cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

A048574 Self-convolution of 1 2 3 5 7 11 15 22 30 42 56 77 ... (A000041).

Original entry on oeis.org

1, 4, 10, 22, 43, 80, 141, 240, 397, 640, 1011, 1568, 2395, 3604, 5360, 7876, 11460, 16510, 23588, 33418, 47006, 65640, 91085, 125596, 172215, 234820, 318579, 430060, 577920, 773130, 1030007, 1366644, 1806445, 2378892, 3121835, 4082796
Offset: 2

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Keywords

Comments

Number of proper partitions of n into parts of two kinds (i.e. both kinds must be present). - Franklin T. Adams-Watters, Feb 08 2006

Examples

			a(4) = 22 because (1,2,3,5)*(5,3,2,1) = 5 + 6 + 6 + 5 = 22
		

Crossrefs

Essentially the same as A052837.
Cf. A122768.
Column k=2 of A060642.

Programs

  • Haskell
    a048574 n = a048574_list !! (n-2)
    a048574_list = f (drop 2 a000041_list) [1] where
    f (p:ps) rs = (sum $ zipWith (*) rs $ tail a000041_list) : f ps (p : rs)
    -- Reinhard Zumkeller, Nov 09 2015
    
  • Maple
    spec := [S,{C=Sequence(Z,1 <= card),B=Set(C,1 <= card),S=Prod(B,B)},unlabeled]: seq(combstruct[count](spec,size=n), n=0..20); # Franklin T. Adams-Watters, Feb 08 2006
    # second Maple program:
    a:= n-> (p-> add(p(j)*p(n-j), j=1..n-1))(combinat[numbpart]):
    seq(a(n), n=2..40);  # Alois P. Heinz, May 26 2018
  • Mathematica
    a[n_] := First[ ListConvolve[ pp = Array[ PartitionsP, n], pp]]; Table[ a[n], {n, 1, 36}] (* Jean-François Alcover, Oct 21 2011 *)
    Table[ListConvolve[PartitionsP[Range[n]],PartitionsP[Range[n]]],{n,40}]// Flatten (* Harvey P. Dale, Oct 29 2020 *)
  • PARI
    a(n) = sum(k=1, n-1, numbpart(k)*numbpart(n-k)); \\ Michel Marcus, Dec 11 2016

Formula

From Franklin T. Adams-Watters, Feb 08 2006: (Start)
a(0) = 0, a(n) = A000712(n)-2*A000041(n) for n>0.
a(n) = Sum_{k=1..n-1} A000041(k)*A000041(n-k).
G.f.: ((Product_{k>0} 1/(1-x^k))-1)^2 = (exp(Sum_{k>0} (x^k/(1-x^k)/k))-1)^2. (End)
a(n) ~ exp(2*Pi*sqrt(n/3)) / (4*3^(3/4)*n^(5/4)). - Vaclav Kotesovec, Mar 10 2018

Extensions

More terms from Larry Reeves (larryr(AT)acm.org), Sep 29 2000