A360703 Starting from 1, successively take the smallest "Choix de Bruxelles" with factor 3 which is not already in the sequence.
1, 3, 9, 27, 67, 187, 129, 43, 41, 121, 17, 37, 97, 277, 677, 1877, 1297, 199, 133, 111, 113, 119, 139, 339, 313, 311, 331, 131, 191, 193, 393, 333, 399, 999, 933, 911, 913, 919, 319, 357, 157, 57, 19, 13, 11, 31, 33, 39, 99, 93, 91, 271, 273, 279, 679, 673, 671, 1871, 1291, 197, 137, 117, 151, 51, 53, 59, 159, 153
Offset: 0
Examples
Below, square brackets [] represent multiplication by 3(e.g., [4] = 12); curly brackets {} represent division by 3 (e.g., {6} = 2); digits outside the brackets are not affected by the multiplication or division (e.g., 1[3] = 19 and 1{18} = 16). We begin with 1 and, at each step, we go to the smallest number possible that hasn't yet appeared in the sequence: 1 --> [1] = 3 3 --> [3] = 9 9 --> [9]= 27 27--> [2]7 = 67 67--> [6]7= 187 187 --> 1{87}=129 129 --> {129} = 43 ... and so on.
Links
- Alon Vinkler, Table of n, a(n) for n = 0..10000
- Eric Angelini, Lars Blomberg, Charlie Neder, Remy Sigrist, and N. J. A. Sloane, "Choix de Bruxelles": A New Operation on Positive Integers, arXiv:1902.01444 [math.NT], Feb 2019; Fib. Quart. 57:3 (2019), 195-200.
- Eric Angelini, Lars Blomberg, Charlie Neder, Remy Sigrist, and N. J. A. Sloane,, "Choix de Bruxelles": A New Operation on Positive Integers, Local copy.
- Alon Vinkler, C# Program
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