cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A055598 Even numbers not the sum of two terms from A034757.

Original entry on oeis.org

12, 20, 24, 34, 36, 38, 46, 52, 54, 58, 60, 70, 72, 74, 78, 80, 84, 88, 94, 98, 100, 106, 108, 110, 112, 116, 118, 120, 124, 126, 128, 136, 140, 142, 144, 148, 152, 154, 158, 160, 166, 170, 174, 180, 182, 184, 188, 190, 198, 204, 206, 210, 212, 214, 216, 224, 226, 228, 230, 232, 236, 238, 240, 242, 244, 256, 258, 264, 266, 268, 272, 274, 276, 278, 280
Offset: 1

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Author

Wouter Meeussen, Jun 02 2000

Keywords

A005282 Mian-Chowla sequence (a B_2 sequence): a(1) = 1; for n>1, a(n) = smallest number > a(n-1) such that the pairwise sums of elements are all distinct.

Original entry on oeis.org

1, 2, 4, 8, 13, 21, 31, 45, 66, 81, 97, 123, 148, 182, 204, 252, 290, 361, 401, 475, 565, 593, 662, 775, 822, 916, 970, 1016, 1159, 1312, 1395, 1523, 1572, 1821, 1896, 2029, 2254, 2379, 2510, 2780, 2925, 3155, 3354, 3591, 3797, 3998, 4297, 4433, 4779, 4851
Offset: 1

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Author

Keywords

Comments

An alternative definition is to start with 1 and then continue with the least number such that all pairwise differences of distinct elements are all distinct. - Jens Voß, Feb 04 2003. [However, compare A003022 and A227590. - N. J. A. Sloane, Apr 08 2016]
Rachel Lewis points out [see link] that S, the sum of the reciprocals of this sequence, satisfies 2.158435 <= S <= 2.158677. Similarly, the sum of the squares of reciprocals of this sequence converges to approximately 1.33853369 and the sum of the cube of reciprocals of this sequence converges to approximately 1.14319352. - Jonathan Vos Post, Nov 21 2004; comment changed by N. J. A. Sloane, Jan 02 2020
Let S denote the reciprocal sum of a(n). Then 2.158452685 <= S <= 2.158532684. - Raffaele Salvia, Jul 19 2014
From Thomas Ordowski, Sep 19 2014: (Start)
Known estimate: n^2/2 + O(n) < a(n) < n^3/6 + O(n^2).
Conjecture: a(n) ~ n^3 / log(n)^2. (End)

Examples

			The second term is 2 because the 3 pairwise sums 1+1=2, 1+2=3, 2+2=4 are all distinct.
The third term cannot be 3 because 1+3 = 2+2. But it can be 4, since 1+4=5, 2+4=6, 4+4=8 are distinct and distinct from the earlier sums 1+1=2, 1+2=3, 2+2=4.
		

References

  • P. Erdős and R. Graham, Old and new problems and results in combinatorial number theory. Monographies de L'Enseignement Mathématique (1980).
  • S. R. Finch, Mathematical Constants, Cambridge, 2003, Section 2.20.2.
  • R. K. Guy, Unsolved Problems in Number Theory, E28.
  • A. M. Mian and S. D. Chowla, On the B_2-sequences of Sidon, Proc. Nat. Acad. Sci. India, A14 (1944), 3-4.
  • N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).

Crossrefs

Row 2 of A347570.
Cf. A051788, A080200 (for differences between terms).
Different from A046185. Cf. A011185.
See also A003022, A227590.
A259964 has a greater sum of reciprocals.
Cf. A002858.

Programs

  • Haskell
    import Data.Set (Set, empty, insert, member)
    a005282 n = a005282_list !! (n-1)
    a005282_list = sMianChowla [] 1 empty where
       sMianChowla :: [Integer] -> Integer -> Set Integer -> [Integer]
       sMianChowla sums z s | s' == empty = sMianChowla sums (z+1) s
                            | otherwise   = z : sMianChowla (z:sums) (z+1) s
          where s' = try (z:sums) s
                try :: [Integer] -> Set Integer -> Set Integer
                try []     s                      = s
                try (x:sums) s | (z+x) `member` s = empty
                               | otherwise        = try sums $ insert (z+x) s
    -- Reinhard Zumkeller, Mar 02 2011
    
  • Maple
    a[1]:= 1: P:= {2}: A:= {1}:
    for n from 2 to 100 do
      for t from a[n-1]+1 do
        Pt:= map(`+`,A union {t},t);
        if Pt intersect P = {} then break fi
      od:
      a[n]:= t;
      A:= A union {t};
      P:= P union Pt;
    od:
    seq(a[n],n=1..100); # Robert Israel, Sep 21 2014
  • Mathematica
    t = {1}; sms = {2}; k = 1; Do[k++; While[Intersection[sms, k + t] != {}, k++]; sms = Join[sms, t + k, {2 k}]; AppendTo[t, k], {49}]; t (* T. D. Noe, Mar 02 2011 *)
  • PARI
    A005282_vec(N, A=[1], U=[0], D(A, n=#A)=vector(n-1, k, A[n]-A[n-k]))={ while(#A2 && U=U[k-1..-1]);A} \\ M. F. Hasler, Oct 09 2019
    
  • PARI
    aupto(L)= my(S=vector(L), A=[1]); for(i=2, L, for(j=1, #A, if(S[i-A[j]], next(2))); for(j=1, #A, S[i-A[j]]=1); A=concat(A, i)); A \\ Ruud H.G. van Tol, Jun 30 2025
    
  • Python
    from itertools import count, islice
    def A005282_gen(): # generator of terms
        aset1, aset2, alist = set(), set(), []
        for k in count(1):
            bset2 = {k<<1}
            if (k<<1) not in aset2:
                for d in aset1:
                    if (m:=d+k) in aset2:
                        break
                    bset2.add(m)
                else:
                    yield k
                    alist.append(k)
                    aset1.add(k)
                    aset2 |= bset2
    A005282_list = list(islice(A005282_gen(),30)) # Chai Wah Wu, Sep 05 2023

Formula

a(n) = A025582(n) + 1.
a(n) = (A034757(n)+1)/2.

Extensions

Examples added by N. J. A. Sloane, Jun 01 2008
Showing 1-2 of 2 results.