cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A025441 Number of partitions of n into 2 distinct nonzero squares.

Original entry on oeis.org

0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 1, 1, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 1, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 1, 1, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 2, 0, 0, 1, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 2, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 1, 0, 0, 1, 0, 1, 0
Offset: 0

Views

Author

Keywords

Crossrefs

Cf. A060306 gives records; A052199 gives where records occur.
Column k=2 of A341040.
Cf. A004439 (a(n)=0), A025302 (a(n)=1), A025303 (a(n)=2), A025304 (a(n)=3), A025305 (a(n)=4), A025306 (a(n)=5), A025307 (a(n)=6), A025308 (a(n)=7), A025309 (a(n)=8), A025310 (a(n)=9), A025311 (a(n)=10), A004431 (a(n)>0).

Programs

  • Haskell
    a025441 n = sum $ map (a010052 . (n -)) $
                          takeWhile (< n `div` 2) $ tail a000290_list
    -- Reinhard Zumkeller, Dec 20 2013
    
  • Mathematica
    Table[Count[PowersRepresentations[n, 2, 2], pr_ /; Unequal @@ pr && FreeQ[pr, 0]], {n, 0, 107}] (* Jean-François Alcover, Mar 01 2019 *)
  • PARI
    a(n)=if(n>4,sum(k=1,sqrtint((n-1)\2),issquare(n-k^2)),0) \\ Charles R Greathouse IV, Jun 10 2016
    
  • PARI
    a(n)=if(n<5,return(0)); my(v=valuation(n, 2), f=factor(n>>v), t=1); for(i=1, #f[, 1], if(f[i, 1]%4==1, t*=f[i, 2]+1, if(f[i, 2]%2, return(0)))); if(t%2, t-(-1)^v, t)/2-issquare(n/2) \\ Charles R Greathouse IV, Jun 10 2016
    
  • Python
    from math import prod
    from sympy import factorint
    def A025441(n):
        f = factorint(n).items()
        return -int(not (any((e-1 if p == 2 else e)&1 for p,e in f) or n&1)) + (((m:=prod(1 if p==2 else (e+1 if p&3==1 else (e+1)&1) for p, e in f))+((((~n & n-1).bit_length()&1)<<1)-1 if m&1 else 0))>>1) if n else 0 # Chai Wah Wu, Sep 08 2022

Formula

a(A025302(n)) = 1. - Reinhard Zumkeller, Dec 20 2013
a(n) = Sum_{ m: m^2|n } A157228(n/m^2). - Andrey Zabolotskiy, May 07 2018
a(n) = [x^n y^2] Product_{k>=1} (1 + y*x^(k^2)). - Ilya Gutkovskiy, Apr 22 2019
a(n) = Sum_{i=1..floor((n-1)/2)} c(i) * c(n-i), where c is the square characteristic (A010052). - Wesley Ivan Hurt, Nov 26 2020
a(n) = A000161(n) - A093709(n). - Andrey Zabolotskiy, Apr 12 2022

A024508 Numbers that are a sum of 2 distinct nonzero squares in more than one way.

Original entry on oeis.org

65, 85, 125, 130, 145, 170, 185, 205, 221, 250, 260, 265, 290, 305, 325, 340, 365, 370, 377, 410, 425, 442, 445, 481, 485, 493, 500, 505, 520, 530, 533, 545, 565, 580, 585, 610, 625, 629, 650, 680, 685, 689, 697, 725, 730, 740, 745, 754, 765, 785, 793, 820, 845, 850, 865, 884, 890, 901, 905, 925, 949, 962, 965, 970, 985, 986, 1000, 1010, 1025, 1037, 1040, 1060, 1066, 1073, 1090, 1105, 1125
Offset: 1

Views

Author

Keywords

Comments

Appears to be n such that sigma(n)==0 (mod 4) and n is expressible as a sum of 2 squares. - Benoit Cloitre, Apr 20 2003
The comment that is in above is true most of the time. However if number of odd divisors of n that is a term of this sequence is not divisible by 4, then sigma(n) cannot be divisible by 4. For example; 325, 425, 625, 650, ... See also A000443 for more related examples. - Altug Alkan, Jun 09 2016
If m is a term then (a^2 + b^2) * m is a term for a,b > 0. Hence this sequence is closed under multiplication. - David A. Corneth, Jun 10 2016

Crossrefs

Cf. A001481, A025303 (exactly 2 ways), A025304 (exactly 3 ways), A025305 (exactly 4 ways), A025306 (exactly 5 ways).

Programs

  • Mathematica
    lst={};q=-1;k=1;Do[Do[x=a^2;Do[y=b^2;If[x+y==n,If[n==q&&k==1,AppendTo[lst,n]];If[n!=q,q=n;k=1,k++ ]],{b,Floor[(n-x)^(1/2)],a+1,-1}],{a,Floor[n^(1/2)],1,-1}],{n,2*6!}];lst (* Vladimir Joseph Stephan Orlovsky, Jan 22 2009 *)
  • PARI
    is(n) = {my(t=0,i);t=sum(i=1,sqrtint((n-1)\2),issquare(n-i^2));t>1} \\ David A. Corneth, Jun 10 2016
    
  • PARI
    is(n)=if(n<9,return(0)); my(v=valuation(n, 2), f=factor(n>>v), t=1); for(i=1, #f[, 1], if(f[i, 1]%4==1, t*=f[i, 2]+1, if(f[i, 2]%2, return(0)))); if(t%2, t-(-1)^v, t)/2-issquare(n/2)>1 \\ Charles R Greathouse IV, Jun 10 2016
Showing 1-2 of 2 results.