cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A293690 Numbers z such that x^2 + y^6 = z^2 for positive integers x and y.

Original entry on oeis.org

10, 17, 45, 80, 123, 136, 225, 234, 260, 270, 291, 325, 360, 365, 459, 510, 514, 640, 666, 745, 984, 1025, 1088, 1215, 1225, 1250, 1305, 1450, 1466, 1565, 1740, 1753, 1800, 1872, 1950, 1970, 2022, 2080, 2125, 2160, 2328, 2600, 2628, 2880, 2920, 3172, 3185
Offset: 1

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Author

XU Pingya, Oct 14 2017

Keywords

Comments

Let i, j and k be nonnegative integers, m > n be positive integers. As ((m^2 - n^2)^(3*i+1) * (2*m*n)^(3*j+2) * (m^2 + n^2)^(3*k))^2 + ((m^2 - n^2)^i * (2*m*n)^(j+1) * (m^2 + n^2)^k)^6 = ((m^2 - n^2)^(3*i) * (2*m*n)^(3*j+2) * (m^2 + n^2)^(3*k+1))^2, so that the number of the form (m^2 - n^2)^(3*i) * (2*m*n)^(3*j+2) * (m^2 + n^2)^(3*k+1) is a term.
When (x, y, z) is a solution of x^2 + y^4 = z^2 (i.e., z = A271576(n)), (x^(3*i+1) * y^(3*j+1) * z^(3*k), x^i * y^(j+1) * z^k, x^(3*i) * y^(3*j+1) * z^(3*k+1)) is a solution of x^2 + y^6 = z^2.
When (x, y, z) is a solution of x^2 + y^6 = z^2, (x^(3*i+1) * y^(3*j) * z^(3*k), x^i * y^(j+1) * z^k, x^(3*i) * y^(3*j) * z^(3*k+1)) is also a solution of x^2 + y^6 = z^2.

Examples

			6^2 + 2^6 = 10^2, 10 is a term.
15^2 + 2^6 = 17^2, 17 is a term.
		

Crossrefs

Programs

  • Mathematica
    z[n_] := Count[n^2 - Range[(n^2 - 1)^(1/6)]^6, _?(IntegerQ[Sqrt[#]] &)] > 0; Select[Range[3200], z]

A349663 Positive numbers x for which x^2 can be expressed as z^2 - y^4 with y != 0.

Original entry on oeis.org

3, 12, 15, 17, 27, 30, 40, 42, 48, 60, 63, 68, 75, 77, 90, 95, 99, 105, 108, 112, 120, 130, 135, 140, 147, 153, 156, 160, 165, 168, 192, 195, 220, 240, 243, 252, 270, 272, 273, 300, 301, 308, 312, 315, 323, 350, 360, 363, 375, 378, 380, 396, 399, 420, 425, 432, 448, 462, 480, 495, 507
Offset: 1

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Author

Keywords

Comments

This sequence is closely related to A271576.
Conditions to be satisfied for a solution:
- z cannot be a square.
- z must have at least one prime factor of the form p == 1 (mod 4), a Pythagorean prime (A002144).
- If z has prime factors of the form p == 3 (mod 4), which are in A002145, then they must appear in the prime divisor sets of x and y too.
- If z is even, x and y must be even too.
- The lower limit of the ratio x/y is sqrt(2).
Multiple solutions are possible; e.g., term 420 has 5 solutions.

Examples

			The 5 solutions corresponding to a(54) = 420 are 420^2 = 176400 = 444^2 - 12^4 = 580^2 - 20^4 = 609^2 - 21^4 = 1295^2 - 35^4 = 3164^2 - 56^4.
		

Crossrefs

A349664 a(n) is the number of solutions for n^4 = z^2 - x^2 with {z,x} >= 1.

Original entry on oeis.org

0, 1, 2, 3, 2, 7, 2, 5, 4, 7, 2, 17, 2, 7, 12, 7, 2, 13, 2, 17, 12, 7, 2, 27, 4, 7, 6, 17, 2, 37, 2, 9, 12, 7, 12, 31, 2, 7, 12, 27, 2, 37, 2, 17, 22, 7, 2, 37, 4, 13, 12, 17, 2, 19, 12, 27, 12, 7, 2, 87, 2, 7, 22, 11, 12, 37, 2, 17, 12, 37, 2, 49, 2, 7, 22
Offset: 1

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Author

Karl-Heinz Hofmann, Dec 13 2021

Keywords

Comments

If n is an odd prime^i, the number of solutions is 2*i.
If n = 2^i, the number of solutions is 2*i-1.
These two facts are not generally valid in reverse for terms > 6.
If a(n) = 2, n is an odd prime. This is generally valid in reverse.
For more information about these facts see the link.
The calculation of the terms is done with an algorithm of Jon E. Schoenfield, which is described in A349324.
Conditions to be satisfied for a valid, countable solution:
- z cannot be a square.
- z must have at least one prime factor of the form p == 1 (mod 4), a Pythagorean prime (A002144).
- If z has prime factors of the form p == 3 (mod 4), which are in A002145, then they must appear in the prime divisor sets of x and n too.
- If z is even, x and n must be even too.
- The lower limit of the ratio x/n is sqrt(2).
- high limits of z and x:
| n is odd | n is even
---------+------------------+------------------
z limit | (n^4 + 1)/2 | (n^4 + 4)/4
x limit | (n^4 + 1)/2 - 1 | (n^4 + 4)/4 - 2

Examples

			a(6) = 7 (solutions): 6^4 = 1296 = 325^2 - 323^2 = 164^2 - 160^2 = 111^2 - 105^2 = 85^2 - 77^2 = 60^2 - 48^2 = 45^2 - 27^2 = 39^2 - 15^2.
		

Crossrefs

Programs

  • Mathematica
    a[n_] := Length[Solve[n^4 == z^2 - x^2 && x >= 1 && z >= 1, {x, z}, Integers]]; Array[a, 75] (* Amiram Eldar, Dec 14 2021 *)
  • PARI
    a(n) = numdiv(if(n%2, n^4, n^4/4))\2; \\ Jinyuan Wang, Dec 19 2021

A273908 Integers z such that x^2 + y^4 = z^6 where x, y, z > 0, is soluble.

Original entry on oeis.org

5, 15, 20, 34, 39, 41, 45, 55, 60, 65, 80, 85, 111, 125, 135, 136, 145, 150, 156, 164, 175, 180, 194, 219, 220, 240, 245, 255, 260, 265, 299, 306, 313, 320, 325, 340, 351, 353, 369, 371, 375, 405, 410, 444, 445, 455, 495, 500, 505, 514, 525, 540, 544
Offset: 1

Views

Author

Altug Alkan, Jun 03 2016

Keywords

Comments

A271576 is a subsequence.
Terms that are not in A271576 are 55, 220, 299, ...
Sequence is infinite since if k is a term then also t^2*k is a term, for every t>0. - Giovanni Resta, Jun 04 2016

Examples

			5 is a term because 75^2 + 10^4 = 5^6.
		

Crossrefs

Programs

  • Mathematica
    q[n_] := {} != Select[Range[n^(1/4)]^4, n > # && IntegerQ@ Sqrt[n - #] &]; Select[ Range[100], q[#^6] &] (* Giovanni Resta, Jun 04 2016 *)

A349665 Record terms of A349664.

Original entry on oeis.org

0, 1, 2, 3, 7, 17, 27, 37, 87, 137, 157, 187, 247, 437, 687, 787, 937, 1237, 2187, 3437, 3937, 4687, 6187, 8437, 10937, 17187, 19687, 23437, 30937, 42187, 54687, 55687, 85937, 98437, 117187, 154687, 210937, 223437, 273437, 278437, 304687, 429687, 492187, 585937
Offset: 1

Views

Author

Karl-Heinz Hofmann, Dec 18 2021

Keywords

Comments

Terms are the record numbers of solutions for the equation: y^4 = z^2 - x^2.

Examples

			Number of | y | Factorization
solutions |   |      of y
----------+---+--------------
        0 | 1 |  -
        1 | 2 | [2]
        2 | 3 | [3]
        3 | 4 | [2, 2]
        7 | 6 | [2, 3]
        :   :      :
For more terms with y and factorization of y see link.
		

Crossrefs

Programs

  • PARI
    lista(nn) = my(f, r); print1("0, 1, 2"); forstep(n=4, nn, 2, f=factor(n)[, 2]; if(rJinyuan Wang, Dec 19 2021

Extensions

More terms from Jinyuan Wang, Dec 19 2021
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