A366605 Number of distinct prime divisors of 4^n + 1.
1, 1, 1, 2, 1, 2, 2, 3, 1, 4, 2, 3, 3, 4, 2, 5, 2, 4, 4, 4, 2, 6, 3, 5, 3, 5, 3, 6, 3, 3, 4, 5, 2, 6, 3, 6, 5, 5, 4, 9, 3, 5, 5, 5, 4, 10, 2, 4, 3, 6, 6, 9, 2, 4, 6, 6, 5, 8, 3, 7, 6, 6, 4, 10, 2, 9, 7, 6, 4, 8, 4, 6, 7, 5, 2, 12, 4, 9, 5, 4, 4, 10, 4, 6, 8, 10
Offset: 0
Keywords
Links
- Max Alekseyev, Table of n, a(n) for n = 0..583
Crossrefs
Programs
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Mathematica
PrimeNu[4^Range[0,100]+1] (* Paolo Xausa, Oct 14 2023 *)
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PARI
for(n = 0, 100, print1(omega(4^n + 1), ", "))
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Python
from sympy import primenu def A366605(n): return primenu((1<<(n<<1))+1) # Chai Wah Wu, Oct 14 2023
Formula
a(n) = A046799(2*n). - Max Alekseyev, Jan 08 2024
Comments