cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A245927 G.f.: sqrt( (1-x - sqrt(1-14*x+x^2)) / (6*x*(1-14*x+x^2)) ).

Original entry on oeis.org

1, 9, 99, 1175, 14499, 183195, 2351805, 30539241, 400000275, 5274560891, 69929215641, 931226954949, 12446852889901, 166888293332805, 2243683808486451, 30235162687458327, 408274269493595283, 5523024440001832875, 74834275541765522505, 1015429462194625633125
Offset: 0

Views

Author

Paul D. Hanna, Aug 15 2014

Keywords

Comments

Multiply the square of each term by -3 to form a bisection of A245925.
Limit a(n+1)/a(n) = 7 + 4*sqrt(3).

Examples

			G.f.: A(x) = 1 + 9*x + 99*x^2 + 1175*x^3 + 14499*x^4 + 183195*x^5 +... where
A(x)^2 = (1-x - sqrt(1-14*x+x^2)) / (6*x*(1-14*x+x^2)). Explicitly,
A(x)^2 = 1 + 18*x + 279*x^2 + 4132*x^3 + 59949*x^4 + 860022*x^5 + 12252547*x^6 + 173756232*x^7 + 2456093529*x^8 +...+ A245924(n)*x^n +...
		

Crossrefs

Programs

  • Maple
    seq(add( binomial(2*n+1,2*k)*binomial(2*k,k)*3^(n-k), k = 0..n),n = 0..20); # Peter Bala, Mar 17 2018
  • Mathematica
    CoefficientList[Series[Sqrt[(1-x-Sqrt[1-14x+x^2])/(6x(1-14x+x^2))],{x,0,20}],x] (* Harvey P. Dale, Oct 23 2015 *)
    a[n_] := (-1)^n Hypergeometric2F1[-n, n + 3/2, 1, 4];
    Table[a[n], {n, 0, 19}] (* Peter Luschny, Mar 17 2018 *)
  • PARI
    /* From definition: */
    {a(n)=polcoeff( sqrt( (1-x - sqrt(1-14*x+x^2 +x^2*O(x^n))) / (6*x*(1-14*x+x^2 +x*O(x^n))) ), n)}
    for(n=0, 20, print1(a(n), ", "))
    
  • PARI
    /* From formula for a(n)^2: */
    {a(n)=sqrtint((-1/3)*sum(k=0, 2*n+1, sum(j=0, 4*n-2*k+2, (-1)^(j+k)*binomial(4*n-k+2,j+k)^2*binomial(j+k, k)^2)))}
    for(n=0, 20, print1(a(n), ", "))

Formula

a(n)^2 = (-1/3)*Sum_{k=0..2*n+1} Sum_{j=0..4*n-2*k+2} (-1)^(j+k) * C(4*n-k+2,j+k)^2 * C(j+k,k)^2.
a(n) ~ (3-sqrt(3)) * (7+4*sqrt(3))^(n+1) / (12*sqrt(Pi*n)). - Vaclav Kotesovec, Aug 16 2014
From Peter Bala, Mar 17 2018: (Start)
a(n) = Sum_{k = 0..n} C(2*n+1,2*k)*C(2*k,k)*3^(n-k).
a(n) = 3^n*hypergeom([-n, -n-1/2], [1], 4/3).
n*(4*n-3)*(2*n+1)*a(n) = (4*n-1)*(28*n^2-14*n-5)*a(n-1) - (n-1)*(2*n-1)*(4*n+1)*a(n-2). (End)
a(n) = (-1)^n*hypergeom([-n, n + 3/2], [1], 4). Peter Luschny, Mar 17 2018
a(n) = (-1)^n/sqrt(-3) * P(2*n+1, sqrt(-3)), where P(n, x) denotes the n-th Legendre polynomial. - Peter Bala, Mar 17 2024

A245923 G.f.: (1-x + sqrt(1 - 14*x + x^2)) / (2*(1 - 14*x + x^2)).

Original entry on oeis.org

1, 10, 127, 1684, 22717, 309214, 4231675, 58117672, 800173945, 11037041074, 152448280183, 2107959984316, 29172777600565, 404016491894662, 5598523988234227, 77617624970307664, 1076533162210721521, 14936507761662251866, 207302489038473478255, 2877906561872502533860
Offset: 0

Views

Author

Paul D. Hanna, Aug 16 2014

Keywords

Comments

Self-convolution of A245926.
Limit a(n+1)/a(n) = 7 + 4*sqrt(3).

Examples

			G.f.: A(x) = 1 + 10*x + 127*x^2 + 1684*x^3 + 22717*x^4 + 309214*x^5 +...
		

Crossrefs

Programs

  • Mathematica
    CoefficientList[Series[(1 - x + Sqrt[1 - 14*x + x^2])/(2*(1 - 14*x + x^2)), {x,0,50}], x] (* G. C. Greubel, Feb 14 2017 *)
  • PARI
    {a(n)=polcoeff( (1-x + sqrt(1-14*x+x^2 +x*O(x^n))) / (2*(1-14*x+x^2 +x*O(x^n))), n)}
    for(n=0, 20, print1(a(n), ", "))

Formula

a(n) ~ (7+4*sqrt(3))^(n+1) * (2-sqrt(3))/8 * (1+1/(3^(1/4)*sqrt(Pi*n/2))). - Vaclav Kotesovec, Aug 17 2014
D-finite with recurrence: n*a(n) +7*(-4*n+3)*a(n-1) +99*(2*n-3)*a(n-2) +7*(-4*n+9)*a(n-3) +(n-3)*a(n-4)=0. - R. J. Mathar, Jan 23 2020
Showing 1-2 of 2 results.