cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-9 of 9 results.

A285037 Irregular triangle read by rows: T(n,k) is the number of primitive (period n) periodic palindromic structures using exactly k different symbols, 1 <= k <= n/2 + 1.

Original entry on oeis.org

1, 0, 1, 0, 1, 0, 2, 1, 0, 3, 1, 0, 4, 5, 1, 0, 7, 6, 1, 0, 10, 18, 7, 1, 0, 14, 25, 10, 1, 0, 21, 63, 43, 10, 1, 0, 31, 90, 65, 15, 1, 0, 42, 202, 219, 85, 13, 1, 0, 63, 301, 350, 140, 21, 1, 0, 91, 650, 1058, 618, 154, 17, 1, 0, 123, 965, 1701, 1050, 266, 28, 1
Offset: 1

Views

Author

Andrew Howroyd, Apr 08 2017

Keywords

Comments

Permuting the symbols will not change the structure.
Equivalently, the number of n-bead aperiodic necklaces (Lyndon words) with exactly k symbols, up to permutation of the symbols, which when turned over are unchanged. When comparing with the turned over necklace a rotation is allowed but a permutation of the symbols is not.

Examples

			Triangle starts:
1
0   1
0   1
0   2    1
0   3    1
0   4    5     1
0   7    6     1
0  10   18     7     1
0  14   25    10     1
0  21   63    43    10     1
0  31   90    65    15     1
0  42  202   219    85    13    1
0  63  301   350   140    21    1
0  91  650  1058   618   154   17   1
0 123  965  1701  1050   266   28   1
0 184 2016  4796  4064  1488  258  21  1
0 255 3025  7770  6951  2646  462  36  1
0 371 6220 21094 24914 12857 3222 410 26 1
0 511 9330 34105 42525 22827 5880 750 45 1
...
Example for n=6, k=2:
There are 6 inequivalent solutions to A285012(6,2) which are 001100, 010010, 000100, 001010, 001110, 010101. Of these, 010010 and 010101 have a period less than 6, so T(6,2) = 6-2 = 4.
		

References

  • M. R. Nester (1999). Mathematical investigations of some plant interaction designs. PhD Thesis. University of Queensland, Brisbane, Australia. [See A056391 for pdf file of Chap. 2]

Crossrefs

Columns 1..6 are: A063524, A056518, A056519, A056521, A056522, A056523.
Partial row sums include A056513, A056514, A056515, A056516, A056517.
Row sums are A285042.

Programs

  • PARI
    \\ Ach is A304972
    Ach(n,k=n) = {my(M=matrix(n, k, n, k, n>=k)); for(n=3, n, for(k=2, k, M[n, k]=k*M[n-2, k] + M[n-2, k-1] + if(k>2, M[n-2, k-2]))); M}
    T(n,k=n\2+1) = {my(A=Ach(n\2+1,k), S=matrix(n\2+1, k, n, k, stirling(n,k,2))); Mat(vectorv(n, n, sumdiv(n, d, moebius(d)*(S[(n/d+1)\2, ] + S[n/d\2+1, ] + if((n-d)%2, A[(n/d+1)\2, ] + A[n/d\2+1, ]))/if(d%2, 2, 1) )))}
    { my(A=T(20)); for(n=1, matsize(A)[1], print(A[n,1..n\2+1])) } \\ Andrew Howroyd, Oct 01 2019
    
  • PARI
    \\ column sequence using above code.
    ColSeq(n, k=2) = { Vec(T(n,k)[,k]) } \\ Andrew Howroyd, Oct 01 2019

Formula

T(n, k) = Sum_{d | n} mu(n/d) * A285012(d, k).

A284855 Array read by antidiagonals: T(n,k) = number of necklaces with n beads and k colors that are the same when turned over.

Original entry on oeis.org

1, 2, 1, 3, 3, 1, 4, 6, 4, 1, 5, 10, 9, 6, 1, 6, 15, 16, 18, 8, 1, 7, 21, 25, 40, 27, 12, 1, 8, 28, 36, 75, 64, 54, 16, 1, 9, 36, 49, 126, 125, 160, 81, 24, 1, 10, 45, 64, 196, 216, 375, 256, 162, 32, 1, 11, 55, 81, 288, 343, 756, 625, 640, 243, 48, 1
Offset: 1

Views

Author

Andrew Howroyd, Apr 04 2017

Keywords

Comments

Number of periodic palindromes of length n using a maximum of k different symbols.
From Petros Hadjicostas, Sep 02 2018: (Start)
According to Christian Bower's theory of transforms, we have boxes of different sizes and different colors. The size of a box is determined by the number of balls it can hold. In this case, we assume all balls are the same and are unlabeled. Assume also that the number of possible colors a box with m balls can have is given by c(m). We place the boxes on a circle at equal distances from each other. Two configurations of boxes on the circle are considered equivalent if one can be obtained from the other by rotation. We are interested about circular configurations of boxes that are circular palindromes (i.e., necklaces with boxes that are the same when turned over). Let b(n) be the number of circularly palindromic configurations of boxes on a circle when the total number of balls in the boxes is n (and each box contains at least one ball).
Bower calls the sequence (b(n): n >= 1), the CPAL ("circular palindrome") transform of the input sequence (c(m): m >= 1). If the g.f. of the input sequence (c(m): m >= 1) is C(x) = Sum_{m>=1} c(m)*x^m, then the g.f. of the output sequence (b(n): n >= 1) is B(x) = Sum_{n >= 1} b(n)*x^n = (1 + C(x))^2/(2*(1 - C(x^2))) - 1/2.
In the current sequence, each box holds only one ball but can have one of k colors. Hence, c(1) = k but c(m) = 0 for m >= 2. Thus, C(x) = k*x. Then, for fixed k, the output sequence is (b(n): n >= 1) = (T(n, k): n >= 1), where T(n, k) = number of necklaces with n beads and k colors that are the same when turned over. If we let B_k(x) = Sum_{n>=1} T(n, k)*x^n, then B_k(x) = (1 + k*x)^2/(2*(1 - k*x^2)) - 1/2. From this, we can easily prove the formulae below.
Note that T(n, k=2) - 1 is the total number of Sommerville symmetric cyclic compositions of n. See pp. 301-304 in his paper in the links below. To see why this is the case, we use MacMahon's method of representing a cyclic composition of n with a necklace of 2 colors (see p. 273 in Sommerville's paper where the two "colors" are an x and a dot . rather than B and W). Given a Sommerville symmetrical composition b_1 + ... + b_r of n (with b_i >= 1 for all i and 1 <= r <= n), create the following circularly palindromic necklace with n beads of 2 colors: Start with a B bead somewhere on the circle and place b_1 - 1 W beads to the right of it; place a B bead to the right of the W beads (if any) followed by b_2 - 1 W beads; and so on. At the end, place a B bead followed with b_r - 1 W beads. (If b_i = 1 for some i, then a B bead follows a B bead since there are 0 W beads between them.) We thus get a circularly palindromic necklace with n beads of two colors. (The only necklace we cannot get with this method is the one than has all n beads colored W.)
It is interesting that the representation of a necklace of length n, say s_1, s_2, ..., s_n, as a periodic sequence (..., s_{-2}, s_{-1}, s_0, s_1, s_2, ...) with the property s_i = s_{i+n} for all i, as was done by Marks R. Nester in Chapter 2 of his 1999 PhD thesis, was considered by Sommerville in his 1909 paper (in the very first paragraph of his paper). (End)

Examples

			Table starts:
1  2   3    4    5     6     7      8      9     10 ...
1  3   6   10   15    21    28     36     45     55 ...
1  4   9   16   25    36    49     64     81    100 ...
1  6  18   40   75   126   196    288    405    550 ...
1  8  27   64  125   216   343    512    729   1000 ...
1 12  54  160  375   756  1372   2304   3645   5500 ...
1 16  81  256  625  1296  2401   4096   6561  10000 ...
1 24 162  640 1875  4536  9604  18432  32805  55000 ...
1 32 243 1024 3125  7776 16807  32768  59049 100000 ...
1 48 486 2560 9375 27216 67228 147456 295245 550000 ...
...
For n = 4 and k = 2, the palindromic necklaces are 0000, 0001, 0011, 0111, 0101, 1111 so T(4,2) = 6. Necklaces are only counted up to cyclic equivalence.
For n = 4 and k = 2, using MacMahon's bijection, with B = 0 and W = 1, the corresponding Sommerville symmetrical cyclic compositions of n = 4 are as follows: 1+1+1+1, 1+1+2, 1+3, 4, 2+2 (with none for 1111). If we let B = 1 and W = 0, we get the corresponding symmetrical cyclic compositions of n=4: (none for 0000) 4, 1+3, 1+1+2, 2+2, 1+1+1+1. (All these cyclic compositions must viewed on a circle.) - _Petros Hadjicostas_, Sep 02 2018
		

References

  • M. R. Nester (1999). Mathematical investigations of some plant interaction designs. PhD Thesis. University of Queensland, Brisbane, Australia. [See A056391 for the pdf file of Chap. 2]

Crossrefs

Programs

  • Mathematica
    a[n_, k_] := If[EvenQ[n], (k^(n/2) + k^(n/2 + 1))/2, k^((n+1)/2)];
    Table[a[n-k+1, k], {n, 1, 11}, {k, n, 1, -1}] // Flatten (* Jean-François Alcover, Jun 05 2017, translated from PARI *)
  • PARI
    a(n,k) = if(n % 2 == 0, (k^(n/2) + k^(n/2+1))/2, k^((n+1)/2));
    for(n=1, 10, for(k=1, 10, print1( a(n,k),", ");); print(););

Formula

T(2*n, k) = (k^(n+1) + k^n) / 2.
T(2*n + 1, k) = k^(n+1).
T(n, k) = 2 * A081720(n, k) - A075195(n, k).
From Petros Hadjicostas, Sep 02 2018: (Start)
For fixed k >= 1, the k-th column (T(n, k): n >= 1) is the CPAL ("circular palindrome") transform of the sequence k, 0, 0, ...
G.f. of column k: Sum_{n>=1} T(n,k)*x^n = (1 + k*x)^2/(2*(1 - k*x^2)) - 1/2. (End)

A056493 Number of primitive (period n) periodic palindromes using a maximum of two different symbols.

Original entry on oeis.org

2, 1, 2, 3, 6, 7, 14, 18, 28, 39, 62, 81, 126, 175, 246, 360, 510, 728, 1022, 1485, 2030, 3007, 4094, 6030, 8184, 12159, 16352, 24381, 32766, 48849, 65534, 97920, 131006, 196095, 262122, 392364, 524286, 785407, 1048446, 1571310, 2097150, 3143497
Offset: 1

Views

Author

Keywords

Comments

For example, aaabbb is not a (finite) palindrome but it is a periodic palindrome.
Also number of aperiodic necklaces (Lyndon words) with two colors that are the same when turned over.

Examples

			a(1) = 2 with aaa... and bbb..., a(2) = 1 with ababab..., a(3) = 2 with aabaab... and abbabb..., a(4) = 3 with aaabaaab... and aabbaabb... and abbbabbb.... - _Michael Somos_, Nov 29 2016
		

References

  • M. R. Nester (1999). Mathematical investigations of some plant interaction designs. PhD Thesis. University of Queensland, Brisbane, Australia. [See A056391 for a pdf file of Chap. 2]

Crossrefs

Column 2 of A284856.

Programs

  • Mathematica
    mx=40;gf[x_,k_]:=Sum[ MoebiusMu[n]*Sum[Binomial[k,i]x^(n i),{i,0,2}]/( 1-k x^(2n)),{n,mx}]; CoefficientList[Series[gf[x,2],{x,0,mx}],x] (* Herbert Kociemba, Nov 29 2016 *)

Formula

Sum_{d|n} mu(d)*b(n/d), where b(n) = A029744(n+1). [Corrected by Petros Hadjicostas, Oct 15 2017. The original formula referred to a previous version of sequence A029744 that had a different offset.]
More generally, let gf(k) be the g.f. for the number of necklaces with reflectional symmetry but no rotational symmetry and beads of k colors. Then gf(k): Sum_{n >= 1} mu(n)*Sum_{i=0..2} binomial(k,i)*x^(n*i)/(1 - k*x^(2*n)). - Herbert Kociemba, Nov 29 2016
G.f.: Sum_{n >= 1} mu(n)*x^n*(2 + 3*x^n)/(1 - 2*x^(2*n)). The g.f. by Herbet Kociemba above, with k = 2, becomes Sum_{n>=1} mu(n)*(x^n + 1)^2/(1 - 2*x^(2*n)). The two formulae differ by the "undetermined" constant Sum_{n >= 1} mu(n). - Petros Hadjicostas, Oct 15 2017

Extensions

More terms and additional comments from Christian G. Bower, Jun 22 2000

A327878 Irregular triangle read by rows: T(n,k) is the number of primitive (period n) periodic palindromes using exactly k different symbols, 1 <= k <= 1 + floor(n/2).

Original entry on oeis.org

1, 0, 1, 0, 2, 0, 3, 3, 0, 6, 6, 0, 7, 21, 12, 0, 14, 36, 24, 0, 18, 90, 132, 60, 0, 28, 150, 240, 120, 0, 39, 339, 900, 960, 360, 0, 62, 540, 1560, 1800, 720, 0, 81, 1149, 4968, 9300, 7920, 2520, 0, 126, 1806, 8400, 16800, 15120, 5040, 0, 175, 3765, 24588, 71400, 103320, 73080, 20160
Offset: 1

Views

Author

Andrew Howroyd, Sep 28 2019

Keywords

Comments

Primitive periodic palindromes may also be called achiral Lyndon words.

Examples

			Triangle begins:
  1;
  0,   1;
  0,   2;
  0,   3,    3;
  0,   6,    6;
  0,   7,   21,    12;
  0,  14,   36,    24;
  0,  18,   90,   132,    60;
  0,  28,  150,   240,   120;
  0,  39,  339,   900,   960,    360;
  0,  62,  540,  1560,  1800,    720;
  0,  81, 1149,  4968,  9300,   7920,  2520;
  0, 126, 1806,  8400, 16800,  15120,  5040;
  0, 175, 3765, 24588, 71400, 103320, 73080, 20160;
  ...
		

Crossrefs

Columns k=2..6 are A056498, A056499, A056500, A056501, A056502.
Row sums are A327879.

Programs

  • PARI
    T(n,k) = {sumdiv(n, d, moebius(n/d) * k! * (stirling((d+1)\2,k,2) + stirling(d\2+1,k,2)))/2}

Formula

T(n,k) = Sum_{j=1..k} (-1)^(k-j)*binomial(k,j)*A284856(n,j).
Column k is the Moebius transform of column k of A305540.

A309528 The number of non-equivalent distinguishing colorings of the cycle on n vertices with at most k colors (k>=1). The cycle graph is defined for n>=3; extended to n=1,2 using the closed form. Square array read by descending antidiagonals: the rows are indexed by n, the number of vertices of the cycle and the columns are indexed by k, the number of permissible colors.

Original entry on oeis.org

0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 4, 3, 0, 0, 0, 0, 10, 15, 12, 1, 0, 0, 0, 20, 45, 72, 37, 2, 0, 0, 0, 35, 105, 252, 266, 117, 6, 0, 0, 0, 56, 210, 672, 1120, 1044, 333, 14, 0, 0, 0, 84, 378, 1512, 3515, 5270, 3788, 975, 30, 0, 0, 0, 120, 630, 3024, 9121, 19350, 23475, 14056, 2712, 62, 0
Offset: 1

Views

Author

Bahman Ahmadi, Aug 06 2019

Keywords

Comments

A vertex-coloring of a graph G is called distinguishing if it is only preserved by the identity automorphism of G. This notion is considered in the subject of symmetry breaking of simple (finite or infinite) graphs. Two vertex-colorings of a graph are called equivalent if there is an automorphism of the graph which preserves the colors of the vertices. Given a graph G, we use the notation Phi_k(G) to denote the number of non-equivalent distinguishing colorings of G with at most k colors. The sequence here, displays A(n,k)=Phi_k(C_n), i.e., the number of non-equivalent distinguishing colorings of the cycle C_n on n vertices with at most k colors.

Examples

			The table begins:
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, ...
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, ...
0, 0, 1, 4, 10, 20, 35, 56, 84, 120, ...
0, 0, 3, 15, 45, 105, 210, 378, 630, 990, ...
0, 0, 12, 72, 252, 672, 1512, 3024, 5544, 9504, ...
0, 1, 37, 266, 1120, 3515, 9121, 20692, 42456, 80565, ...
0, 2, 117, 1044, 5270, 19350, 57627, 147752, 338364, 709290, ...
0, 6, 333, 3788, 23475, 102690, 355446, 1039248, 2673810, 6222150, ...
0, 14, 975, 14056, 106950, 555990, 2233469, 7440160, 21493836, 55505550, ...
0, 30, 2712, 51132, 483504, 3009426, 14089488, 53611992, 174189024, 499720518, ...
------
For n=4, we can color the vertices of the cycle C_4 with at most 3 colors, in 3 ways, such that all the colorings distinguish the graph (i.e., no non-identity automorphism of C_4 preserves the coloring) and that all the three colorings are non-equivalent. The color classes are as follows:
{ { 1 }, { 2 }, { 3, 4 } }
{ { 1 }, { 2, 3 }, { 4 } }
{ { 1, 2 }, { 3 }, { 4 } }
		

Crossrefs

Columns k=2..5 for n >= 3 are A032239, A032240, A032241, A032242.
Different from A293496.

Programs

  • PARI
    A(n,k)={sumdiv(n, d, moebius(n/d)*(k^d/n - if(d%2, k^((d+1)/2), (k+1)*k^(d/2)/2)))/2} \\ Andrew Howroyd, Aug 11 2019

Formula

A(n,k) = (A074650(n,k) - A284856(n,k))/2. - Andrew Howroyd, Aug 11 2019

A056494 Number of primitive (period n) periodic palindromes using a maximum of three different symbols.

Original entry on oeis.org

3, 3, 6, 12, 24, 42, 78, 144, 234, 456, 726, 1392, 2184, 4290, 6528, 12960, 19680, 39078, 59046, 117600, 177060, 353562, 531438, 1061280, 1594296, 3186456, 4782726, 9561552, 14348904, 28690752, 43046718
Offset: 1

Views

Author

Keywords

Comments

For example, aaabbb is not a (finite) palindrome but it is a periodic palindrome.
Number of aperiodic necklaces with three colors that are the same when turned over and hence have reflectional symmetry but no rotational symmetry. - Herbert Kociemba, Nov 29 2016

References

  • M. R. Nester (1999). Mathematical investigations of some plant interaction designs. PhD Thesis. University of Queensland, Brisbane, Australia. [See A056391 for pdf file of Chap. 2]

Crossrefs

Column 3 of A284856.
Cf. A056459.

Programs

  • Mathematica
    mx=40;gf[x_,k_]:=Sum[ MoebiusMu[n]*Sum[Binomial[k,i]x^(n i),{i,0,2}]/( 1-k x^(2n)),{n,mx}]; CoefficientList[Series[gf[x,3],{x,0,mx}],x] (* Herbert Kociemba, Nov 29 2016 *)

Formula

a(n) = Sum_{d|n} mu(d)*A038754(n/d+1).
From Herbert Kociemba, Nov 29 2016: (Start)
More generally, gf(k) is the g.f. for the number of necklaces with reflectional symmetry but no rotational symmetry and beads of k colors.
gf(k): Sum_{n>=1} mu(n)*Sum_{i=0..2} binomial(k,i)x^(n*i)/(1-k*x^(2*n)). (End)

A056495 Number of primitive (period n) periodic palindromes using a maximum of four different symbols.

Original entry on oeis.org

4, 6, 12, 30, 60, 138, 252, 600, 1008, 2490, 4092, 10050, 16380, 40698, 65460, 163200, 262140, 654192, 1048572, 2618850, 4194036, 10481658, 16777212, 41932200, 67108800, 167755770, 268434432, 671047650
Offset: 1

Views

Author

Keywords

Comments

Number of aperiodic necklaces with four colors that are the same when turned over and hence have reflectional symmetry but no rotational symmetry. - Herbert Kociemba, Nov 29 2016

Examples

			For example, aaabbb is not a (finite) palindrome but it is a periodic palindrome.
		

References

  • M. R. Nester (1999). Mathematical investigations of some plant interaction designs. PhD Thesis. University of Queensland, Brisbane, Australia. [See A056391 for pdf file of Chap. 2]

Crossrefs

Column 4 of A284856.
Cf. A056460.

Programs

  • Mathematica
    mx=40;gf[x_,k_]:=Sum[ MoebiusMu[n]*Sum[Binomial[k,i]x^(n i),{i,0,2}]/( 1-k x^(2n)),{n,mx}]; CoefficientList[Series[gf[x,4],{x,0,mx}],x] (* Herbert Kociemba, Nov 29 2016 *)

Formula

a(n) = Sum_{d|n} mu(d)*A056486(n/d).
From Herbert Kociemba, Nov 29 2016: (Start)
More generally, gf(k) is the g.f. for the number of necklaces with reflectional symmetry but no rotational symmetry and beads of k colors.
gf(k): Sum_{n>=1} mu(n)*Sum_{i=0..2} binomial(k,i)x^(n*i)/(1-k*x^(2*n)). (End)

A056496 Number of primitive (period n) periodic palindromes using a maximum of five different symbols.

Original entry on oeis.org

5, 10, 20, 60, 120, 340, 620, 1800, 3100, 9240, 15620, 46440, 78120, 233740, 390480, 1170000, 1953120, 5855900, 9765620, 29287440, 48827480, 146468740, 244140620, 732373200, 1220703000, 3662031240
Offset: 1

Views

Author

Keywords

Comments

Number of aperiodic necklaces with five colors that are the same when turned over and hence have reflectional symmetry but no rotational symmetry. - Herbert Kociemba, Nov 29 2016

Examples

			For example, aaabbb is not a (finite) palindrome but it is a periodic palindrome.
		

References

  • M. R. Nester (1999). Mathematical investigations of some plant interaction designs. PhD Thesis. University of Queensland, Brisbane, Australia. [See A056391 for pdf file of Chap. 2]

Crossrefs

Column 5 of A284856.
Cf. A056461.

Programs

  • Mathematica
    mx=40;gf[x_,k_]:=Sum[ MoebiusMu[n]*Sum[Binomial[k,i]x^(n i),{i,0,2}]/( 1-k x^(2n)),{n,mx}]; CoefficientList[Series[gf[x,5],{x,0,mx}],x] (* Herbert Kociemba, Nov 29 2016 *)

Formula

a(n) = Sum_{d|n} mu(d)*A056487(n/d).
From Herbert Kociemba, Nov 29 2016: (Start)
More generally, gf(k) is the g.f. for the number of necklaces with reflectional symmetry but no rotational symmetry and beads of k colors.
gf(k): Sum_{n>=1} mu(n)*Sum_{i=0..2} binomial(k,i)x^(n*i)/(1-k*x^(2*n)). (End)

A056497 Number of primitive (period n) periodic palindromes using a maximum of six different symbols.

Original entry on oeis.org

6, 15, 30, 105, 210, 705, 1290, 4410, 7740, 26985, 46650, 162435, 279930, 978465, 1679370, 5874120, 10077690, 35263440, 60466170, 211604295, 362795730, 1269743025, 2176782330, 7618570470, 13060693800
Offset: 1

Views

Author

Keywords

Comments

Number of aperiodic necklaces with six colors that are the same when turned over and hence have reflectional symmetry but no rotational symmetry. - Herbert Kociemba, Nov 29 2016

Examples

			For example, aaabbb is not a (finite) palindrome but it is a periodic palindrome.
		

References

  • M. R. Nester (1999). Mathematical investigations of some plant interaction designs. PhD Thesis. University of Queensland, Brisbane, Australia. [See A056391 for pdf file of Chap. 2]

Crossrefs

Column 6 of A284856.
Cf. A056462.

Programs

  • Mathematica
    mx=40;gf[x_,k_]:=Sum[ MoebiusMu[n]*Sum[Binomial[k,i]x^(n i),{i,0,2}]/( 1-k x^(2n)),{n,mx}]; CoefficientList[Series[gf[x,6],{x,0,mx}],x] (* Herbert Kociemba, Nov 29 2016 *)

Formula

a(n) = Sum_{d|n} mu(d)*A056488(n/d).
From Herbert Kociemba, Nov 29 2016: (Start)
More generally, gf(k) is the g.f. for the number of necklaces with reflectional symmetry but no rotational symmetry and beads of k colors.
gf(k): Sum_{n>=1} mu(n)*Sum_{i=0..2} binomial(k,i)x^(n*i)/(1-k*x^(2*n)). (End)
Showing 1-9 of 9 results.