cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A070253 Numbers k such that k^2 - 1 is a palindrome.

Original entry on oeis.org

1, 2, 3, 10, 18, 24, 65, 76, 100, 192, 205, 1000, 1748, 1908, 2366, 2967, 5732, 10000, 18992, 20565, 100000, 174602, 174748, 179318, 243064, 293787, 552102, 1000000, 1868288, 2967033, 9200157, 10000000, 22765896, 31552660, 93809717, 100000000
Offset: 1

Views

Author

Amarnath Murthy, May 06 2002

Keywords

Comments

Every palindrome of the form h^2-1 is of the form m*(m+2) (easy to prove by replacing h by m+1). In fact this is equal to A028503 + 1. - Patrick De Geest, May 09 2002

Crossrefs

Programs

  • Mathematica
    Do[ If[ a = IntegerDigits[n^2 - 1]; a == Reverse[a], Print[n]], {n, 1, 10^8/4}]
    Select[Range[10^8],PalindromeQ[#^2-1]&] (* Harvey P. Dale, Oct 13 2024 *)
  • PARI
    intreverse(n)=local(d,rev); rev=0; while(n>0,d=divrem(n,10); n=d[1]; rev=10*rev+d[2]); rev
    for(n=1,100000000,q=n*n-1; if(q==intreverse(q),print1(n,",")))

Formula

a(n) = A028503(n) + 1. - Giovanni Resta, Aug 29 2018

Extensions

Edited by Jason Earls, Klaus Brockhaus and Robert G. Wilson v, May 08 2002

A028504 Palindromes of form k*(k+2); or palindromes 1 less than a square.

Original entry on oeis.org

0, 3, 8, 99, 323, 575, 4224, 5775, 9999, 36863, 42024, 999999, 3055503, 3640463, 5597955, 8803088, 32855823, 99999999, 360696063, 422919224, 9999999999, 30485858403, 30536863503, 32154945123, 59080108095, 86310801368, 304816618403, 999999999999, 3490500050943
Offset: 1

Views

Author

Keywords

Comments

10^(2*m) - 1 for m > 0 are terms. - Chai Wah Wu, May 25 2017

Examples

			4224 belongs to this sequence as 4225 = 65^2.
		

Crossrefs

Programs

  • ARIBAS
    stop := 400000; m := 1; while m < stop do s := m*m - 1; if s = int_reverse(s) then write(s," "); end; inc(m); end;
  • Mathematica
    palQ[n_] := Block[{d = IntegerDigits[n]}, d == Reverse[d]]; Select[Range[10000]^2 - 1, palQ] (* Giovanni Resta, Aug 29 2018 *)
    Select[Table[n(n+2),{n,0,19*10^5}],PalindromeQ] (* Harvey P. Dale, Oct 13 2024 *)

Formula

a(n) = A028503(n) * (A028503(n) + 2) = A070253(n)^2 - 1 = A070254(n) - 1. - Giovanni Resta, Aug 29 2018

Extensions

More terms from Giovanni Resta, Aug 28 2018
Showing 1-2 of 2 results.