cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A048906 Octagonal heptagonal numbers.

Original entry on oeis.org

1, 297045, 69010153345, 16032576845184901, 3724720317758036481633, 865334473646149974640821781, 201036235582696134090746961388705, 46705140322177796790584365589105966085
Offset: 1

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Keywords

Comments

As n increases, this sequence is approximately geometric with common ratio r = lim(n->Infinity,a(n)/a(n-1)) = (sqrt(5)+sqrt(6))^8 = 116161+21208*sqrt(30). - Ant King, Dec 30 2011

Crossrefs

Programs

  • Magma
    I:=[1, 297045, 69010153345]; [n le 3 select I[n] else 232323*Self(n-1)-232323*Self(n-2)+Self(n-3): n in [1..15]]; // Vincenzo Librandi, Dec 28 2011
  • Mathematica
    CoefficientList[Series[(-133*x^2-64722*x-1)/(x^3-232323*x^2+ 232323*x- 1),{x,0,20}],x] (* or *) LinearRecurrence[{232323,-232323,1},{1,297045,69010153345},21] (* Harvey P. Dale, Dec 09 2011 *)

Formula

From Harvey P. Dale, Dec 09 2011: (Start)
G.f.: x*(-133*x^2-64722*x-1)/(x^3-232323*x^2+232323*x-1).
a(1)=1, a(2)=297045, a(3)=69010153345, a(n) = 232323*a(n-1)-232323*a(n-2)+a(n-3). (End)
From Ant King, Dec 30 2011: (Start)
a(n) = 232322*a(n-1)-a(n-2)+64856.
a(n) = 1/480*((17+2*sqrt(30))*(sqrt(5)+sqrt(6))^(8n-6)+(17-2*sqrt(30))*(sqrt(5)-sqrt(6))^(8n-6)-134).
a(n) = floor(1/480*(17+2*sqrt(30))*(sqrt(5)+sqrt(6))^(8n-6)). (End)

A048905 Indices of octagonal numbers which are also heptagonal.

Original entry on oeis.org

1, 315, 151669, 73103983, 35235967977, 16983663460771, 8186090552123485, 3945678662460058839, 1901808929215196236753, 916667958203062126055947, 441832054044946729562729541, 212962133381706120587109582655, 102647306457928305176257256110009
Offset: 1

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Author

Keywords

Comments

As n increases, this sequence is approximately geometric with common ratio r = lim_{n->oo} a(n)/a(n-1) = (sqrt(5)+sqrt(6))^4 = 241+44*sqrt(30). - Ant King, Dec 30 2011

Crossrefs

Programs

  • Mathematica
    LinearRecurrence[{483,-483,1},{1,315,151669},20] (* Vincenzo Librandi, Dec 28 2011 *)

Formula

G.f.: -x*(1-168*x+7*x^2) / ( (x-1)*(x^2-482*x+1) ). - R. J. Mathar, Dec 21 2011
From Ant King, Dec 30 2011: (Start)
a(n) = 482*a(n-1)-a(n-2)-160.
a(n) = 1/120*((2*sqrt(5)+5*sqrt(6))*(sqrt(5)+sqrt(6))^(4*n-3) + (2*sqrt(5)-5*sqrt(6))*(sqrt(5)-sqrt(6))^(4*n-3)+40).
a(n) = ceiling(1/120*(2*sqrt(5)+5*sqrt(6))*(sqrt(5)+sqrt(6))^(4*n-3)). (End)
Showing 1-2 of 2 results.