cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-4 of 4 results.

A338617 Number of spanning trees in the n X 4 king graph.

Original entry on oeis.org

1, 2304, 1612127, 1064918960, 698512774464, 457753027631164, 299940605530116319, 196531575367664678400, 128774089577828985307985, 84377085408032081020147412, 55286683084713553039968700608, 36225680193828279388607070447232, 23736274839549237072891352060244017
Offset: 1

Views

Author

Seiichi Manyama, Nov 29 2020

Keywords

Crossrefs

Column 4 of A338029.
Cf. A003696.

Programs

  • Python
    # Using graphillion
    from graphillion import GraphSet
    def make_nXk_king_graph(n, k):
        grids = []
        for i in range(1, k + 1):
            for j in range(1, n):
                grids.append((i + (j - 1) * k, i + j * k))
                if i < k:
                    grids.append((i + (j - 1) * k, i + j * k + 1))
                if i > 1:
                    grids.append((i + (j - 1) * k, i + j * k - 1))
        for i in range(1, k * n, k):
            for j in range(1, k):
                grids.append((i + j - 1, i + j))
        return grids
    def A338029(n, k):
        if n == 1 or k == 1: return 1
        universe = make_nXk_king_graph(n, k)
        GraphSet.set_universe(universe)
        spanning_trees = GraphSet.trees(is_spanning=True)
        return spanning_trees.len()
    def A338617(n):
        return A338029(n, 4)
    print([A338617(n) for n in range(1, 20)])

Formula

Empirical g.f.: x*(56*x^7 + 7072*x^6 - 162708*x^5 + 371791*x^4 + 18080*x^3 - 49920*x^2 + 1556*x + 1) / (x^8 - 748*x^7 + 61345*x^6 - 368764*x^5 + 680848*x^4 - 368764*x^3 + 61345*x^2 - 748*x + 1). - Vaclav Kotesovec, Dec 04 2020

A339257 Number of spanning trees in the n X 5 king graph.

Original entry on oeis.org

1, 27648, 146356224, 698512774464, 3271331573452800, 15258885095892902976, 71111090441547013886784, 331335100372867196224868352, 1543757070688065237574186369344, 7192607774929149127350811889484864, 33511424900308657559195109303117533184, 156134620449573478209362729027690283037248
Offset: 1

Views

Author

Seiichi Manyama, Nov 29 2020

Keywords

Crossrefs

Column 5 of A338029.
Cf. A003779.

Programs

  • Python
    # Using graphillion
    from graphillion import GraphSet
    def make_nXk_king_graph(n, k):
        grids = []
        for i in range(1, k + 1):
            for j in range(1, n):
                grids.append((i + (j - 1) * k, i + j * k))
                if i < k:
                    grids.append((i + (j - 1) * k, i + j * k + 1))
                if i > 1:
                    grids.append((i + (j - 1) * k, i + j * k - 1))
        for i in range(1, k * n, k):
            for j in range(1, k):
                grids.append((i + j - 1, i + j))
        return grids
    def A338029(n, k):
        if n == 1 or k == 1: return 1
        universe = make_nXk_king_graph(n, k)
        GraphSet.set_universe(universe)
        spanning_trees = GraphSet.trees(is_spanning=True)
        return spanning_trees.len()
    def A339257(n):
        return A338029(n, 5)
    print([A339257(n) for n in range(1, 15)])

Formula

Empirical g.f.: -x*(218700000000*x^8 - 2040471000000*x^7 + 538526880000*x^6 + 311791396500*x^5 - 17462695797*x^4 - 80280747*x^3 + 10513308*x^2 - 21759*x - 1) / (656100000000*x^8 - 4293081000000*x^7 + 4819127400000*x^6 - 930215250900*x^5 + 51621632181*x^4 - 1033572501*x^3 + 5949540*x^2 - 5889*x + 1). - Vaclav Kotesovec, Dec 09 2020

A338100 Number of spanning trees in the n X 2 king graph.

Original entry on oeis.org

1, 16, 192, 2304, 27648, 331776, 3981312, 47775744, 573308928, 6879707136, 82556485632, 990677827584, 11888133931008, 142657607172096, 1711891286065152, 20542695432781824, 246512345193381888, 2958148142320582656, 35497777707846991872, 425973332494163902464, 5111679989929966829568
Offset: 1

Views

Author

Seiichi Manyama, Nov 29 2020

Keywords

Crossrefs

Column 2 of A338029.

Programs

  • Python
    # Using graphillion
    from graphillion import GraphSet
    def make_nXk_king_graph(n, k):
        grids = []
        for i in range(1, k + 1):
            for j in range(1, n):
                grids.append((i + (j - 1) * k, i + j * k))
                if i < k:
                    grids.append((i + (j - 1) * k, i + j * k + 1))
                if i > 1:
                    grids.append((i + (j - 1) * k, i + j * k - 1))
        for i in range(1, k * n, k):
            for j in range(1, k):
                grids.append((i + j - 1, i + j))
        return grids
    def A338029(n, k):
        if n == 1 or k == 1: return 1
        universe = make_nXk_king_graph(n, k)
        GraphSet.set_universe(universe)
        spanning_trees = GraphSet.trees(is_spanning=True)
        return spanning_trees.len()
    def A338100(n):
        return A338029(n, 2)
    print([A338100(n) for n in range(1, 20)])

Formula

a(n) = 12 * a(n-1) for n > 2.
a(n) = 3^(n-2) * 4^n for n > 1.
G.f.: x*(1 + 4*x)/(1 - 12*x). - Stefano Spezia, Nov 29 2020

A338532 Number of spanning trees in the n X 3 king graph.

Original entry on oeis.org

1, 192, 17745, 1612127, 146356224, 13286470095, 1206167003329, 109497763028928, 9940381426772625, 902403667119137183, 81921642989758089216, 7436977302591050167695, 675140651246077550931841, 61290344237862763973468352, 5564035123440571957929508305, 505111975464406109413779799007
Offset: 1

Views

Author

Seiichi Manyama, Nov 29 2020

Keywords

Crossrefs

Column 3 of A338029.
Cf. A006238.

Programs

  • Python
    # Using graphillion
    from graphillion import GraphSet
    def make_nXk_king_graph(n, k):
        grids = []
        for i in range(1, k + 1):
            for j in range(1, n):
                grids.append((i + (j - 1) * k, i + j * k))
                if i < k:
                    grids.append((i + (j - 1) * k, i + j * k + 1))
                if i > 1:
                    grids.append((i + (j - 1) * k, i + j * k - 1))
        for i in range(1, k * n, k):
            for j in range(1, k):
                grids.append((i + j - 1, i + j))
        return grids
    def A338029(n, k):
        if n == 1 or k == 1: return 1
        universe = make_nXk_king_graph(n, k)
        GraphSet.set_universe(universe)
        spanning_trees = GraphSet.trees(is_spanning=True)
        return spanning_trees.len()
    def A338532(n):
        return A338029(n, 3)
    print([A338532(n) for n in range(1, 20)])

Formula

Empirical g.f.: x*(-15*x^3 - 111*x^2 + 97*x + 1) / (x^4 - 95*x^3 + 384*x^2 - 95*x + 1). - Vaclav Kotesovec, Dec 04 2020
Showing 1-4 of 4 results.