cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-3 of 3 results.

A063987 Irregular triangle in which n-th row gives quadratic residues modulo the n-th prime.

Original entry on oeis.org

1, 1, 1, 4, 1, 2, 4, 1, 3, 4, 5, 9, 1, 3, 4, 9, 10, 12, 1, 2, 4, 8, 9, 13, 15, 16, 1, 4, 5, 6, 7, 9, 11, 16, 17, 1, 2, 3, 4, 6, 8, 9, 12, 13, 16, 18, 1, 4, 5, 6, 7, 9, 13, 16, 20, 22, 23, 24, 25, 28, 1, 2, 4, 5, 7, 8, 9, 10, 14, 16, 18, 19, 20, 25, 28, 1, 3, 4, 7, 9, 10, 11, 12, 16, 21, 25
Offset: 1

Views

Author

Suggested by Gary W. Adamson, Sep 18 2001

Keywords

Comments

For n >= 2, row lengths are (prime(n) - 1)/2. For example, since 17 is the 7th prime number, the length of row 7 is (17 - 1)/2 = 8. - Geoffrey Critzer, Apr 04 2015

Examples

			Modulo the 5th prime, 11, the (11 - 1)/2 = 5 quadratic residues are 1,3,4,5,9 and the 5 non-residues are 2, 6, 7, 8, 10.
The irregular triangle T(n, k) begins (p is prime(n)):
   n    p  \k 1 2 3 4  5  6  7  8  9 10 11 12 13 14
   1,   2:    1
   2,   3:    1
   3,   5:    1 4
   4,   7:    1 2 4
   5,  11:    1 3 4 5  9
   6:  13:    1 3 4 9 10 12
   7,  17:    1 2 4 8  9 13 15 16
   8,  19:    1 4 5 6  7  9 11 16 17
   9,  23:    1 2 3 4  6  8  9 12 13 16 18
  10,  29:    1 4 5 6  7  9 13 16 20 22 23 24 25 28
  ...  reformatted by _Wolfdieter Lang_, Mar 06 2016
		

References

  • Albert H. Beiler, Recreations in the theory of numbers, New York, Dover, (2nd ed.) 1966. See Table 82 at p. 202.

Crossrefs

Cf. A063988, A010379 (6th row), A010381 (7th row), A010385 (8th row), A010391 (9th row), A010392 (10th row), A278580 (row 23), A230077.
Cf. A076409 (row sums).
Cf. A046071 (for all n), A048152 (for all n, with 0's).

Programs

  • Maple
    with(numtheory): for n from 1 to 20 do for j from 1 to ithprime(n)-1 do if legendre(j, ithprime(n)) = 1 then printf(`%d,`,j) fi; od: od:
    # Alternative:
    QR := (a, n) -> NumberTheory:-QuadraticResidue(a, n):
    for n from 1 to 10 do p := ithprime(n):
    print(select(a -> 1 = QR(a, p), [seq(1..p-1)])) od:  # Peter Luschny, Jun 02 2024
  • Mathematica
    row[n_] := (p = Prime[n]; Select[ Range[p - 1], JacobiSymbol[#, p] == 1 &]); Flatten[ Table[ row[n], {n, 1, 12}]] (* Jean-François Alcover, Dec 21 2011 *)
  • PARI
    residue(n,m)=local(r);r=0;for(i=0,floor(m/2),if(i^2%m==n,r=1));r
    isA063987(n,m)=residue(n,prime(m)) /* Michael B. Porter, May 07 2010 */
    
  • PARI
    row(n) = my(p=prime(n)); select(x->issquare(Mod(x,p)), [1..p-1]); \\ Michel Marcus, Nov 07 2020
    
  • Python
    from sympy import jacobi_symbol as J, prime
    def a(n):
        p = prime(n)
        return [1] if n==1 else [i for i in range(1, p) if J(i, p)==1]
    for n in range(1, 11): print(a(n)) # Indranil Ghosh, May 27 2017
    
  • SageMath
    for p in prime_range(30): print(quadratic_residues(p)[1:])
    # Peter Luschny, Jun 02 2024

Extensions

Edited by Wolfdieter Lang, Mar 06 2016

A010419 Squares mod 58.

Original entry on oeis.org

0, 1, 4, 5, 6, 7, 9, 13, 16, 20, 22, 23, 24, 25, 28, 29, 30, 33, 34, 35, 36, 38, 42, 45, 49, 51, 52, 53, 54, 57
Offset: 1

Views

Author

Keywords

Crossrefs

Row 58 of A096008.

Programs

A028742 Nonsquares mod 29.

Original entry on oeis.org

2, 3, 8, 10, 11, 12, 14, 15, 17, 18, 19, 21, 26, 27
Offset: 1

Views

Author

Keywords

Examples

			Since 12 is not a perfect square and there are no solutions to x^2 = 12 mod 29, 12 is in the sequence.
Although 13 is not a perfect square either, there are solutions to x^2 = 13 mod 29, such as x = 10, x = 19, so 13 is not in the sequence.
		

Crossrefs

Cf. A010391.

Programs

  • Mathematica
    Complement[Range[0, 28], PowerMod[Range[29], 2, 29]] (* Alonso del Arte, Nov 29 2019 *)
  • Scala
    val squaresMod29 = (1 to 29).map(n => n * n).map(_ % 29)
    (0 to 28).diff(squaresMod29) // Alonso del Arte, Nov 29 2019
Showing 1-3 of 3 results.