cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-6 of 6 results.

A182712 Number of 2's in the last section of the set of partitions of n.

Original entry on oeis.org

0, 0, 1, 0, 2, 1, 4, 3, 8, 7, 15, 15, 27, 29, 48, 53, 82, 94, 137, 160, 225, 265, 362, 430, 572, 683, 892, 1066, 1370, 1640, 2078, 2487, 3117, 3725, 4624, 5519, 6791, 8092, 9885, 11752, 14263, 16922, 20416, 24167, 29007, 34254, 40921, 48213, 57345, 67409
Offset: 0

Views

Author

Omar E. Pol, Nov 28 2010

Keywords

Comments

Essentially the same as A087787 but here a(n) is the number of 2's in the last section of n, not n-2. See also A100818.
Note that a(1)..a(11) coincide with a(2)..a(12) of A005291.
Also number of 2's in all partitions of n that do not contain 1's as a part, if n >= 1. Also 0 together with the first differences of A024786. - Omar E. Pol, Nov 13 2011
Also number of 2's in the n-th section of the set of partitions of any integer >= n. For the definition of "section" see A135010. - Omar E. Pol, Dec 01 2013

Examples

			a(6) = 4 counts the 2's in 6 = 4+2 = 2+2+2. The 2's in 6 = 3+2+1 = 2+2+1+1 = 2+1+1+1+1 do not count. - _Omar E. Pol_, Nov 13 2011
From _Omar E. Pol_, Oct 27 2012: (Start)
----------------------------------
Last section               Number
of the set of                of
partitions of 6             2's
----------------------------------
6 .......................... 0
3 + 3 ...................... 0
4 + 2 ...................... 1
2 + 2 + 2 .................. 3
.   1 ...................... 0
.       1 .................. 0
.       1 .................. 0
.           1 .............. 0
.           1 .............. 0
.               1 .......... 0
.                   1 ...... 0
---------------------------------
.   8 - 4 =                  4
.
In the last section of the set of partitions of 6 the difference between the sum of the second column and the sum of the third column is 8 - 4 = 4, the same as the number of 2's, so a(6) = 4 (see also A024786).
(End)
		

Crossrefs

Programs

  • Mathematica
    Table[Count[Flatten@Cases[IntegerPartitions[n], x_ /; Last[x] != 1], 2], {n, 0, 49}] (* Robert Price, May 15 2020 *)
  • Sage
    A182712 = lambda n: sum(list(p).count(2) for p in Partitions(n) if 1 not in p) # Omar E. Pol, Nov 13 2011

Formula

It appears that A000041(n) = a(n+1) + a(n+2), n >= 0. - Omar E. Pol, Feb 04 2012
G.f.: (x^2/(1 + x))*Product_{k>=1} 1/(1 - x^k). - Ilya Gutkovskiy, Jan 03 2017
a(n) ~ exp(Pi*sqrt(2*n/3)) / (8*sqrt(3)*n). - Vaclav Kotesovec, Jun 02 2018

A062282 Number of permutations of n elements with an even number of fixed points.

Original entry on oeis.org

1, 0, 2, 2, 16, 64, 416, 2848, 22912, 205952, 2060032, 22659328, 271913984, 3534877696, 49488295936, 742324422656, 11877190795264, 201912243453952, 3634420382302208, 69053987263479808, 1381079745270120448, 29002674650671480832, 638058842314774675456
Offset: 0

Views

Author

Ahmed Fares (ahmedfares(AT)my-deja.com), Jul 04 2001

Keywords

Comments

Let d(n) be the number of derangements of n elements (sequence A000166) then a(n) has the recursion: a(n) = d(n) + C(n,2)*d(n-2) + C(n,4)*d(n-4) + C(n,6)*d(n-6)... = A000166(n) + A000387(n) + A000475(n) + C(n,6)*d(n-6)... The E.g.f. for a(n) is: cosh(x) * exp(-x)/(1-x) and the asymptotic expression for a(n) is: a(n) ~ n! * (1 + 1/e^2)/2 i.e., as n goes to infinity the fraction of permutations that has an even number of fixed points is about (1 + 1/e^2)/2 = 0.567667...

Crossrefs

Programs

  • Mathematica
    nn = 20; d = Exp[-x]/(1 - x); Range[0, nn]! CoefficientList[Series[Cosh[x] d, {x, 0, nn}], x] (* Geoffrey Critzer, Jan 14 2012 *)
    Table[Sum[Sum[(-1)^j * n!/(j!*(2*k)!), {j, 0, n - 2*k}], {k, 0, Floor[n/2]}], {n,0,50}] (* G. C. Greubel, Aug 21 2017 *)
  • PARI
    for(n=0,50, print1(sum(k=0,n\2, sum(j=0,n-2*k, (-1)^j*n!/(j!*(2*k)!))), ", ")) \\ G. C. Greubel, Aug 21 2017

Formula

a(n) = Sum_{k=0..[n/2]} Sum_{l=0..(n-2*k)} (-1)^l * n!/((2*k)! * l!).
More generally, e.g.f. for number of degree-n permutations with an even number of k-cycles is cosh(x^k/k)*exp(-x^k/k)/(1-x). - Vladeta Jovovic, Jan 31 2006
E.g.f.: 1/(1-x)/(x*E(0)+1), where E(k) = 1 - x^2/( x^2 + (2*k+1)*(2*k+3)/E(k+1) ); (continued fraction ). - Sergei N. Gladkovskii, Dec 29 2013
Conjecture: a(n) = Sum_{k=0..n} A008290(n, k)*A059841(k). - John Keith, Jun 30 2020

Extensions

More terms from Vladeta Jovovic, Jul 05 2001

A113979 Number of compositions of n with an even number of 1's.

Original entry on oeis.org

1, 0, 2, 1, 6, 6, 20, 28, 72, 120, 272, 496, 1056, 2016, 4160, 8128, 16512, 32640, 65792, 130816, 262656, 523776, 1049600, 2096128, 4196352, 8386560, 16781312, 33550336, 67117056, 134209536, 268451840, 536854528, 1073774592, 2147450880
Offset: 0

Views

Author

Vladeta Jovovic, Jan 31 2006

Keywords

Comments

More generally, the g.f. for the number of compositions such that part m occurs with even multiplicity is (1-x)/(1-2*x)*(1-2*x+x^m-x^(m+1))/(1-2*x+2*x^m-2*x^(m+1)). - Vladeta Jovovic, Sep 01 2007

Examples

			a(4)=6 because the compositions of 4 having an even number of 1's are 4,22,211,121,112 and 1111 (the other compositions of 4 are 31 and 13).
		

Crossrefs

Programs

  • Maple
    a:=proc(n) if n mod 2 = 0 then 2^(n-2)+2^((n-2)/2) else 2^(n-2)-2^((n-3)/2) fi end: seq(a(n),n=1..38); # Emeric Deutsch, Feb 01 2006
  • Mathematica
    f[n_] := If[ EvenQ[n], 2^(n - 2) + 2^((n - 2)/2), 2^(n - 2) - 2^((n - 3)/2)]; Array[f, 34] (* Robert G. Wilson v, Feb 01 2006 *)
  • PARI
    a(n) = n-=2; (n==-2) + 1<=0, (-1)^n << (n>>1)); \\ Kevin Ryde, May 02 2023

Formula

a(0) = 1, a(n) = 2^(n-2) + 2^((n-2)/2) if n is positive and even, otherwise a(n) = 2^(n-2) - 2^((n-3)/2).
G.f.: (1-z)*(1-z-z^2)/((1-2*z)*(1-2*z^2)). - Emeric Deutsch, Feb 03 2006
E.g.f.: (1 + exp(2*x) - sqrt(2)*sinh(x*sqrt(2)) + 2*cosh(x*sqrt(2)))/4. - Sergei N. Gladkovskii, Nov 18 2011
a(k) = (1/4)*0^k + (1/4)*2^k + (1/8)*(2-sqrt(2))*(sqrt(2))^k + (1/8)*(2+sqrt(2))*(-sqrt(2))^k. - Sergei N. Gladkovskii, Nov 18 2011

Extensions

More terms from Robert G. Wilson v and Emeric Deutsch, Feb 01 2006
a(0)=1 prepended and formulas corrected by Jason Yuen, Sep 09 2024

A182722 a(n) = A005291(n+1)-A182712(n).

Original entry on oeis.org

1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 3, 5, 10, 14, 26, 36, 60, 83, 128, 175, 261, 351, 504, 674, 943, 1247, 1711, 2243
Offset: 0

Views

Author

Omar E. Pol, Nov 28 2010, Nov 29 2010

Keywords

Comments

The difference between two apparently unrelated sequences which happen to have the same initial terms. - N. J. A. Sloane, Dec 01 2010

Crossrefs

Formula

a(n) = A005291(n+1)-A182712(n)

A113980 Number of compositions of n with an odd number of 1's.

Original entry on oeis.org

1, 0, 3, 2, 10, 12, 36, 56, 136, 240, 528, 992, 2080, 4032, 8256, 16256, 32896, 65280, 131328, 261632, 524800, 1047552, 2098176, 4192256, 8390656, 16773120, 33558528, 67100672, 134225920, 268419072, 536887296, 1073709056, 2147516416
Offset: 1

Views

Author

Vladeta Jovovic, Jan 31 2006

Keywords

Examples

			a(4)=2 because only the compositions 31 and 13 of 4 have an odd number of 1's (the other compositions are 4,22,211,121,112 and 1111).
		

Crossrefs

Programs

  • Maple
    a:=proc(n) if n mod 2 = 0 then 2^(n-2)-2^((n-2)/2) else 2^(n-2)+2^((n-3)/2) fi end: seq(a(n),n=1..38); # Emeric Deutsch, Feb 01 2006
  • Mathematica
    f[n_] := If[EvenQ[n], 2^(n - 2) - 2^((n - 2)/2), 2^(n - 2) + 2^((n - 3)/2)]; Array[f, 34] (* Robert G. Wilson v, Feb 01 2006 *)

Formula

a(n) = 2^(n-2)-2^((n-2)/2) if n is even, else a(n) = 2^(n-2)+2^((n-3)/2).
G.f.: z(1-z)^2/[(1-2z)(1-2z^2)]. - Emeric Deutsch, Feb 03 2006
G.f.: 1 + x + Q(0), where Q(k)= 1 - 1/(2^k - 2*x*2^(2*k)/(2*x*2^k - 1/(1 + 1/(2*2^k - 8*x*2^(2*k)/(4*x*2^k + 1/Q(k+1)))))); (continued fraction). - Sergei N. Gladkovskii, May 22 2013

Extensions

More terms from Robert G. Wilson v and Emeric Deutsch, Feb 01 2006

A195308 a(n) = A005291(n) + A005291(n+1).

Original entry on oeis.org

1, 1, 1, 2, 3, 5, 7, 11, 15, 22, 30, 43, 58, 81, 109, 150, 200, 271, 359, 481, 633, 838, 1095, 1438, 1867, 2430, 3136, 4053, 5200, 6676, 8519, 10871, 13802, 17514, 22129, 27940, 35141, 44155, 55299, 69179, 86286, 107495, 133562, 165744, 205188, 253691, 312975, 385619
Offset: 1

Views

Author

Omar E. Pol, Feb 03 2012

Keywords

Comments

This sequence arises from A005291 in the same way as A000041 arises from A182712.
Observation: a(3)..a(13) coincide with a sequence related to Stirling's numbers from the Jordan's book.

References

  • Charles Jordan, Calculus of finite differences, Chelsea Publishing Co., 1965, chapter IV, pp. 153-155.

Crossrefs

Formula

a(n) = A000041(n-2), 2 <= n <= 11. - Omar E. Pol, Feb 24 2013

Extensions

More terms from Amiram Eldar, May 17 2025
Showing 1-6 of 6 results.