A364917 For each n, if the sequence defined by G_0 = C_n, G_k = Aut(G_{k-1}) for k >= 1 stabilizes, then a(n) is the order of G_k for sufficiently large k; otherwise a(n) = 0. Here C_n is the cyclic group of order n.
1, 1, 1, 1, 1, 1, 1, 6, 1, 1, 1, 6, 6, 1, 8, 8, 8, 1, 1, 8, 12, 1, 1, 336, 8, 6, 1, 12, 12, 8, 8
Offset: 1
Examples
For n = 24, we have G_0 = C_24, G_1 = C_2 X C_2 X C_2, G_2 = PSL(2,7) and G_k = PGL(2,7) for all k >= 3, hence a(24) = |PGL(2,7)| = 336.
Links
- G. Muller, Does Aut(Aut(...Aut(G)...)) stabilize?, MathOverflow (2009).
- S. Palcoux, On the iterated automorphism groups of the cyclic groups, MathOverflow (2020).
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