cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A090622 Square array read by antidiagonals of highest power of k dividing n! (with n,k>1).

Original entry on oeis.org

1, 0, 1, 0, 1, 3, 0, 0, 1, 3, 0, 0, 1, 1, 4, 0, 1, 0, 1, 2, 4, 0, 0, 1, 1, 2, 2, 7, 0, 0, 0, 1, 1, 2, 2, 7, 0, 0, 1, 0, 2, 1, 3, 4, 8, 0, 0, 0, 1, 0, 2, 1, 3, 4, 8, 0, 0, 0, 0, 1, 1, 2, 1, 4, 4, 10, 0, 0, 0, 1, 1, 1, 1, 4, 2, 4, 5, 10, 0, 0, 1, 0, 1, 1, 2, 1, 4, 2, 5, 5, 11, 0, 0, 0, 1, 0, 1, 1, 2, 1, 4, 2, 5, 5, 11
Offset: 2

Views

Author

Henry Bottomley, Dec 06 2003

Keywords

Examples

			Square array starts:
1, 0, 0, 0, 0, 0, 0, ...
1, 1, 0, 0, 1, 0, 0, ...
3, 1, 1, 0, 1, 0, 1, ...
3, 1, 1, 1, 1, 0, 1, ...
4, 2, 2, 1, 2, 0, 1, ...
4, 2, 2, 1, 2, 1, 1, ...
7, 2, 3, 1, 2, 1, 2, ...
		

Crossrefs

Programs

  • Maple
    f:= proc(n, p) local c, k; c, k:= 0, p;
           while n>=k do c:= c+iquo(n, k); k:= k*p od; c
        end:
    T:= (n, k)-> min(seq(iquo(f(n, i[1]), i[2]), i=ifactors(k)[2])):
    seq(seq(T(n, 2+d-n), n=2..d), d=2..20);  # Alois P. Heinz, Oct 04 2012
  • Mathematica
    f[n_, p_] := Module[{c = 0, k = p}, While[n >= k , c = c + Quotient[n, k]; k = k*p ]; c ]; t[n_, k_] := Min[ Table[ Quotient[f[n, i[[1]]], i[[2]]], {i, FactorInteger[k]}]]; Table[ Table[t[n, 2 + d - n], {n, 2, d}], {d, 2, 20}] // Flatten (* Jean-François Alcover, Oct 03 2013, translated from Alois P. Heinz's Maple program *)

Formula

For k=p prime: T(n,p) = [n/p] + [n/p^2] + [n/p^3] + .... For k = p^m a prime power: T(n,p^m) = [T(n,p)/m]. For k = b*c with b and c coprime: T(n,a*b) = min(T(n,a), T(n,b)). T(n,k) is close to, but below, n/A090624(k).

A064459 a(n) = Sum_{k>=1} floor(n/12^k).

Original entry on oeis.org

0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8
Offset: 0

Views

Author

Robert G. Wilson v, Oct 03 2001

Keywords

Comments

Original incorrect name was: "Highest power of 12 dividing n!": that sequence is A090619. If p is prime, Legendre's formula says the highest power of p dividing n! is Sum_{k>=1} floor(n/p^k), but of course 12 is not prime. - Robert Israel, Mar 23 2018

Crossrefs

Programs

  • GAP
    List([0..110],n->Sum([1..n],k-?Int(n/(12^k)))); # Muniru A Asiru, Mar 24 2018
  • Maple
    f:= proc(n) add(floor(n/12^k), k=1..floor(log[12](n))) end proc:
    f(0):= 0:
    map(f, [$0..100]); # Robert Israel, Mar 23 2018
  • Mathematica
    Table[t = 0; p = 12; While[s = Floor[n/p]; t = t + s; s > 0, p *= 12]; t, {n, 0, 100} ]
    Join[{0},Accumulate[Table[If[Divisible[n,12],1,0],{n,110}]]] (* Harvey P. Dale, Feb 14 2016 *)
  • PARI
    { for (n=0, 1000, a=0; p=12; while (s = n\p, a+=s; p*=12); write("b064459.txt", n, " ", a) ) } \\ Harry J. Smith, Sep 15 2009
    

Formula

a(n) = floor[n/12] + floor[n/144] + floor[n/1728] + floor[n/20736] + ....

Extensions

Corrected by Robert Israel, Mar 23 2018

A090621 Exponent of highest power of 16 dividing n!.

Original entry on oeis.org

0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 4, 4, 4, 4, 4, 4, 5, 5, 5, 5, 6, 6, 6, 6, 7, 7, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9, 10, 10, 10, 10, 11, 11, 11, 11, 12, 12, 12, 12, 13, 13, 13, 13, 14, 14, 14, 14, 15, 15, 16, 16, 16, 16, 16, 16, 17, 17, 17, 17, 18, 18, 18, 18, 19, 19, 19, 19
Offset: 0

Views

Author

Henry Bottomley, Dec 06 2003

Keywords

Examples

			a(10)=2 since 10! = 3628800 = 16^2 * 14175.
		

Crossrefs

Programs

Formula

a(n) = A090622(n, 16) = floor(A011371(n)/4) = floor(A090616(n)/2) = floor((floor(n/2) + floor(n/4) + floor(n/8) + floor(n/16) + ...)/4). Almost n/4.
Showing 1-3 of 3 results.