A118164 Number of representations of A005243(n) as sum of consecutive earlier terms in A005243.
0, 0, 1, 1, 1, 1, 1, 2, 2, 1, 1, 1, 1, 1, 1, 2, 2, 2, 1, 1, 1, 1, 4, 1, 2, 1, 3, 1, 2, 1, 2, 2, 3, 1, 2, 3, 1, 2, 3, 2, 1, 1, 2, 1, 1, 1, 2, 3, 1, 1, 1, 1, 1, 3, 2, 1, 1, 1, 3, 2, 2, 1, 2, 1, 1, 1, 3, 1, 1, 4, 1, 2, 1, 3, 1, 2, 1, 2, 1, 1, 2, 2, 1, 3, 1, 3, 4, 2, 1, 3, 1, 2, 2, 2, 3, 1, 1, 1, 2, 2, 1, 3, 1, 1, 4
Offset: 1
Keywords
Examples
A005243(33) = 54 = 29+25 = Sum(A005243[17:18]) = 19+18+17 = Sum(A005243[11:13]) = 14+11+10+8+6+5 = Sum(A005243[4:9]), therefore a(33) = 3.
Links
- Eric Weisstein's World of Mathematics, Hofstadter Sequences
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