A302784 Inverse permutation to A302783: a(n) = A003188(A052331(n)).
0, 1, 3, 6, 12, 2, 24, 7, 48, 13, 96, 5, 192, 25, 15, 384, 768, 49, 1536, 10, 27, 97, 3072, 4, 6144, 193, 51, 30, 12288, 14, 24576, 385, 99, 769, 20, 54, 49152, 1537, 195, 11, 98304, 26, 196608, 102, 60, 3073, 393216, 387, 786432, 6145, 771, 198, 1572864, 50, 108, 31, 1539, 12289, 3145728, 9, 6291456, 24577, 40, 390, 204, 98, 12582912, 774, 3075, 21
Offset: 1
Keywords
Links
Programs
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PARI
up_to = 4096; v050376 = vector(up_to); ispow2(n) = (n && !bitand(n,n-1)); i = 0; for(n=1,oo,if(ispow2(isprimepower(n)), i++; v050376[i] = n); if(i == up_to,break)); A052331(n) = { my(s=0,e); while(n > 1, fordiv(n, d, if(((n/d)>1)&&ispow2(isprimepower(n/d)), e = vecsearch(v050376, n/d); if(!e, print("v050376 too short!"); return(1/0)); s += 2^(e-1); n = d; break))); (s); }; A003188(n) = bitxor(n, n>>1); A302784(n) = A003188(A052331(n));
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