim Johannes Ohrtmann, Jun 06 2016

Keywords

Comments

a(2), a(3), a(5), a(6), a(7), a(10), a(15), a(22), a(23), a(30), ... are only conjectural (see links).

Crossrefs

A085917 Least k such that k*2^n - 1 is a semiprime.

Original entry on oeis.org

5, 4, 2, 1, 3, 5, 4, 2, 1, 2, 1, 3, 6, 3, 3, 3, 3, 6, 3, 3, 3, 2, 1, 3, 6, 3, 6, 3, 6, 3, 3, 11, 16, 8, 4, 2, 1, 8, 4, 2, 1, 15, 13, 15, 16, 8, 4, 2, 1, 6, 3, 17, 15, 12, 6, 3, 4, 2, 1, 3, 6, 3, 3, 5, 3, 2, 1, 5, 6, 3, 48, 24, 12, 6, 3, 12, 6, 3, 10, 5, 4, 2, 1, 3, 3, 31, 21, 17, 15, 11, 13, 24, 12, 6, 3
Offset: 1

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Author

Jason Earls, Aug 16 2003

Keywords

Comments

The first few values of n such that 509203*2^n - 1 is a semiprime, where k = 509203 (the conjectured smallest Riesel number), are: 3,4,16,34,61,82,124,142,163,171,... Conjecture: there are infinitely many semiprimes of this form.

Examples

			a(33)=16 because k*2^33 - 1 is not a semiprime for k=1,2,...15, but 16*2^33 - 1 = 223 * 616318177 is.
		

Crossrefs

A206430 Least k such that k*2^m - 1 has a covering set with precisely n primes.

Original entry on oeis.org

509203, 777149, 7106977, 60014203
Offset: 6

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Author

Arkadiusz Wesolowski, Apr 19 2012

Keywords

Comments

A set of primes is a covering set for k*2^m - 1 if for every positive integer m there is some prime in the set which divides k*2^m - 1. Only minimal covering sets are considered here (those which would not remain covering sets with the removal of any element).

Examples

			509203 has the covering set {3, 5, 7, 13, 17, 241}.
777149 has the covering set {3, 5, 7, 13, 19, 37, 73}.
7106977 has the covering set {3, 5, 13, 17, 19, 109, 241, 433}.
60014203 has the covering set {3, 5, 7, 11, 13, 31, 41, 61, 151}.
		

Crossrefs

A244545 Integers n such that for every integer k>0, n*6^k+1 has a divisor in the set { 7, 13, 31, 37, 43 }.

Original entry on oeis.org

243417, 1161910, 1293662, 1434861, 1446213, 1460502, 1473746, 1689722, 2284675, 2483249, 2485141, 2693347, 2695449, 2708061, 2783733, 3207751, 3237765, 3273761, 3684535, 4120955, 4154366, 4189067, 4274801, 4354265
Offset: 1

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Author

Pierre CAMI, Jun 29 2014

Keywords

Comments

For n > 24, a(n) = a(n-24) + 4488211, the first 24 values are in the data.
When the number a(n) has 4 or 9 as the last digit, the number a(n)*6^k-1 is always divisible by 5 and always has a divisor in the set { 7, 13, 31, 37, 97 } for every k.

Crossrefs

Formula

For n > 24 a(n) = a(n-24) + 4488211.

A244351 Integers n such that for every integer k>0, n*6^k-1 has a divisor in the set { 7, 13, 31, 37, 97 }.

Original entry on oeis.org

84687, 429127, 508122, 1273238, 1570311, 1656045, 2574762, 2847748, 3048732, 3345805, 3849481, 5076399, 5324003, 5338292, 5908351, 6961919, 7639428, 8167823, 8508662, 8994775, 9078721, 9421866, 9936270, 9950261
Offset: 1

Views

Author

Pierre CAMI, Jun 26 2014

Keywords

Comments

For n > 24 a(n) = a(n-24) + 10124569, the first 24 values are in the data.
When the number a(n) has 1 or 6 as the last digit the number a(n)*6^k-1 is always divisible by 5 and have always a divisor in the set { 7, 13, 31, 37, 97 } for every k.

Crossrefs

Formula

For n>24 a(n) = a(n-24) + 10124569.

A244549 Integers m such that for every integer k>0, m*6^k+1 has a divisor in the set { 7, 13, 31, 37, 97 }.

Original entry on oeis.org

174308, 188299, 702703, 1045848, 1129794, 1615907, 1956746, 2485141, 3162650, 4216218, 4786277, 4800566, 5048170, 6275088, 6778764, 7075837, 7276821, 7549807, 8468524, 8554258, 8851331, 9616447, 9695442, 10039882
Offset: 1

Views

Author

Pierre CAMI, Jun 29 2014

Keywords

Comments

For n > 24 a(n) = a(n-24) + 10124569, the first 24 values are in the data.
When the number a(n) has 4 or 9 as the last digit the number a(n)*6^k-1 is always divisible by 5 and have always a divisor in the set { 7, 13, 31, 37, 97 } for every k.

Crossrefs

Formula

For n > 24 a(n) = a(n-24) + 10124569.
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