cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A324975 Rank of the n-th Carmichael number.

Original entry on oeis.org

6, 10, 12, 8, 8, 10, 6, 6, 8, 18, 52, 12, 12, 18, 98, 164, 22, 6, 50, 8, 96, 34, 52, 46, 52, 6, 6, 156, 20, 46, 36, 32, 16, 8, 304, 36, 20, 36, 10, 316, 76, 468, 8, 30, 24, 1580, 84, 54, 8, 12, 250, 28, 92, 36, 20, 418, 456, 928, 188, 16, 8, 276, 284, 56, 144
Offset: 1

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Author

Keywords

Comments

See A324974 for definition and explanation of rank of a special polygonal number, hence of rank of a Carmichael number A002997 by Kellner and Sondow 2019.
The ranks of the primary Carmichael numbers A324316 form the subsequence A324976.

Examples

			If m = A002997(1) = 561 = 3*11*17, then p = 17, so a(1) = 2+2*((561/17)-1)/(17-1) = 6.
		

Crossrefs

Subsequence of A324974.
A324976 is a subsequence.

Programs

  • Mathematica
    T = Cases[Range[1, 10000000, 2], n_ /; Mod[n, CarmichaelLambda[n]] == 1 && ! PrimeQ[n]];
    GPF[n_] := Last[Select[Divisors[n], PrimeQ]];
    Table[2 + 2*(T[[i]]/GPF[T[[i]]] - 1)/(GPF[T[[i]]] - 1), {i, Length[T]}]

Formula

a(n) = 2+2*((m/p)-1)/(p-1), where m = A002997(n) and p is its greatest prime factor. (See Formula in A324974.) Hence a(n) is even, by Carmichael's theorem that p-1 divides (m/p)-1, for any prime factor p of a Carmichael number m.

A324976 Rank of the n-th primary Carmichael number.

Original entry on oeis.org

12, 8, 18, 12, 52, 52, 20, 32, 16, 54, 8, 36, 124, 34, 12, 72, 96, 26, 28, 76, 98, 1804, 108, 124, 18, 72, 172, 120, 10, 104, 32, 244, 130, 376, 18, 92, 780, 36, 172, 92, 284, 24, 198, 12, 244, 64, 234, 340, 100, 284, 24, 124, 44, 518, 364, 16, 82, 148, 8, 206
Offset: 1

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Author

Keywords

Comments

See A324974 for definition and explanation of rank of a special polygonal number, hence of rank of a primary Carmichael number A324316 by Kellner and Sondow 2019.

Examples

			If m = A324316(1) = 1729 = 7*13*19, then p = 19, so a(1) = 2+2*((1729/19)-1)/(19-1) = 12.
		

Crossrefs

Subsequence of A324975 (rank of the n-th Carmichael number A002997) and of A324974 (rank of the n-th special polygonal number A324973).
Cf. also A324316, A324972.

Programs

  • Mathematica
    SD[n_, p_] := If[n < 1 || p < 2, 0, Plus @@ IntegerDigits[n, p]];
    LP[n_] := Transpose[FactorInteger[n]][[1]];
    TestCP[n_] := (n > 1) && SquareFreeQ[n] && VectorQ[LP[n], SD[n, #] == # &];
    T = Select[Range[1, 10^7, 2], TestCP[#] &];
    GPF[n_] := Last[Select[Divisors[n], PrimeQ]];
    Table[2 + 2*(T[[i]]/GPF[T[[i]]] - 1)/(GPF[T[[i]]] - 1), {i, Length[T]}]

Formula

a(n) = 2+2*((m/p)-1)/(p-1), where m = A324316(n) and p is its greatest prime factor. Hence a(n) is even; see Formula in A324975.

Extensions

More terms from Amiram Eldar, Mar 27 2019

A324857 Numbers m > 1 such that there exists a prime divisor p of m with s_p(m) = p.

Original entry on oeis.org

6, 10, 12, 15, 18, 20, 21, 24, 33, 34, 36, 39, 40, 45, 48, 57, 63, 65, 66, 68, 72, 80, 85, 87, 91, 93, 96, 99, 105, 111, 117, 130, 132, 133, 135, 136, 144, 145, 160, 165, 171, 175, 185, 189, 192, 205, 217, 225, 231, 249, 255, 258, 259, 260, 261, 264, 265, 272, 273, 279, 285, 288, 297, 301, 305, 320, 325, 327, 333, 341, 351, 384, 385
Offset: 1

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Author

Jonathan Sondow, Mar 17 2019

Keywords

Comments

The function s_p(m) gives the sum of the base-p digits of m.
m must have at least 2 prime factors, since s_p(p^k) = 1 < p.
The sequence contains the primary Carmichael numbers A324316.
The main entry for this sequence is A324456 = numbers m > 1 such that there exists a divisor d > 1 of m with s_d(m) = d. It appears that d is usually prime: compare the sparser sequence A324858 = numbers m > 1 such that there exists a composite divisor c of m with s_c(m) = c. However, d is usually composite for higher values of m.
The sequence contains the 3-Carmichael numbers A087788, but not all Carmichael numbers A002997. This is a nontrivial fact. The smallest Carmichael number that is not a member is 173085121 = 11*31*53*61*157. For further properties of the terms see A324456 and Kellner 2019. - Bernd C. Kellner, Apr 02 2019

Examples

			s_p(m) = 1 < p for m = 2, 3, 4, 5 with prime p dividing m, but if m = 6 and p = 2 then s_p(m) = s_2(2 + 2^2) = 1 + 1 = 2 = p, so a(1) = 6.
		

Crossrefs

A324456 is the union of A324857 and A324858.
Includes A083558.

Programs

  • Maple
    S:= (p,m) -> convert(convert(m,base,p),`+`):
    filter:= proc(m) ormap(p -> S(p,m) = p, numtheory:-factorset(m)) end proc:
    select(filter, [$2..500]); # Robert Israel, Mar 20 2019
  • Mathematica
    s[n_, b_] := If[n < 1 || b < 2, 0, Plus @@ IntegerDigits[n, b]];
    f[n_] := AnyTrue[Divisors[n], PrimeQ[#] && s[n, #] == # &];
    Select[Range[400], f[#] &]n (* simplified by Bernd C. Kellner, Apr 02 2019 *)
  • PARI
    isok(n) = {if (n>1, my(vp=factor(n)[,1]); for (k=1, #vp, if (sumdigits(n, vp[k]) == vp[k], return (1)))); } \\ Michel Marcus, Mar 19 2019

A324974 Rank of the n-th special polygonal number A324973(n).

Original entry on oeis.org

3, 3, 3, 5, 3, 3, 6, 3, 6, 3, 11, 5, 3, 3, 8, 10, 5, 6, 12, 3, 15, 9, 3, 5, 3, 8, 3, 8, 19, 14, 5, 7, 3, 6, 6, 36, 21, 66, 22, 3, 10, 5, 6, 3, 3, 50, 10, 20, 5, 14, 11, 51, 3, 10, 21, 6, 13, 5, 16, 25, 3, 3, 6, 6, 12, 14, 10, 68, 5, 28, 3, 11, 29, 3, 56, 6, 19
Offset: 1

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Author

Keywords

Comments

While two polygonal numbers of different ranks can be equal (e.g., P(6,n) = P(3,2n-1)), that cannot occur for special polygonal numbers, since for fixed p the value of P(r,p) is strictly increasing with r. Thus the rank of a special polygonal number is well-defined.
The Carmichael numbers A002997 and primary Carmichael numbers A324316 are special polygonal numbers (see Kellner and Sondow 2019). Their ranks form the subsequences A324975 and A324976.

Examples

			If m = A324973(4) = 70 = 2*5*7, then p = 7, so a(4) = 2+2*((70/7)-1)/(7-1) = 5.
		

Crossrefs

A324975 and A324976 are subsequences.

Programs

  • Mathematica
    GPF[n_] := Last[Select[Divisors[n], PrimeQ]];
    T = Select[Flatten[Table[{p, (p^2*(r - 2) - p*(r - 4))/2}, {p, 3, 150}, {r, 3, 100}], 1], SquareFreeQ[Last[#]] && First[#] == GPF[Last[#]] &];
    TT = Take[Union[Table[Last[T[[i]]], {i, Length[T]}]], 47];
    Table[2 + 2*(t/GPF[t] - 1)/(GPF[t] - 1), {t, TT}]

Formula

a(n) = 2 + 2*((m/p)-1)/(p-1), where m = A324973(n) and p is its greatest prime factor. (Proof: solve m = P(r,p) = (p^2*(r-2) - p*(r-4))/2 for r.)

Extensions

Several missing terms inserted by and more terms from Jinyuan Wang, Feb 18 2021
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