cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A365823 Decimal expansion of 2*(2 + sqrt(2)).

Original entry on oeis.org

6, 8, 2, 8, 4, 2, 7, 1, 2, 4, 7, 4, 6, 1, 9, 0, 0, 9, 7, 6, 0, 3, 3, 7, 7, 4, 4, 8, 4, 1, 9, 3, 9, 6, 1, 5, 7, 1, 3, 9, 3, 4, 3, 7, 5, 0, 7, 5, 3, 8, 9, 6, 1, 4, 6, 3, 5, 3, 3, 5, 9, 4, 7, 5, 9, 8, 1, 4, 6, 4, 9, 5, 6, 9, 2, 4, 2, 1, 4, 0, 7, 7
Offset: 1

Views

Author

Wolfdieter Lang, Nov 13 2023

Keywords

Comments

The greater one of the solutions to x^2 - 8 * x + 8 = 0. The other solution is A157259 - 3 = 1.17157... . - Michal Paulovic, Nov 14 2023

Examples

			6.8284271247461900976033774484193961571393437507538961...
		

Crossrefs

Essentially the same as A157258, A090488, A086178 and A010466.

Programs

  • Maple
    evalf(4+sqrt(8), 130);  # Alois P. Heinz, Nov 13 2023
  • Mathematica
    First[RealDigits[2*(2 + Sqrt[2]), 10, 99]] (* Stefano Spezia, Nov 11 2023 *)
  • PARI
    \\ Works in v2.13 and higher; n = 100 decimal places
    my(n=100); digits(floor(10^n*(4+quadgen(32)))) \\ Michal Paulovic, Nov 14 2023

Formula

Equals 2*sqrt(2)*(1 + sqrt(2)) = 2*(2 + sqrt(2)). This is an integer in the quadratic number field Q(sqrt(2)).
Equals lim_{n->oo} A057084(n + 1)/A057084(n).
Equals continued fraction with periodic term [[6], [1, 4]]. - Peter Luschny, Nov 13 2023
Equals -3+A157258 = 1+A156035 = 2+A090488 = 3+A086178 = 4+A010466 = 6+A163960. - Alois P. Heinz, Nov 15 2023

A381756 Decimal expansion of the smallest angular distance between two vertices of the equilateral square antiprism measured along the circumscribing sphere.

Original entry on oeis.org

1, 3, 0, 6, 5, 2, 7, 1, 6, 1, 7, 1, 7, 4, 3, 7, 2, 7, 5, 5, 3, 4, 1, 6, 4, 6, 9, 0, 5, 9, 8, 6, 9, 4, 7, 4, 4, 1, 6, 2, 8, 6, 1, 3, 9, 0, 1, 9, 9, 9, 2, 7, 8, 9, 0, 3, 1, 9, 6, 8, 8, 6, 5, 8, 5, 8, 9, 7, 4, 5, 3, 6, 9, 4, 0, 3, 0, 6, 5, 2, 9, 1, 1, 4, 4, 9, 1, 2, 9, 1, 0
Offset: 1

Views

Author

R. J. Mathar, Mar 06 2025

Keywords

Comments

The equilateral square antiprism of side number n=4, lateral edge length a, and the two bases separated vertically by h has h = a*sqrt( 1-sec^2(Pi/(2n)) ) = a/2^(1/4). The 4 vertices of the top base have Cartesian coordinates (+-a/sqrt(2),0,h/2), (0,+-a/sqrt(2),h/2); the 4 vertices at the bottom base have (+-a/2,+-a/2,-h/2). The common distance of these 8 vertices from the origin is r = a*sqrt(8+2^(3/2))/4, the radius of the circumscribing sphere. The largest dot product between pairs of the 8 vertices is sqrt(2)*a^2/8 , which is equivalent to the smallest distance measured along the surface of the sphere of radius r. Dividing this dot product through r^2 gives 2^(3/2)/(8+2^(3/2)), the cosine of the angle between closest vertices. This here is the angle measured in radians.

Examples

			1.3065271617174372755341...
		

Crossrefs

Cf. A086178.

Programs

  • Maple
    evalf( arccos(1/(2^(3/2)+1)) ) ;
  • Mathematica
    RealDigits[ArcCos[1/(2^(3/2)+1)],10,91][[1]] (* Stefano Spezia, Jul 29 2025 *)

Formula

Equals arccos(1/(2^(3/2)+1)) = arcsec(A086178).
Previous Showing 21-22 of 22 results.