cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A028890 Product of digits of n is a nonzero Fibonacci number.

Original entry on oeis.org

1, 2, 3, 5, 8, 11, 12, 13, 15, 18, 21, 24, 31, 37, 42, 51, 73, 81, 111, 112, 113, 115, 118, 121, 124, 131, 137, 142, 151, 173, 181, 211, 214, 222, 241, 289, 298, 311, 317, 368, 371, 386, 412, 421, 449, 466, 494, 511, 638, 646, 664, 683, 713, 731, 811, 829, 836
Offset: 1

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Comments

Numbers n whose product of digits is 1, 2, 3, 5, 8, 21, or 144 (these being the only 7-smooth Fibonacci numbers). - Robert Israel, Jan 26 2020

Crossrefs

Programs

  • Maple
    select(t -> member(convert(convert(t,base,10),`*`),[1, 2, 3, 5, 8, 21, 144]),[$1..999]); # Robert Israel, Jan 26 2020

Extensions

More terms from Erich Friedman.
Name clarified and offset changed by Robert Israel, Jan 26 2020

A028841 Iterated sum of digits of n is a Fibonacci number.

Original entry on oeis.org

1, 2, 3, 5, 8, 10, 11, 12, 14, 17, 19, 20, 21, 23, 26, 28, 29, 30, 32, 35, 37, 38, 39, 41, 44, 46, 47, 48, 50, 53, 55, 56, 57, 59, 62, 64, 65, 66, 68, 71, 73, 74, 75, 77, 80, 82, 83, 84, 86, 89, 91, 92, 93, 95, 98, 100, 101, 102, 104, 107, 109, 110, 111, 113, 116, 118, 119
Offset: 1

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Comments

Intermediate iterations don't count. For example, with 85, we have 8 + 5 = 13, which is a Fibonacci number, but 1 + 3 = 4, which is not a Fibonacci numbers, so 85 is not in the sequence. - Alonso del Arte, Jan 20 2020

Examples

			98 -> 9 + 8 = 17 -> 1 + 7 = 8 is a Fibonacci number.
		

Crossrefs

Programs

  • Mathematica
    With[{fibo = {1, 2, 3, 5, 8}}, Select[Range[120], MemberQ[fibo, NestWhile[Total[IntegerDigits[#]] &, #, # > 9 &]]&]] (* Harvey P. Dale, Apr 11 2013 *)
  • Scala
    def fiboDRQ(n: Int): Boolean = List(1, 2, 3, 5, 8).contains(n % 9)
    (1 to 100).filter(fiboDRQ) // Alonso del Arte, Jan 28 2020

Formula

Conjectures from Colin Barker, Feb 18 2020: (Start)
G.f.: x*(1 + x + x^2 + 2*x^3 + 3*x^4 + x^5) / ((1 - x)^2*(1 + x + x^2 + x^3 + x^4)).
a(n) = a(n-1) + a(n-5) - a(n-6) for n>6.
(End)

Extensions

More terms from Patrick De Geest, Jun 15 1999
Offset corrected to 1 by Alonso del Arte, Jan 28 2020 at Michel Marcus's suggestion
Showing 1-2 of 2 results.