cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-5 of 5 results.

A103348 Denominators of sum_{k=1..n} 1/k^7 = Zeta(7,n).

Original entry on oeis.org

1, 128, 279936, 35831808, 2799360000000, 933120000000, 768464444160000000, 98363448852480000000, 645362587921121280000000, 645362587921121280000000, 12576291107821424895098880000000, 12576291107821424895098880000000
Offset: 1

Views

Author

Wolfdieter Lang, Feb 15 2005

Keywords

Comments

For the numerators, comments and a link reference see A103347.

Programs

A103349 Numerators of sum_{k=1..n} 1/k^8 = Zeta(8,n).

Original entry on oeis.org

1, 257, 1686433, 431733409, 168646292872321, 168646392872321, 972213062238348973121, 248886558707571775009601, 1632944749460578249437992161, 1632944765723715465050248417
Offset: 1

Views

Author

Wolfdieter Lang, Feb 15 2005

Keywords

Comments

a(n) gives the partial sums, Zeta(8,n) of Euler's Zeta(8). Zeta(k,n) is also called H(k,n) because for k=1 these are the harmonic numbers H(n) A001008/A002805.
For the denominators see A103350 and for the rationals Zeta(8,n) see the W. Lang link under A103345.

Crossrefs

Programs

Formula

a(n)=numerator(sum_{k=1..n} 1/k^8).
G.f. for rationals Zeta(8, n): polylogarithm(8, x)/(1-x).

A103351 Numerators of sum_{k=1..n} 1/k^9 = Zeta(9,n).

Original entry on oeis.org

1, 513, 10097891, 5170139875, 10097934603139727, 373997614931101, 15092153145114981831307, 7727182467755471289426059, 4106541588424891370931874221019, 4106541592523201949266162797531
Offset: 1

Views

Author

Wolfdieter Lang, Feb 15 2005

Keywords

Comments

a(n) gives the partial sums, Zeta(9,n), of Euler's Zeta(9). Zeta(k,n) is also called H(k,n) because for k=1 these are the harmonic numbers H(n) A001008/A002805.
For the denominators see A103352 and for the rationals Zeta(9,n) see the W. Lang link under A103345.

Crossrefs

Programs

Formula

a(n) = numerator(sum_{k=1..n} 1/k^9).
G.f. for rationals Zeta(9, n): polylogarithm(9, x)/(1-x).

A103716 Numerators of sum_{k=1..n} 1/k^10 =: Zeta(10,n).

Original entry on oeis.org

1, 1025, 60526249, 61978938025, 605263128567754849, 605263138567754849, 170971856382109814342232401, 175075181098169912564190119249, 10338014371627802833957102351534201, 413520574906423083987893722912609
Offset: 1

Views

Author

Wolfdieter Lang, Feb 15 2005

Keywords

Comments

a(n) gives the partial sums, Zeta(10,n), of Euler's Zeta(10). Zeta(k,n) is also called H(k,n) because for k=1 these are the harmonic numbers H(n) = A001008/A002805.
For the denominators see A103717 and for the rationals Zeta(10,n) see the W. Lang link under A103345.

Crossrefs

Programs

Formula

a(n) = numerator(sum_{k=1..n} 1/k^10).
G.f. for rationals Zeta(10, n): polylogarithm(10, x)/(1-x).

A322265 Square array A(n,k), n >= 1, k >= 0, read by antidiagonals: A(n,k) = numerator of Sum_{j=1..n} 1/j^k.

Original entry on oeis.org

1, 1, 2, 1, 3, 3, 1, 5, 11, 4, 1, 9, 49, 25, 5, 1, 17, 251, 205, 137, 6, 1, 33, 1393, 2035, 5269, 49, 7, 1, 65, 8051, 22369, 256103, 5369, 363, 8, 1, 129, 47449, 257875, 14001361, 28567, 266681, 761, 9, 1, 257, 282251, 3037465, 806108207, 14011361, 9822481, 1077749, 7129, 10
Offset: 1

Views

Author

Ilya Gutkovskiy, Dec 01 2018

Keywords

Examples

			Square array begins:
  1,       1,          1,              1,                  1,  ...
  2,     3/2,        5/4,            9/8,              17/16,  ...
  3,    11/6,      49/36,        251/216,          1393/1296,  ...
  4,   25/12,    205/144,      2035/1728,        22369/20736,  ...
  5,  137/60,  5269/3600,  256103/216000,  14001361/12960000,  ...
		

Crossrefs

Denominators are in A322266.

Programs

  • Mathematica
    Table[Function[k, Numerator[Sum[1/j^k, {j, 1, n}]]][i - n], {i, 0, 10}, {n, 1, i}] // Flatten
    Table[Function[k, Numerator[HarmonicNumber[n, k]]][i - n], {i, 0, 10}, {n, 1, i}] // Flatten
    Table[Function[k, Numerator[SeriesCoefficient[PolyLog[k, x]/(1 - x), {x, 0, n}]]][i - n], {i, 0, 10}, {n, 1, i}] // Flatten

Formula

G.f. of column k: PolyLog(k,x)/(1 - x), where PolyLog() is the polylogarithm function (for rationals Sum_{j=1..n} 1/j^k).
Showing 1-5 of 5 results.