cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A068740 Result after dividing (n^n)! as many times as possible by n!.

Original entry on oeis.org

1, 1, 3, 833712928048000000
Offset: 0

Views

Author

Henry Bottomley, Feb 26 2002

Keywords

Comments

For prime n, it is also the number of generalized knockout tournament seedings with n players in one match and n rounds (see formula below). - Alexander Karpov, Dec 14 2017
Next term is too large to include.
From Robert G. Wilson v, Dec 14 2017: (Start)
a(4) = 4125147631... (370 digits)...3291015625,
a(5) = 3483655217... (7923 digits)...3819109376,
a(6) = 2196422024... (164237 digits)...0161431552,
a(7) = 4948281440... (4005981 digits)...0000000000,
a(8) = 4242413765...(102886160 digits)...4619140625,
(End)

Examples

			a(3)=833712928048000000 since 3!=6 and (3^3)!=27!=10888869450418352160768000000 which is divisible by 6^13=13060694016 but not 6^14=78364164096.
		

Crossrefs

Formula

a(n) = A068741(n)/A068742(n).
For p prime, a(p) = (p^p)!/(p!)^((p^p-1)/(p-1)).

A068741 a(n) = (n^n)!.

Original entry on oeis.org

1, 1, 24, 10888869450418352160768000000
Offset: 0

Views

Author

Henry Bottomley, Feb 26 2002

Keywords

Comments

Next term: 857817775342842654119...0 (507 digits). - Vladimir Joseph Stephan Orlovsky, Dec 03 2008

Examples

			a(0) = (0^0)! = 1! = 1;
a(1) = (1^1)! = 1! = 1;
a(2) = (2^2)! = 4! = 24;
a(3) = (3^3)! = 27! = 10888869450418352160768000000.
		

Crossrefs

Programs

Formula

a(n) = A000142(A000312(n)). - Michel Marcus, Jan 12 2015
Showing 1-2 of 2 results.