cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A003410 Expansion of (1+x)(1+x^2)/(1-x-x^3).

Original entry on oeis.org

1, 2, 3, 5, 7, 10, 15, 22, 32, 47, 69, 101, 148, 217, 318, 466, 683, 1001, 1467, 2150, 3151, 4618, 6768, 9919, 14537, 21305, 31224, 45761, 67066, 98290, 144051, 211117, 309407, 453458, 664575, 973982, 1427440, 2092015, 3065997, 4493437, 6585452, 9651449
Offset: 0

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Author

Keywords

Comments

From Emeric Deutsch, Feb 15 2010: (Start)
a(n) is the number of binary words of length n that have no pair of adjacent 1's and have no 0000 subwords. Example: a(4)=7 because we have 0101, 1010, 0010, 1001, 0100, 0001, and 1000.
a(n) = A171855(n,0). (End)
a(n) is the number of solus bitstrings of length n with no runs of 4 zeros. - Steven Finch, Mar 25 2020

References

  • R. K. Guy, personal communication.
  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

Crossrefs

Essentially the same as A058278 and A097333, partial sums and first differences of A058278, first and second differences of itself and A038718. Equals A038718(n+1) + 1, n>0.
Cf. A171855. - Emeric Deutsch, Feb 15 2010

Programs

  • Maple
    G:=series((1+x)*(1+x^2)/(1-x-x^3),x=0,42): 1,seq(coeff(G,x^n),n=1..38);
    A003410:=-(1+z)*(1+z**2)/(-1+z+z**3); # Simon Plouffe in his 1992 dissertation
  • Mathematica
    Join[{1}, LinearRecurrence[{1, 0, 1}, {2, 3, 5}, 80]] (* Vladimir Joseph Stephan Orlovsky, Feb 11 2012 *)
    CoefficientList[Series[((1+x)(1+x^2))/(1-x-x^3),{x,0,50}],x] (* Harvey P. Dale, Jul 07 2025 *)
  • PARI
    a(n)=([0,1,0; 0,0,1; 1,0,1]^n*[1;2;3])[1,1] \\ Charles R Greathouse IV, Mar 25 2020

Formula

a(n) = a(n-1) + a(n-3) for n>3, see also A000930. - Reinhard Zumkeller, Oct 26 2005
For n>1, a(n) = 2*A000930(n) + A000930(n-2). - Gerald McGarvey, Sep 10 2008
a(n) = A058278(n+4) = A097333(n+1) for n >= 1. - Jianing Song, Aug 11 2023

Extensions

More terms from Emeric Deutsch, Dec 11 2004