cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-6 of 6 results.

A347392 Numbers k such that nearest common ancestor of k and sigma(k) in Doudna tree (A347879) is the grandparent of k.

Original entry on oeis.org

8, 9, 12, 13, 24, 35, 160, 455, 42550, 127650, 8041950, 22469750, 58506250, 67409250, 175518750, 394055550, 4246782750
Offset: 1

Views

Author

Antti Karttunen, Aug 30 2021

Keywords

Comments

Note how 13 * 35 = 455.
If there exists any odd perfect numbers x, with sigma(x) = 2x, then 2*x would be a term of this sequence, as then sigma(2*x) = 6*x would be situated as a descendant under the other branch of the grandparent of 2*x (a parent of x), which is m = A064989(x), with m in A005101. Opn x itself would be a term of A336702. Furthermore, if such x is not a multiple of 3 (in which case m is odd and in A005231), then also 3x would be a term of this sequence as sigma(3*x) = 4*sigma(x) = 8*x would be situated as a grandchild of 2x, with 2x being a first cousin of 3x. Also, in that case, 6*x would be located in A336702 (particularly, in A027687) because then sigma(6*x) = 12*sigma(x) = 24*x = 4*(6*x).
.
<--A003961-- m ---(*2)--->
.............../ \...............
/ \
/ \
/ \
x 2m
etc..../ \......2x = sigma(x) 3x....../ \......4m
/ \ / \ / \
etc. \ etc. \ etc. etc.
\ \
4x sigma(2x) = 6x
/ \ / \
etc \ etc. \
\ \
8x = sigma(3x) 12x
if m odd \
\
24x = sigma(6x) if m odd.
.
Furthermore, if there were any hypothetical odd terms y in A005820 (triperfect numbers), then 2y would be a term of this sequence. See the diagram in A347391.
If it exists, a(18) > 2^33.

Examples

			455 is included in the sequence as sigma(455) = 672, and the nearest common ancestor of 455 and 672 in Doudna tree is 42, which is the grandparent of 455 [as 455 = A003961(A003961(42))] and the grand-grand-grand-parent of 672 [as 672 = (2^4)*42].
		

Crossrefs

Programs

A356158 a(n) = gcd(n, A347879(n)).

Original entry on oeis.org

1, 2, 1, 2, 1, 6, 1, 2, 1, 2, 1, 3, 1, 1, 3, 2, 1, 2, 1, 10, 1, 2, 1, 6, 1, 1, 1, 28, 1, 2, 1, 2, 3, 2, 1, 2, 1, 1, 1, 1, 1, 3, 1, 1, 3, 2, 1, 3, 1, 2, 1, 2, 1, 2, 1, 1, 1, 1, 1, 3, 1, 1, 1, 2, 5, 2, 1, 1, 3, 2, 1, 2, 1, 1, 1, 1, 1, 1, 1, 5, 1, 1, 1, 1, 1, 1, 3, 1, 1, 3, 1, 1, 1, 2, 1, 3, 1, 2, 1, 2, 1, 2, 1, 1, 3
Offset: 1

Views

Author

Antti Karttunen, Jul 30 2022

Keywords

Comments

The fixed points of this sequence is given by the union of {2} and A336702.

Crossrefs

Programs

  • PARI
    Abincompreflen(n, m) = { my(x=binary(n),y=binary(m),u=min(#x,#y)); for(i=1,u,if(x[i]!=y[i],return(i-1))); (u);};
    Abinprefix(n,k) = { my(digs=binary(n)); fromdigits(vector(k,i,digs[i]),2); };
    A005940(n) = { my(p=2, t=1); n--; until(!n\=2, if((n%2), (t*=p), p=nextprime(p+1))); (t); };
    A156552(n) = {my(f = factor(n), p, p2 = 1, res = 0); for(i = 1, #f~, p = 1 << (primepi(f[i, 1]) - 1); res += (p * p2 * (2^(f[i, 2]) - 1)); p2 <<= f[i, 2]); res}; \\ From A156552
    A348040sq(x,y) = Abincompreflen(A156552(x), A156552(y));
    A348041sq(x,y) = A005940(1+Abinprefix(A156552(x),A348040sq(x,y)));
    A347879(n) = A348041sq(n,sigma(n));
    A356158(n) = gcd(n, A347879(n));

Formula

a(n) = gcd(n, A347879(n)).

A348041 Square array read by antidiagonals. A(n,k) is the nearest common ancestor of n and k in the Doudna tree (A005940).

Original entry on oeis.org

1, 1, 1, 1, 2, 1, 1, 2, 2, 1, 1, 2, 3, 2, 1, 1, 2, 2, 2, 2, 1, 1, 2, 3, 4, 3, 2, 1, 1, 2, 3, 2, 2, 3, 2, 1, 1, 2, 3, 2, 5, 2, 3, 2, 1, 1, 2, 2, 2, 3, 3, 2, 2, 2, 1, 1, 2, 2, 4, 5, 6, 5, 4, 2, 2, 1, 1, 2, 3, 4, 2, 3, 3, 2, 4, 3, 2, 1, 1, 2, 3, 2, 2, 2, 7, 2, 2, 2, 3, 2, 1, 1, 2, 3, 2, 5, 2, 2, 2, 2, 5, 2, 3, 2, 1
Offset: 1

Views

Author

Antti Karttunen and Peter Munn, Sep 27 2021

Keywords

Comments

Array is symmetric and is read by antidiagonals as A(1,1), A(1,2), A(2,1), A(1,3), A(2,2), A(3,1), ... .
Also the nearest common ancestor of n and k in the tree depicted in A163511 (the mirror image of the Doudna tree).
The first fork in the Doudna tree separates numbers divisible by the square of their largest prime factor (on one main branch) from other numbers greater than 2 (on the other main branch). If n and m are on different main branches then A(n, m) = 2.
In more general terms A(.,.) can be considered as a binary operation that evaluates certain differences between the prime factors of its operands. To start, compare the largest prime factor of each operand with the 2nd largest prime factor. As described above, 2 is the result if these 2 factors are the same in one operand, but are different in the other operand; otherwise 3 is the result if these 2 factors are consecutive primes in one operand, but are nonconsecutive primes in the other operand. Further cases are covered in the examples, but note it is the difference between the indices of the prime numbers that is significant.

Examples

			The top left 17x17 corner of the array:
  n/k |  1  2  3  4  5  6  7  8  9  10  11  12  13  14  15  16  17
------+-------------------------------------------------------------
    1 |  1, 1, 1, 1, 1, 1, 1, 1, 1,  1,  1,  1,  1,  1,  1,  1,  1,
    2 |  1, 2, 2, 2, 2, 2, 2, 2, 2,  2,  2,  2,  2,  2,  2,  2,  2,
    3 |  1, 2, 3, 2, 3, 3, 3, 2, 2,  3,  3,  3,  3,  3,  3,  2,  3,
    4 |  1, 2, 2, 4, 2, 2, 2, 4, 4,  2,  2,  2,  2,  2,  2,  4,  2,
    5 |  1, 2, 3, 2, 5, 3, 5, 2, 2,  5,  5,  3,  5,  5,  3,  2,  5,
    6 |  1, 2, 3, 2, 3, 6, 3, 2, 2,  3,  3,  6,  3,  3,  6,  2,  3,
    7 |  1, 2, 3, 2, 5, 3, 7, 2, 2,  5,  7,  3,  7,  7,  3,  2,  7,
    8 |  1, 2, 2, 4, 2, 2, 2, 8, 4,  2,  2,  2,  2,  2,  2,  8,  2,
    9 |  1, 2, 2, 4, 2, 2, 2, 4, 9,  2,  2,  2,  2,  2,  2,  4,  2,
   10 |  1, 2, 3, 2, 5, 3, 5, 2, 2, 10,  5,  3,  5,  5,  3,  2,  5,
   11 |  1, 2, 3, 2, 5, 3, 7, 2, 2,  5, 11,  3, 11,  7,  3,  2, 11,
   12 |  1, 2, 3, 2, 3, 6, 3, 2, 2,  3,  3, 12,  3,  3,  6,  2,  3,
   13 |  1, 2, 3, 2, 5, 3, 7, 2, 2,  5, 11,  3, 13,  7,  3,  2, 13,
   14 |  1, 2, 3, 2, 5, 3, 7, 2, 2,  5,  7,  3,  7, 14,  3,  2,  7,
   15 |  1, 2, 3, 2, 3, 6, 3, 2, 2,  3,  3,  6,  3,  3, 15,  2,  3,
   16 |  1, 2, 2, 4, 2, 2, 2, 8, 4,  2,  2,  2,  2,  2,  2, 16,  2,
   17 |  1, 2, 3, 2, 5, 3, 7, 2, 2,  5, 11,  3, 13,  7,  3,  2, 17,
.
The nearest common ancestor of 7 and 15 in the Doudna tree (see diagram in the links and A005940) is 3, thus A(7,15) = A(15,7) = 3.
The nearest common ancestor of 12 and 15 in the Doudna tree is 6, thus A(12,15) = A(15,12) = 6.
The nearest common ancestor of 4 and 27 is 4 because 27 is a descendant of 4 in the Doudna tree, thus A(4,27) = A(27,4) = 4.
Example without reference to the Doudna tree: (Start)
The method below works in general for A(.,.) considered as a binary operation, but we use A(20, 42) as our example.
(1) Write each operand as a product of primes in nondecreasing order, convert to a tuple of prime indices, decrement each index, take first differences, then reverse the order:
  20 = 2*2*5 = prime(1) * prime(1) * prime(3) -> (1,1,3) -> (0,0,2) -> (0,0,2) -> (2,0,0);
  42 = 2*3*7 = prime(1) * prime(2) * prime(4) -> (1,2,4) -> (0,1,3) -> (0,1,2) -> (2,1,0).
(2) Truncate each tuple after the first elements that differ between them (or at the length of the shorter tuple):
  (2,0,0) -> (2,0); (2,1,0) -> (2,1).
(3) Choose the lesser tuple: (2,0).
(4) Determine which number would generate this tuple by the process from step (1):
  10 = 2*5 = prime(1) * prime(3) -> (1,3) -> (0,2) -> (0,2) -> (2,0).
This gives A(20, 42) = 10.
(End)
		

Crossrefs

Cf. A000027 (main diagonal).
Cf. also A341510, A347380, A347381.

Programs

  • PARI
    up_to = 105;
    Abincompreflen(n, m) = { my(x=binary(n),y=binary(m),u=min(#x,#y)); for(i=1,u,if(x[i]!=y[i],return(i-1))); (u);};
    Abinprefix(n,k) = { my(digs=binary(n)); fromdigits(vector(k,i,digs[i]),2); };
    A005940(n) = { my(p=2, t=1); n--; until(!n\=2, if((n%2), (t*=p), p=nextprime(p+1))); (t); };
    A156552(n) = {my(f = factor(n), p, p2 = 1, res = 0); for(i = 1, #f~, p = 1 << (primepi(f[i, 1]) - 1); res += (p * p2 * (2^(f[i, 2]) - 1)); p2 <<= f[i, 2]); res}; \\ From A156552
    A348040sq(x,y) = Abincompreflen(A156552(x), A156552(y));
    A348041sq(x,y) = A005940(1+Abinprefix(A156552(x),A348040sq(x,y)));
    A348041list(up_to) = { my(v = vector(up_to), i=0); for(a=1,oo, for(col=1,a, i++; if(i > up_to, return(v)); v[i] = A348041sq(col,(a-(col-1))))); (v); };
    v348041 = A348041list(up_to);
    A348041(n) = v348041[n];
    
  • PARI
    \\ A348041sq can be defined also as:
    A064989(n) = {my(f); f = factor(n); if((n>1 && f[1,1]==2), f[1,2] = 0); for (i=1, #f~, f[i,1] = precprime(f[i,1]-1)); factorback(f)};
    A252463(n) = if(!(n%2),n/2,A064989(n));
    A348041sq(x,y) = if(1==x||1==y,1, my(lista=List([]), i, k=x, stemvec, h=y); while(k>1, listput(lista,k); k = A252463(k)); stemvec = Vecrev(Vec(lista)); while(1, if((i=vecsearch(stemvec,h))>0, return(stemvec[i])); h = A252463(h)));

Formula

A(n, 1) = A(1, n) = 1; otherwise if A241917(n) <> A241917(m) then A(n, m) = A000040(1 + min(A241917(2*n), A241917(2*m))); otherwise A(n, m) = x * A000040(A061395(x)+A241917(n)), where x = A(A052126(n), A052126(m)).
A(i, j) = A(j, i).
A(n, n) = n.
A(2, n) = 2 for all n > 1.
A(p, q) = min(p, q) for any primes p and q.
A(A070003(n), A102750(m)) = 2.
A(u^2, v^2) = A(u, v)^2.
A(4k+2, 6k+3) = A064989(2k+1) for all k >= 1.

A356156 The nearest common ancestor of n and gcd(n, sigma(n)) in the Doudna tree (A005940).

Original entry on oeis.org

1, 1, 1, 1, 1, 6, 1, 1, 1, 2, 1, 2, 1, 2, 3, 1, 1, 2, 1, 2, 1, 2, 1, 12, 1, 2, 1, 28, 1, 6, 1, 1, 3, 2, 1, 1, 1, 2, 1, 10, 1, 3, 1, 2, 3, 2, 1, 2, 1, 1, 3, 2, 1, 2, 1, 2, 1, 2, 1, 6, 1, 2, 1, 1, 1, 3, 1, 2, 3, 2, 1, 2, 1, 2, 1, 2, 1, 3, 1, 2, 1, 2, 1, 5, 1, 2, 3, 2, 1, 2, 5, 2, 1, 2, 5, 12, 1, 1, 3, 1, 1, 3, 1, 2, 3
Offset: 1

Views

Author

Antti Karttunen, Jul 30 2022

Keywords

Crossrefs

Cf. A000203, A007691 (fixed points), A009194, A348040, A348041.

Programs

  • PARI
    Abincompreflen(n, m) = { my(x=binary(n),y=binary(m),u=min(#x,#y)); for(i=1,u,if(x[i]!=y[i],return(i-1))); (u);};
    Abinprefix(n,k) = { my(digs=binary(n)); fromdigits(vector(k,i,digs[i]),2); };
    A005940(n) = { my(p=2, t=1); n--; until(!n\=2, if((n%2), (t*=p), p=nextprime(p+1))); (t); };
    A156552(n) = {my(f = factor(n), p, p2 = 1, res = 0); for(i = 1, #f~, p = 1 << (primepi(f[i, 1]) - 1); res += (p * p2 * (2^(f[i, 2]) - 1)); p2 <<= f[i, 2]); res}; \\ From A156552
    A348040sq(x,y) = Abincompreflen(A156552(x), A156552(y));
    A348041sq(x,y) = A005940(1+Abinprefix(A156552(x),A348040sq(x,y)));
    A356156(n) = A348041sq(n,gcd(n, sigma(n)));

Formula

a(n) = A348041(n, A009194(n)) = A348041(n, gcd(n, A000203(n))).

A356157 The nearest common ancestor of sigma(n) and gcd(n, sigma(n)) in the Doudna tree (A005940).

Original entry on oeis.org

1, 1, 1, 1, 1, 6, 1, 1, 1, 2, 1, 2, 1, 2, 3, 1, 1, 3, 1, 2, 1, 2, 1, 6, 1, 2, 1, 28, 1, 2, 1, 1, 3, 2, 1, 1, 1, 2, 1, 3, 1, 6, 1, 2, 3, 2, 1, 2, 1, 1, 2, 2, 1, 6, 1, 2, 1, 2, 1, 3, 1, 2, 1, 1, 1, 2, 1, 2, 3, 2, 1, 3, 1, 2, 1, 2, 1, 3, 1, 2, 1, 2, 1, 28, 1, 2, 3, 2, 1, 2, 7, 2, 1, 2, 3, 3, 1, 1, 3, 1, 1, 2, 1, 2, 3
Offset: 1

Views

Author

Antti Karttunen, Jul 30 2022

Keywords

Crossrefs

Cf. A000203, A009194, A336702 (fixed points), A348040, A348041.
Cf. also A347879, A356156, A356307.

Programs

  • PARI
    Abincompreflen(n, m) = { my(x=binary(n),y=binary(m),u=min(#x,#y)); for(i=1,u,if(x[i]!=y[i],return(i-1))); (u);};
    Abinprefix(n,k) = { my(digs=binary(n)); fromdigits(vector(k,i,digs[i]),2); };
    A005940(n) = { my(p=2, t=1); n--; until(!n\=2, if((n%2), (t*=p), p=nextprime(p+1))); (t); };
    A156552(n) = {my(f = factor(n), p, p2 = 1, res = 0); for(i = 1, #f~, p = 1 << (primepi(f[i, 1]) - 1); res += (p * p2 * (2^(f[i, 2]) - 1)); p2 <<= f[i, 2]); res}; \\ From A156552
    A348040sq(x,y) = Abincompreflen(A156552(x), A156552(y));
    A348041sq(x,y) = A005940(1+Abinprefix(A156552(x),A348040sq(x,y)));
    A356157(n) = A348041sq(sigma(n),gcd(n, sigma(n)));

A356301 The nearest common ancestor of A000265(sigma(n)) and A000265(n) in the tree depicted in A253563.

Original entry on oeis.org

1, 1, 1, 1, 3, 3, 1, 1, 3, 3, 3, 3, 7, 3, 3, 1, 3, 9, 5, 3, 1, 3, 3, 3, 5, 3, 3, 7, 3, 9, 1, 1, 3, 3, 3, 3, 19, 3, 3, 3, 3, 3, 11, 3, 9, 3, 3, 3, 3, 3, 9, 7, 3, 9, 3, 3, 3, 3, 3, 15, 31, 3, 3, 1, 3, 9, 17, 3, 3, 3, 3, 9, 37, 3, 3, 5, 3, 21, 5, 3, 3, 3, 3, 3, 3, 3, 15, 3, 3, 45, 7, 3, 1, 3, 3, 3, 7, 3, 9, 5, 3, 9, 13, 3, 3
Offset: 1

Views

Author

Antti Karttunen, Aug 03 2022

Keywords

Crossrefs

Cf. also A347879.
Positions of 1's in this sequence is given by the union of A000079 and A046528.

Programs

  • PARI
    A000265(n) = (n>>valuation(n,2));
    A161942(n) = A000265(sigma(n));
    A253553(n) = if(n<=2,1,my(f=factor(n), k=#f~); if(f[k,2]>1,f[k,2]--,f[k,1] = precprime(f[k,1]-1)); factorback(f));
    A356300sq(x,y) = if(1==x||1==y,1, my(lista=List([]), i, k=x, stemvec, stemlen, h=y); while(k>1, listput(lista,k); k = A253553(k)); stemvec = Vecrev(Vec(lista)); stemlen = #stemvec; while(1, if((i=vecsearch(stemvec,h))>0, return(stemvec[i])); h = A253553(h)));
    A356301(n) = A356300sq(A161942(n),A000265(n));

Formula

a(n) = A356300(A161942(n), A000265(n)).
Showing 1-6 of 6 results.