1, 1, 2, 3, 1, 4, 3, 7, 4, -5, 6, 7, -1, 12, 6, -3, -7, 8, 12, -4, -1, 15, 8, -7, -3, 13, 15, -6, -4, 18, 13, -12, -7, 12, 18, -8, -6, 12, 28, 12, -15, -12, 1, 14, 28, -13, -8, 3, 24, 14, -18, -15, 4, 15, 24, 24, -12, -13, 7, 1, 31, 24, -28, -18, 6, 3
Offset: 1
Triangle begins:
1;
1, 2;
3, 1;
4, 3;
7, 4, -5;
6, 7, -1;
12, 6, -3, -7;
8, 12, -4, -1;
15, 8, -7, -3;
13, 15, -6, -4;
18, 13, -12, -7;
12, 18, -8, -6, 12;
28, 12, -15, -12, 1;
14, 28, -13, -8, 3;
24, 14, -18, -15, 4, 15;
24, 24, -12, -13, 7, 1;
31, 24, -28, -18, 6, 3;
18, 31, -14, -12, 12, 4;
39, 18, -24, -28, 8, 7;
20, 39, -24, -14, 15, 6;
42, 20, -31, -24, 13, 12;
32, 42, -18, -24, 18, 8, -22;
36, 32, -39, -31, 12, 15, -1;
24, 36, -20, -18, 28, 13, -3;
60, 24, -42, -39, 14, 18, -4;
31, 60, -32, -20, 24, 12, -7, -26;
...
For n = 21 the sum of divisors of 21 is 1 + 3 + 7 + 21 = 32. On the other hand, from Euler's Pentagonal Number Theorem we have that the sum of divisors of 21 is S_21 = S_20 + S_19 - S_16 - S_14 + S_9 + S_6, the same as the sum of the 21st row of triangle: 42 + 20 - 31 - 24 + 13 + 12 = 32, equaling the sum of divisors of 21.
For n = 22 the sum of divisors of 22 is 1 + 2 + 11 + 22 = 36. On the other hand, from Euler's Pentagonal Number Theorem we have that the sum of divisors of 22 is S_22 = S_21 + S_20 - S_17 - S_15 + S_10 + S_7 - S_0, the same as the sum of the 22nd row of triangle is 32 + 42 - 18 - 24 + 18 + 8 - 22 = 36, equaling the sum of divisors of 22. Note that S_0 = n, hence in this case S_0 = 22.
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