A326572 Number of covering antichains of subsets of {1..n}, all having different sums.
2, 1, 2, 8, 80, 3015, 803898
Offset: 0
Examples
The a(0) = 2 through a(3) = 8 antichains: {} {{1}} {{1,2}} {{1,2,3}} {{}} {{1},{2}} {{1},{2,3}} {{2},{1,3}} {{1,2},{1,3}} {{1,2},{2,3}} {{1},{2},{3}} {{1,3},{2,3}} {{1,2},{1,3},{2,3}} The a(4) = 80 antichains: {1234} {1}{234} {1}{2}{34} {1}{2}{3}{4} {12}{13}{14}{24}{34} {12}{34} {1}{3}{24} {1}{23}{24}{34} {12}{13}{23}{24}{34} {13}{24} {1}{4}{23} {2}{13}{14}{34} {2}{134} {2}{3}{14} {12}{13}{14}{24} {3}{124} {1}{23}{24} {12}{13}{14}{34} {4}{123} {1}{23}{34} {12}{13}{23}{24} {12}{134} {1}{24}{34} {12}{13}{23}{34} {12}{234} {2}{13}{14} {12}{13}{24}{34} {13}{124} {2}{13}{34} {12}{14}{24}{34} {13}{234} {2}{14}{34} {12}{23}{24}{34} {14}{123} {3}{14}{24} {13}{14}{24}{34} {14}{234} {4}{12}{23} {13}{23}{24}{34} {23}{124} {12}{13}{14} {12}{13}{14}{234} {23}{134} {12}{13}{24} {12}{23}{24}{134} {24}{134} {12}{13}{34} {123}{124}{134}{234} {34}{123} {12}{14}{34} {123}{124} {12}{23}{24} {123}{134} {12}{23}{34} {123}{234} {12}{24}{34} {124}{134} {13}{14}{24} {124}{234} {13}{23}{24} {134}{234} {13}{23}{34} {13}{24}{34} {14}{24}{34} {12}{13}{234} {12}{14}{234} {12}{23}{134} {12}{24}{134} {13}{14}{234} {13}{23}{124} {14}{34}{123} {23}{24}{134} {12}{134}{234} {13}{124}{234} {14}{123}{234} {23}{124}{134} {123}{124}{134} {123}{124}{234} {123}{134}{234} {124}{134}{234}
Crossrefs
Antichain covers are A006126.
Set partitions with different block-sums are A275780.
MM-numbers of multiset partitions with different part-sums are A326535.
Antichain covers with equal edge-sums are A326566.
Antichain covers with different edge-sizes are A326570.
The case without singletons is A326571.
Antichains with equal edge-sums are A326574.
Programs
-
Mathematica
stableSets[u_,Q_]:=If[Length[u]==0,{{}},With[{w=First[u]},Join[stableSets[DeleteCases[u,w],Q],Prepend[#,w]&/@stableSets[DeleteCases[u,r_/;r==w||Q[r,w]||Q[w,r]],Q]]]]; cleq[n_]:=Select[stableSets[Subsets[Range[n]],SubsetQ[#1,#2]||Total[#1]==Total[#2]&],Union@@#==Range[n]&]; Table[Length[cleq[n]],{n,0,5}]
Comments