A006238 Complexity of (or spanning trees in) a 3 X n grid.
1, 15, 192, 2415, 30305, 380160, 4768673, 59817135, 750331584, 9411975375, 118061508289, 1480934568960, 18576479568193, 233018797965135, 2922930580320960, 36664523428884015, 459910778352898337, 5769007865476035840, 72365017995700730081, 907729015392142395375
Offset: 1
Keywords
References
- F. Faase, On the number of specific spanning subgraphs of the graphs G X P_n, Ars Combin. 49 (1998), 129-154.
- N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
Links
- T. D. Noe, Table of n, a(n) for n = 1..200
- Peter Bala, Linear divisibility sequences and Chebyshev polynomials
- F. Faase, On the number of specific spanning subgraphs of the graphs G X P_n, Preliminary version of paper that appeared in Ars Combin. 49 (1998), 129-154.
- F. Faase, Counting Hamiltonian cycles in product graphs
- F. Faase, Results from the counting program
- Germain Kreweras, Complexité et circuits Eulériens dans les sommes tensorielles de graphes, J. Combin. Theory, B 24 (1978), 202-212.
- P. Raff, Spanning Trees in Grid Graphs, arXiv:0809.2551 [math.CO], 2008.
- P. Raff, Analysis of the Number of Spanning Trees of P_3 x P_n. Contains sequence, recurrence, generating function, and more.
- Hugh Williams, R. K. Guy, Some fourth-order linear divisibility sequences, Intl. J. Number Theory vol. 7 (5) (2011) 1255-1277
- Index to divisibility sequences
- Index entries for sequences related to trees
- Index entries for linear recurrences with constant coefficients, signature (15,-32,15,-1).
Programs
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Maple
a:= n-> (<<0|1|0|0>, <0|0|1|0>, <0|0|0|1>, <-1|15|-32|15>>^n. <<1, 0, 1, 15>>)[2, 1]: seq(a(n), n=1..30); # Alois P. Heinz, Apr 14 2011
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Mathematica
LinearRecurrence[{15,-32,15,-1},{1,15,192,2415},30] (* Harvey P. Dale, May 14 2013 *)
Formula
a(n) = 15a(n-1) - 32a(n-2) + 15a(n-3) - a(n-4), n>4.
G.f.: -x(x^2-1)/(x^4-15x^3+32x^2-15x+1). - Paul Raff, Mar 06 2009
From Peter Bala, Mar 25 2014: (Start)
a(n) = ( T(n,alpha) - T(n,beta) )/(alpha - beta), where alpha = (15 + sqrt(105))/4 and beta = (15 - sqrt(105))/4 and T(n,x) denotes the Chebyshev polynomial of the first kind.
a(n) = the bottom left entry of the 2X2 matrix T(n, M), where M is the 2X2 matrix [0, -15/2; 1, 15/2].
See the remarks in A100047 for the general connection between Chebyshev polynomials of the first kind and 4th-order linear divisibility sequences. (End)
a(n) = (A003775(n+1)+A003775(n-2))/24-(A003775(n)+A003775(n-1))/3, n>1. - Sergey Perepechko, Apr 26 2016
Comments