A089466 Inverse hyperbinomial transform of A089467.
1, 1, 3, 18, 163, 1950, 28821, 505876, 10270569, 236644092, 6098971555, 173823708696, 5427760272507, 184267682837992, 6757353631762293, 266191329601854000, 11210291102456374801, 502602430218071545104, 23900770928782913595651, 1201581698963550283673632
Offset: 0
Keywords
Links
- Vincenzo Librandi, Table of n, a(n) for n = 0..100
Programs
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Mathematica
nn=20; t=Sum[n^(n-1)x^n/n!,{n,1,nn}]; a=Log[1/(1-t)]; Range[0,nn]! CoefficientList[Series[Exp[a-t^2/2], {x,0,nn}], x] (* Geoffrey Critzer, Mar 21 2012 *)
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PARI
a(n)=if(n<0,0,sum(m=0,n,sum(j=0,m,binomial(m,j)*binomial(n,n-m-j)*(n-1)^(n-m-j)*(m+j)!/(-2)^j)/m!))
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PARI
a(n) = n! * sum(k=0, n\2, (-1/2)^k * n^(n - 2*k) / (k! * (n - 2*k)!)); \\ Daniel Suteu, Jun 19 2018
Formula
A089467(n) = Sum_{k=0..n} (n-k+1)^(n-k-1)*C(n, k)*a(k).
a(n) = Sum_{m=0..n} (Sum_{j=0..m} C(m, j)*C(n, n-m-j)*(n-1)^(n-m-j)*(m+j)!/(-2)^j)/m!.
E.g.f.: exp(-(T(x))^2/2)/(1-T(x)), where T(x) is the e.g.f. for A000169. - Geoffrey Critzer, Mar 21 2012
a(n) ~ exp(-1/2) * n^n. - Vaclav Kotesovec, Oct 08 2013
a(n) = n! * Sum_{k=0..floor(n/2)} (-1/2)^k * n^(n - 2*k) / (k! * (n - 2*k)!). - Daniel Suteu, Jun 19 2018
Comments