A063258 a(n) = binomial(n+5,4) - 1.
4, 14, 34, 69, 125, 209, 329, 494, 714, 1000, 1364, 1819, 2379, 3059, 3875, 4844, 5984, 7314, 8854, 10625, 12649, 14949, 17549, 20474, 23750, 27404, 31464, 35959, 40919, 46375, 52359, 58904, 66044, 73814, 82250, 91389, 101269, 111929, 123409, 135750
Offset: 0
Links
- Harry J. Smith, Table of n, a(n) for n = 0..1000
- Guillaume Aupy, Julien Herrmann. Periodicity in optimal hierarchical checkpointing schemes for adjoint computations. Optimization Methods and Software, Volume 32, 2017 - Issue 3. Preprint
- D. D. Frey and J. A. Sellers, Generalizing Bailey's generalization of the Catalan numbers, The Fibonacci Quarterly, 39 (2001) 142-148.
- Milan Janjic, Two Enumerative Functions
- Index entries for linear recurrences with constant coefficients, signature (5,-10,10,-5,1).
Crossrefs
Programs
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Magma
[Binomial(n+5,4) -1 : n in [0..50]]; // G. C. Greubel, Apr 22 2024
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Maple
[seq(binomial(n+5,4)-1,n=0..37)]; # Zerinvary Lajos, Nov 25 2006
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Mathematica
Binomial[5+Range[0,50],4] -1 (* G. C. Greubel, Apr 22 2024 *)
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PARI
{ for (n=0, 1000, write("b063258.txt", n, " ", binomial(n + 5, 4) - 1) ) } \\ Harry J. Smith, Aug 19 2009
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SageMath
[binomial(n+5,4) -1 for n in range(51)] # G. C. Greubel, Apr 22 2024
Formula
a(n) = A062750(n+2, 4) = (n+6)*(n+1)*(n^2 + 7*n + 16)/4!.
G.f.: (2-x)*(2-2*x+x^2)/(1-x)^5 = N(4;1, x)/(1-x)^5 with N(4;1, x)= 4 - 6*x + 4*x^2 - x^3, polynomial of second row of A062751.
E.g.f.: (1/24)*(96 + 240*x + 120*x^2 + 20*x^3 + x^4)*exp(x). - G. C. Greubel, Apr 22 2024
a(n) = A000332(n+5)-1. - R. J. Mathar, Nov 22 2024
Extensions
Simpler definition from Vladeta Jovovic, Jul 21 2003
Comments