1, 2, 6, 3, 14, 50, 5, 34, 179, 892, 7, 72, 548, 3765, 21225, 11, 157, 1651, 14961, 108798, 700212, 15, 311, 4485, 53196, 491235, 3903733
Offset: 1
Triangle begins:
n\k| 1 2 3 4 5 6 7
---+------------------------------------
1 | 1
2 | 2 6
3 | 3 14 50
4 | 5 34 179 892
5 | 7 72 548 3765 21225
6 | 11 157 1651 14961 108798 700212
7 | 15 311 4485 53196 491235 3903733 ?
For n = k = 2, we have the following six partitions of the 2 X 2 square:
{ [ (2,2) ], [ (2,1), (2,1) ], [ (2,1), (1,1), (1,1) ], [ (1,2), (1,2) ],
[ (1,2), (1,1), (1,1) ], [ (1,1), (1,1), (1,1), (1,1) ] }.
They can be represented graphically as follows:
AA AB AB AA AA AB
AA AB AC BB BC CD
where in each figure a given letter corresponds to a given rectangular part.
For n = 3, k = 2, we have the fourteen partitions { [(3,2)], [(3,1), (3,1)],
[(3,1), (2,1), (1,1)], [(3,1), (1,1), (1,1), (1,1)], [(2,2), (1,2)],
[(2,2), (1,1), (1,1)], [(2,1), (2,1), (1,2)], [(2,1), (2,1), (1,1), (1,1)],
[(2,1), (1,2), (1,1), (1,1)], [(2,1), (1,1), (1,1), (1,1), (1,1)],
[(1,2), (1,2), (1,2)], [(1,2), (1,1), (1,1), (1,1), (1,1)],
[(1,2), (1,2), (1,1), (1,1)], [(1,1), (1,1), (1,1), (1,1), (1,1), (1,1)] },
AA AB AB AB AA AA AB AB AC AC AA AA AA AB
i.e.: AA AB AB AC AA AA AB AB AD AD BB BB BC CD .
AA AB AC AD BB BC CC CD BB BE CC CD DE EF
For n = k = 3, we have 50 distinct partitions. Only one of them, namely
AAB
[(2,1), (2,1), (1,2), (1,2), (1,1)] corresponding to: DEB
DCC
cannot be obtained by repeatedly slicing the full square, and subsequently the resulting smaller rectangles, in two rectangular parts at each step.
Note that the arrangement: ABC
ABD which also cannot be obtained in that way,
ABD AED corresponds to the equivalent partition:
ABD , i.e., the multiset [(3,1), (2,1), (2,1), (1,1), (1,1)],
AEC which can be obtained by subsequent "slicing in two rectangles".
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