cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A231865 Numbers n such that (43^n + 1)/44 is prime.

Original entry on oeis.org

5, 7, 19, 251, 277, 383, 503, 3019, 4517, 9967, 29573
Offset: 1

Views

Author

Robert Price, Nov 14 2013

Keywords

Comments

All terms are primes.
a(11) > 10^5.

Crossrefs

Programs

  • Mathematica
    Do[ p=Prime[n]; If[ PrimeQ[ (43^p + 1)/44 ], Print[p] ], {n, 1, 9592} ]
  • PARI
    is(n)=ispseudoprime((43^n+1)/44) \\ Charles R Greathouse IV, Feb 20 2017

A235683 Numbers n such that (46^n + 1)/47 is prime.

Original entry on oeis.org

7, 23, 59, 71, 107, 223, 331, 2207, 6841, 94841
Offset: 1

Views

Author

Robert Price, Jan 13 2014

Keywords

Comments

All terms up to a(10) are primes.
a(11) > 10^5.

Crossrefs

Programs

  • Mathematica
    Do[ p=Prime[n]; If[ PrimeQ[ (46^p + 1)/47 ], Print[p] ], {n, 1, 9592} ]
  • PARI
    is(n)=ispseudoprime((46^n+1)/47) \\ Charles R Greathouse IV, May 22 2017

A237052 Numbers n such that (49^n + 1)/50 is prime.

Original entry on oeis.org

7, 19, 37, 83, 1481, 12527, 20149
Offset: 1

Views

Author

Robert Price, Feb 02 2014

Keywords

Comments

All terms are primes.
a(8) > 10^5.

Crossrefs

Programs

  • Mathematica
    Do[ p=Prime[n]; If[ PrimeQ[ (49^p + 1)/50 ], Print[p] ], {n, 1, 9592} ]
  • PARI
    is(n)=ispseudoprime((49^n+1)/50) \\ Charles R Greathouse IV, Jun 13 2017

Extensions

Typo in description corrected by Ray Chandler, Feb 20 2017

A283657 Numbers m such that 2^m + 1 has at most 2 distinct prime factors.

Original entry on oeis.org

0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 16, 17, 19, 20, 23, 28, 31, 32, 40, 43, 61, 64, 79, 92, 101, 104, 127, 128, 148, 167, 191, 199, 256, 313, 347, 356, 596, 692, 701, 1004, 1228, 1268, 1709, 2617, 3539, 3824, 5807, 10501, 10691, 11279, 12391, 14479
Offset: 1

Views

Author

Vladimir Shevelev, Mar 13 2017

Keywords

Comments

Using comment in A283364, note that if a(n) is odd > 9, then it is prime.
503 <= a(41) <= 596. - Robert Israel, Mar 13 2017
Could (4^p + 1)/5^t be prime, where p is prime, 5^t is the highest power of 5 dividing 4^p + 1, other than for p=2, 3 and 5? - Vladimir Shevelev, Mar 14 2017
In his message to seqfans from Mar 15 2017, Jack Brennen beautifully proved that there are no more primes of such form. From his proof one can see also that there are no terms of the form 2*p > 10 in the sequence. - Vladimir Shevelev, Mar 15 2017
Where A046799(n)=2. - Robert G. Wilson v, Mar 15 2017
From Giuseppe Coppoletta, May 16 2017: (Start)
The only terms that are not in A066263 are those m giving 2^m + 1 = prime (i.e. m = 0 and any number m such that 2^m + 1 is a Fermat prime) and the values of m giving 2^m + 1 = power of a prime, giving m = 3 as the only possible case (by Mihăilescu-Catalan's result, see links).
For the relation with Fermat numbers and for other possible terms to check, see comments in A073936 and A066263.
All terms after a(59) refer to probabilistic primality tests for 2^a(n) + 1 (see Caldwell's link for the list of the largest certified Wagstaff primes).
After a(65), the values 267017, 269987, 374321, 986191, 4031399 and 4101572 are also terms, but there still remains the remote possibility of some gaps in between. In addition, 13347311 and 13372531 are also terms, but possibly much further along in the numbering (see comments in A000978).
(End).

Examples

			0 is a term as 2^0 + 1 = 2 is a prime.
10 is a term as 2^10 + 1 = 5^2 * 41.
14 is not a term as 2^14 + 1 = 5 * 29 * 113.
		

Crossrefs

Programs

  • Maple
    # this uses A002587[i] for i<=500, e.g., from the b-file for that sequence
    count:= 0:
    for i from 0 to 500 do
      m:= 0;
      r:= (2^i+1);
      if i::odd then
        m:= 1;
        r:= r/3^padic:-ordp(r,3);
      elif i > 2 then
        q:= max(numtheory:-factorset(i));
        if q > 2 then
          m:= 1;
          r:= r/B[i/q]^padic:-ordp(r,A002587[i/q]);
        fi
      fi;
      if r mod B[i] = 0 then m:= m+1;
          j:= padic:-ordp(r, A002587[i]);
          r:= r/B[i]^j;
      fi;
      mmax:= m;
      if isprime(r) then m:= m+1; mmax:= m
      elif r > 1 then mmax:= m+2
      fi;
      if mmax <= 2 or (m <= 1 and m + nops(numtheory:-factorset(r)) <= 2) then
           count:= count+1;
         A[count]:= i;
      fi
    od:
    seq(A[i],i=1..count); # Robert Israel, Mar 13 2017
  • Mathematica
    Select[Range[0, 313], PrimeNu[2^# + 1]<3 &] (* Indranil Ghosh, Mar 13 2017 *)
  • PARI
    for(n=0, 313, if(omega(2^n + 1)<3, print1(n,", "))) \\ Indranil Ghosh, Mar 13 2017

Extensions

a(16)-a(38) from Peter J. C. Moses, Mar 13 2017
a(39)-a(40) from Robert Israel, Mar 13 2017
a(41)-a(65) from Giuseppe Coppoletta, May 08 2017

A309533 Numbers k such that (144^k + 1)/145 is prime.

Original entry on oeis.org

23, 41, 317, 3371, 45259, 119671
Offset: 1

Views

Author

Paul Bourdelais, Aug 06 2019

Keywords

Comments

The corresponding primes are terms of A059055. - Bernard Schott, Aug 09 2019

Crossrefs

Programs

  • Mathematica
    Do[p=Prime[n]; If[PrimeQ[(144^p + 1)/145], Print[p]], {n, 1, 1000000}]
  • PARI
    is(n)=ispseudoprime((144^n+1)/145)

A236167 Numbers k such that (47^k + 1)/48 is prime.

Original entry on oeis.org

5, 19, 23, 79, 1783, 7681
Offset: 1

Views

Author

Robert Price, Jan 19 2014

Keywords

Comments

a(7) > 10^5.

Crossrefs

Programs

  • Mathematica
    Do[ p=Prime[n]; If[ PrimeQ[ (47^p + 1)/48 ], Print[p] ], {n, 1, 9592} ]
  • PARI
    is(n)=ispseudoprime((47^n+1)/48) \\ Charles R Greathouse IV, Jun 06 2017
    
  • Python
    from sympy import isprime
    def afind(startat=0, limit=10**9):
      pow47 = 47**startat
      for k in range(startat, limit+1):
        q, r = divmod(pow47+1, 48)
        if r == 0 and isprime(q): print(k, end=", ")
        pow47 *= 47
    afind(limit=300) # Michael S. Branicky, May 19 2021

A185230 Numbers n such that (33^n + 1)/34 is prime.

Original entry on oeis.org

5, 67, 157, 12211, 313553
Offset: 1

Views

Author

Robert Price, Aug 29 2013

Keywords

Comments

All terms are prime.
a(5) > 10^5.

Crossrefs

Programs

  • Mathematica
    Do[ p=Prime[n]; If[ PrimeQ[ (33^p + 1)/34 ], Print[p] ], {n, 1, 9592} ]
  • PARI
    is(n)=ispseudoprime((33^n+1)/34) \\ Charles R Greathouse IV, Jun 13 2017

Extensions

a(5) from Paul Bourdelais, Feb 26 2021

A195439 Numbers n such that 16^n + 1 is a semiprime.

Original entry on oeis.org

3, 5, 7, 8, 10, 16, 23, 26, 32, 37, 64, 89, 149, 173, 251, 307, 317, 956, 30197, 46058
Offset: 1

Views

Author

Arkadiusz Wesolowski, Oct 19 2011

Keywords

Crossrefs

Programs

  • Mathematica
    Select[Range[37], PrimeOmega[16^# + 1] == 2 &] (* Arkadiusz Wesolowski, Dec 15 2011 *)

A236530 Numbers n such that (48^n + 1)/49 is prime.

Original entry on oeis.org

5, 17, 131, 84589
Offset: 1

Views

Author

Robert Price, Jan 27 2014

Keywords

Comments

All terms are primes.
a(5) > 10^5.

Crossrefs

Programs

  • Mathematica
    Do[ p=Prime[n]; If[ PrimeQ[ (48^p + 1)/49 ], Print[p] ], {n, 1, 9592} ]
  • PARI
    is(n)=ispseudoprime((48^n+1)/49) \\ Charles R Greathouse IV, Jun 13 2017

Extensions

Incorrect first term deleted by Robert Price, Feb 21 2014

A347138 Numbers k such that (100^k + 1)/101 is prime.

Original entry on oeis.org

3, 293, 461, 11867, 90089
Offset: 1

Views

Author

Paul Bourdelais, Aug 19 2021

Keywords

Comments

These are the repunit primes in base -100. It is unusual to represent numbers in a negative base, but it follows the same formulation as any base: numbers are represented as a sum of powers in that base, i.e., a0*1 + a1*b^1 + a2*b^2 + a3*b^3 ... Since the base is negative, the terms will be alternating positive/negative. For repunits the coefficients are all ones so the sum reduces to 1 + b + b^2 + b^3 + ... + b^(k-1) = (b^k-1)/(b-1). Since b is negative and k is an odd prime, the sum equals (|b|^k+1)/(|b|+1). For k=3, the sum is 9901, which is prime. As with all repunits, we only need to PRP test the prime exponents. The factors of repunits base -100 will be of the form p=2*k*m+1 where m must be even, which is common for (negative) bases that are squares.

Examples

			3 is a term since (100^3 + 1)/101 = 9901 is a prime.
		

Crossrefs

Programs

  • Mathematica
    Do[ If[ PrimeQ[ (100^n + 1)/101], Print[n]], {n, 0, 18000}]
  • PARI
    is(n)=isprime((100^n+1)/101)
Previous Showing 11-20 of 22 results. Next