A377134 Abundant numbers k such that k^2 + A033880(k)^2 is a perfect square.
336, 1080, 3078, 6048, 6552, 19845, 47616, 239760, 435708, 599400, 760320, 873180, 997920, 1468800, 1602300, 2004480, 4312440, 4612608, 4713984, 10181808, 10665984, 11554816, 12160512, 24149664, 31244850, 46431744, 56439504, 64995840, 116958492
Offset: 1
Keywords
Examples
336 is a term because its abundance is 320 and 320^2 + 336^2 = 464^2.
Links
- Amiram Eldar, Table of n, a(n) for n = 1..56
Programs
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Mathematica
l={}; Do[a=DivisorSigma[1,n]-2*n; If[a>0&&IntegerQ@Sqrt[n^2+a^2], AppendTo[l, n]], {n, 12, 2*10^8}]; l
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PARI
for(n=12, 2*10^8, a=sigma(n)-2*n; a>0&&issquare(n^2+a^2)&&print1(n", "))
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Python
import sympy as sp for i in range(12, 200000000): a=sp.ntheory.factor_.divisor_sigma(i) - 2*i if a>0 and sp.ntheory.primetest.is_square(i*i+a*a): print(i, end=", ")
Comments