A172372 Least number k such that the n-th prime not dividing 10 (A004139(n)) divides the repunit (10^k-1)/9.
3, 6, 2, 6, 16, 18, 22, 28, 15, 3, 5, 21, 46, 13, 58, 60, 33, 35, 8, 13, 41, 44, 96, 4, 34, 53, 108, 112, 42, 130, 8, 46, 148, 75, 78, 81, 166, 43, 178, 180, 95, 192, 98, 99, 30, 222, 113, 228, 232, 7, 30, 50, 256, 262, 268, 5, 69, 28, 141, 146, 153, 155, 312, 79, 110
Offset: 1
Keywords
Examples
3 divides 111, but not 1 or 11, so a(1) = 3. 7 divides 111111 but not 1, 11, 111, 1111, or 11111, so a(2) = 6.
References
- David Wells, The Factors of the Repunits 11 through R_40, The Penguin Dictionary of Curious and Interesting Numbers, p. 219 Penguin 1986.
- David Wells, The Penguin Dictionary of Curious and Interesting Numbers, Penguin Books, 1997.
- David Wells, Curious and Interesting Numbers (Revised), Penguin Books, page 114.
Links
- Project Euler, Problem 129: Repunit divisibility
- S. S. Wagstaff, Jr., The Cunningham Project
- Eric Weisstein's World of Mathematics, Repunit.
Crossrefs
Programs
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PARI
a(n) = {k=1; p = if(n>1, prime(n+2), 3); while((10^k-1)/9 % p, k++); k;} \\ Michel Marcus, May 25 2014
Extensions
Corrected and edited by Michel Lagneau, Apr 25 2010
Term 6 between terms 44 and 96 doesn't belong to the sequence. The same for term 43 between terms 43 and 178. Corrected and edited by Krzysztof Wojtas, May 25 2014
Comments