cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-5 of 5 results.

A056072 a(n) = floor(e^e^ ... ^e), with n e's.

Original entry on oeis.org

1, 2, 15, 3814279
Offset: 0

Views

Author

Robert G. Wilson v, Jul 26 2000

Keywords

Comments

The next term is too large to include.
From Vladimir Reshetnikov, Apr 27 2013: (Start)
a(4) = 2331504399007195462289689911...2579139884667434294745087021 (1656521 decimal digits in total), given by initial segment of A085667.
a(5) has more than 10^10^6 decimal digits.
a(6) has more than 10^10^10^6 decimal digits. (End)

Crossrefs

Programs

A159825 Continued fraction for e^e^e A073227.

Original entry on oeis.org

3814279, 9, 1, 1, 4, 1, 53, 26, 1, 13, 3, 1, 1, 22, 1, 226, 1, 5, 2, 1, 6, 2, 3, 1, 4, 1, 6, 39, 2, 1, 3, 1, 5, 1, 4, 1, 3, 1, 4, 1, 1, 19, 1, 2, 8899, 5, 2, 2, 1, 3, 3, 2, 2, 2, 1, 1, 3, 5, 1, 6, 10, 2, 1, 2, 1, 1, 1, 2, 2, 4, 1, 10, 2, 6, 1, 5, 6, 2, 4, 2, 1, 2, 1, 1, 1, 3, 2, 2, 1, 1, 11, 7, 3, 1, 4, 4
Offset: 0

Views

Author

Harry J. Smith, Apr 30 2009

Keywords

Comments

It was conjectured (but remains unproved) that this sequence is infinite and aperiodic, but it is difficult to determine who first posed this problem. - Vladimir Reshetnikov, Apr 27 2013

Examples

			3814279.104760220592209... = 3814279 + 1/(9 + 1/(1 + 1/(1 + 1/(4 + ...)))).
		

Crossrefs

Programs

  • Mathematica
    ContinuedFraction[E^E^E, 96] (* Vladimir Reshetnikov, Apr 27 2013 *)
  • PARI
    { allocatemem(932245000); default(realprecision, 21000); x=contfrac(exp(exp(exp(1)))); for (n=1, 20001, write("b159825.txt", n-1, " ", x[n])); }

A225053 Second terms of continued fractions for power towers e, e^e, e^e^e, ...

Original entry on oeis.org

1, 6, 9, 4
Offset: 1

Views

Author

Vladimir Reshetnikov, Apr 25 2013

Keywords

Comments

It was conjectured (but remains unproved) that none of the power towers e, e^e, e^e^e, ... are integers. If so, the corresponding continued fractions contain at least 2 terms. If the conjecture fails, let the corresponding a(n) = 0.

Examples

			a(3) = 9 because floor(1/frac(e^e^e)) = 9, since e^e^e ~ 3814279.10476.
		

Crossrefs

A056072 yields the first term of the continued fraction.

Programs

  • Mathematica
    $MaxExtraPrecision = Infinity; terms = 4; Map[Function[x, ContinuedFraction[x, 2][[2]]], NestList[Exp, E, terms - 1]]

A116907 Continued fraction expansion for e^(-e) = 0.0659880358453125370767901875.

Original entry on oeis.org

0, 15, 6, 2, 13, 1, 3, 6, 2, 1, 1, 5, 1, 1, 1, 9, 4, 1, 1, 1, 6, 7, 1, 2, 4, 1, 2, 2, 24, 1, 2, 4, 56, 1, 1, 2, 4, 1, 75, 1, 5, 1, 2, 2, 1, 137, 2, 2, 97, 3, 16, 1, 1, 1, 1, 3, 5, 12, 1, 1, 2, 1, 53, 1, 2, 5, 3, 2, 4, 1, 2, 1, 39, 1, 2, 1, 4, 1, 11, 1, 5, 5, 1, 4, 1, 17, 12, 4, 82, 1, 4, 6, 25, 3, 2, 3, 39
Offset: 1

Views

Author

Jonathan Vos Post, Mar 16 2006

Keywords

Comments

e^(-e) = (1/e)^e = 1/(e^e) = (reciprocal of A073226). e^(-e) = 0.0659880358453125370767901875... = 0 + 1/15+ 1/6+ 1/2+ 1/13+ 1/1+ 1/3+ 1/6+ 1/2+ ... See also: A073230 Decimal expansion of (1/e)^e. See also: A064107 Continued fraction quotients for e^e = 15.15426223. See also: A058287 Continued fraction for e^Pi. See also: A058288 Continued fraction expansion of Pi^e.

Crossrefs

A225062 Continued fraction for 1/frac(e^e^e^e). Also, continued fraction for e^e^e^e starting from the 2nd term.

Original entry on oeis.org

4, 1, 1, 11, 1, 1, 3, 1, 6, 2, 1, 3, 1, 1, 8, 1, 8, 2, 3, 1, 3, 3, 1, 1, 4, 22, 4, 2, 2, 4, 6, 1, 98, 1, 3, 1, 3, 1, 1, 3, 3, 1, 1, 1, 9, 2, 16, 1, 1, 1, 3, 3, 1, 11, 2, 1, 2, 1, 2, 5, 1, 11, 1, 7, 4, 1, 4, 12, 8, 1, 6, 1, 1, 1, 1, 4, 2, 2, 3, 2, 1, 1, 7, 1, 8, 8, 1, 117, 4, 6, 3, 1, 3, 1, 1, 4, 2, 2, 7, 1, 2, 1, 1, 3, 21, 1, 9, 6, 1, 1, 4, 2, 2, 1, 5
Offset: 1

Views

Author

Vladimir Reshetnikov, Apr 26 2013

Keywords

Comments

The 1st term of continued fraction for e^e^e^e has 1656521 decimal digits, so it is not included in the sequence.

Crossrefs

Programs

  • Mathematica
    $MaxExtraPrecision = Infinity; terms = 115; ContinuedFraction[1/FractionalPart[E^E^E^E], terms]
Showing 1-5 of 5 results.