A024482 a(n) = (1/2)*(binomial(2n, n) - binomial(2n-2, n-1)).
2, 7, 25, 91, 336, 1254, 4719, 17875, 68068, 260338, 999362, 3848222, 14858000, 57500460, 222981435, 866262915, 3370764540, 13135064250, 51250632510, 200205672810, 782920544640, 3064665881940, 12007086477750, 47081501377326, 184753963255176, 725510446350004
Offset: 2
Keywords
Examples
The path udUududD has two sawtooth patterns, shown in lower case.
Links
- Stefano Spezia, Table of n, a(n) for n = 2..1600
- Toufik Mansour and I. L. Ramirez, Enumerations of polyominoes determined by Fuss-Catalan words, Australas. J. Combin. 81 (3) (2021) 447-457, table 2.
Programs
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Magma
[(3*n-2)*Catalan(n-1)/2: n in [2..40]]; // G. C. Greubel, Apr 03 2024
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Maple
Z:=(1-z-sqrt(1-4*z))/sqrt(1-4*z)/2: Zser:=series(Z, z=0, 32): seq(coeff(Zser, z, n), n=2..25); # Zerinvary Lajos, Jan 16 2007
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Mathematica
Table[(Binomial[2n,n]-Binomial[2n-2,n-1])/2,{n,2,30}] (* Harvey P. Dale, Mar 04 2011 *)
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SageMath
[(3*n-2)*catalan_number(n-1)/2 for n in range(2,41)] # G. C. Greubel, Apr 03 2024
Formula
a(n) = A051924(n)/2. - Zerinvary Lajos, Jan 16 2007
From R. J. Mathar, Nov 09 2018: (Start)
D-finite with recurrence n*a(n) - (5*n-4)*a(n-1) + 2*(2*n-5)*a(n-2) = 0.
n*(3*n-5)*a(n) - 2*(3*n-2)*(2*n-3)*a(n-1) = 0. (End)
a(n) ~ 3*2^(2*n-3)/sqrt(n*Pi). - Stefano Spezia, May 09 2023
From G. C. Greubel, Apr 03 2024: (Start)
a(n) = (3*n-2)*A000108(n-1)/2.
G.f.: ((1-x)*sqrt(1-4*x) - (1+x)*(1-4*x))/(2*(1-4*x)).
E.g.f.: (1/2)*( -1 - x + exp(2*x)*( (1-x)*BesselI(0, 2*x) + x*BesselI(1, 2*x) ) ). (End)
Comments