cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-10 of 13 results. Next

A107703 Sums of antidiagonals of number array A103209.

Original entry on oeis.org

1, 2, 4, 11, 43, 218, 1336, 9557, 78053, 714578, 7223548, 79704015, 951626175, 12210506762, 167413540912, 2440529176297, 37665520151241, 613124748803618, 10492684074110772, 188241358671950227, 3531254422923432083
Offset: 0

Views

Author

Paul Barry, May 21 2005

Keywords

Comments

Row sums of A107702.

Formula

a(n)=sum{k=0..n, sum{j=0..n-k, C(n-k+j, 2j)*k^j*C(k)}}, C(n) given by A000108.

A107704 Diagonal sums of A103209, viewed as number triangle.

Original entry on oeis.org

1, 1, 2, 3, 8, 26, 107, 492, 2481, 13599, 81288, 531343, 3790344, 29279668, 242278645, 2125160800, 19608039385, 189437263949, 1912477987102, 20161911603747, 221869317899264, 2546362514225134, 30430660439311103
Offset: 0

Views

Author

Paul Barry, May 21 2005

Keywords

Formula

a(n)=sum{k=0..floor(n/2), sum{j=0..n-2k, C(n-2k+j, 2j)*k^j*C(k)}}, C(n) given by A000108.

A103210 a(n) = (1/n) * Sum_{i=0..n-1} C(n,i)*C(n,i+1)*2^i*3^(n-i), a(0)=1.

Original entry on oeis.org

1, 3, 15, 93, 645, 4791, 37275, 299865, 2474025, 20819307, 178003815, 1541918901, 13503125805, 119352115551, 1063366539315, 9539785668657, 86104685123025, 781343125570515, 7124072211203775, 65233526296899981, 599633539433039445, 5531156299278726663
Offset: 0

Views

Author

Ralf Stephan, Jan 27 2005

Keywords

Comments

The Hankel transform of this sequence is 6^C(n+1,2). - Philippe Deléham, Oct 28 2007
The Hankel transform of the sequence starting 1, 1, 3, 15, ... is A081955. - Paul Barry, Dec 09 2008
Number of Schroeder paths from (0,0) to (0,2n) allowing two colors for the down steps (or alternatively for the rise steps). - Paul Barry, Feb 01 2009
Essentially, reversion of x*(1-2*x)/(1+x). - Paul Barry, Apr 28 2009
a(n) is also the number of infix expressions with n variables and operators +, - and * (or +, * and /) such that there are no redundant parentheses. - Vjeran Crnjak, Apr 25 2020

Crossrefs

Third column of array A103209.

Programs

  • Magma
    R:=PowerSeriesRing(Rationals(), 25); Coefficients(R!((1-x-Sqrt(x^2-10*x+1))/(4*x))); // G. C. Greubel, Feb 10 2018
    
  • Maple
    A103210 := proc(n)
        if n = 0 then
            1;
        else
            add(binomial(n,i)*binomial(n,i+1)*2^i*3^(n-i),i=0..n-1)/n ;
        end if;
    end proc: # R. J. Mathar, Feb 10 2015
    A103210_list := proc(n) local j, a, w; a := array(0..n); a[0] := 1;
    for w from 1 to n do a[w] := 3*a[w-1] + 2*add(a[j]*a[w-j-1], j=1..w-1) od;
    convert(a, list) end: A103210_list(21); # Peter Luschny, Feb 29 2016
  • Mathematica
    CoefficientList[Series[(1-x-Sqrt[x^2-10*x+1])/(4*x), {x, 0, 25}], x] (* Vaclav Kotesovec, Oct 17 2012 *)
    A103210[n_]:= Hypergeometric2F1[-n, n+1, 2, -2]; Table[A103210[n], {n, 0, 25}] (* Peter Luschny, Jan 07 2018 *)
  • PARI
    my(x='x+O('x^25)); Vec((1-x-sqrt(x^2-10*x+1))/(4*x)) \\ G. C. Greubel, Feb 10 2018
    
  • Sage
    [1]+[(3^n/n)*sum( binomial(n,j)*binomial(n,j+1)*(2/3)^j for j in (0..n-1)) for n in (1..25)] # G. C. Greubel, Jun 08 2020

Formula

G.f.: (1 - z - sqrt(1 -10*z +z^2))/(4*z).
a(n) = Sum_{k=0..n} C(n+k, 2k) * 2^k * C(k), C(n) given by A000108. - Paul Barry, May 21 2005
a(n) = Sum_{k=0..n} A060693(n,k)*2^(n-k). - Philippe Deléham, Apr 02 2007
a(0) = 1, a(n) = a(n-1) + 2*Sum_{k=0..n-1} a(k)*a(n-1-k). - Philippe Deléham, Oct 23 2007
a(n) = (3/2)*A107841(n) for n > 0. - Philippe Deléham, Oct 28 2007
G.f.: 1/(1-x-2*x/(1-x-2*x/(1-x-2*x/(1-.... (continued fraction). - Paul Barry, Feb 01 2009
G.f.: 1/(1-3*x-6*x^2/(1-5*x-6*x^2/(1-5*x-6*x^2/(1-... (continued fraction). - Paul Barry, Apr 28 2009
G.f.: 1/(1-3*x/(1-2*x/(1-3*x/(1-2*x/(1-3*x/(1-... (continued fraction). - Paul Barry, May 14 2009
a(n) = Hypergeometric2F1(-n,n+1;2;-2) = Sum_{k=0..n} C(n+k,k) * C(n,k) * 2^k/(k+1). - Paul Barry, Feb 08 2011
G.f.: A(x) = (1-x-(x^2-10*x+1)^(1/2))/(4*x) = 1/(G(0)-x); G(k)= 1 + x - 3*x/G(k+1); (continued fraction, 1-step). - Sergei N. Gladkovskii, Jan 05 2012
D-finite with recurrence: (n+1)*a(n) = 5*(2*n-1)*a(n-1) - (n-2)*a(n-2). - Vaclav Kotesovec, Oct 17 2012
a(n) ~ sqrt(12+5*sqrt(6))*(5+2*sqrt(6))^n/(4*sqrt(Pi)*n^(3/2)). - Vaclav Kotesovec, Oct 17 2012
G.f. A(x) satisfies: A(x) = (1 + 2*x*A(x)^2) / (1 - x). - Ilya Gutkovskiy, Jun 30 2020

Extensions

Spelling/notation corrections by Charles R Greathouse IV, Mar 18 2010

A103211 a(n) = (1/n) * Sum_{i=0..n-1} C(n,i)*C(n,i+1)*3^i*4^(n-i), a(0)=1.

Original entry on oeis.org

1, 4, 28, 244, 2380, 24868, 272188, 3080596, 35758828, 423373636, 5092965724, 62071299892, 764811509644, 9511373563492, 119231457692284, 1505021128450516, 19112961439180588, 244028820862442116, 3130592301487969948, 40333745806536135028, 521655330655122923980
Offset: 0

Views

Author

Ralf Stephan, Jan 27 2005

Keywords

Comments

The Hankel transform of this sequence is 12^C(n+1,2). - Philippe Deléham, Oct 28 2007
The sequence 1, 1, 4, 28, ... has a(n) = 0^n + Sum_{k=0..n-1} C(n+k-1, 2*k)*C(k)*3^k and Hankel transform 3^C(n+1, 2)*4^C(n, 2). - Paul Barry, Dec 09 2008
Number of Dyck n-paths with two colors of up (U,u) and two colors of down (D,d) avoiding DU. - David Scambler, Jun 24 2013

Examples

			G.f. = 1 + 4*x + 28*x^2 + 244*x^3 + 2380*x^4 + 24868*x^5 + ... _Michael Somos_, Mar 15 2024
		

Crossrefs

Fourth column of array A103209.
Cf. A131763.

Programs

  • GAP
    a:=n->(1/n)*Sum([0..n-1],i->Binomial(n,i)*Binomial(n,i+1)*
    3^i*4^(n-i));;
    A103211:=Concatenation([1],List([1..20],n->a(n))); # Muniru A Asiru, Feb 11 2018
  • Magma
    Q:=Rationals(); R:=PowerSeriesRing(Q, 40); Coefficients(R!((1-x-Sqrt(x^2-14*x+1))/(6*x))) // G. C. Greubel, Feb 10 2018
    
  • Maple
    A103211_list := proc(n) local j, a, w; a := array(0..n); a[0] := 1;
    for w from 1 to n do a[w] := a[w-1] + 3*add(a[j]*a[w-j-1], j=0..w-1) od;
    convert(a, list) end: A103211_list(20); # Peter Luschny, Feb 29 2016
  • Mathematica
    CoefficientList[Series[(1-x-Sqrt[x^2-14*x+1])/(6*x), {x, 0, 20}], x] (* Vaclav Kotesovec, Oct 17 2012 *)
    a[n_] := Sum[(-1)^(n - k) Binomial[n, k] Hypergeometric2F1[k - n, n + 1, k + 2, 4], {k, 0, n}]; Table[a[n], {n, 0, 20}] (* Peter Luschny, Jan 08 2018 *)
    a[ n_] := If[n < 0, a[-1-n], SeriesCoefficient[2/(1 - x + Sqrt[1 - 14*x + x^2]), {x, 0, n}]]; (* Michael Somos, Mar 15 2024 *)
  • PARI
    x='x+O('x^30); Vec((1-x-sqrt(x^2-14*x+1))/(6*x)) \\ G. C. Greubel, Feb 10 2018
    
  • PARI
    {a(n) = if(n<0, a(-1-n), polcoeff(2/(1 - x + sqrt(1 - 14*x + x^2 + x*O(x^n))), n))}; /* Michael Somos, Mar 15 2024 */
    

Formula

G.f.: (1-z-sqrt(z^2-14*z+1))/(6*z).
a(n) = Sum_{k=0..n} C(n+k,2k)*3^k*C(k), C(n) given by A000108. - Paul Barry, May 21 2005
a(n) = Sum_{k=0..n} A060693(n,k)*3^(n-k). - Philippe Deléham, Apr 02 2007
a(0)=1, a(n) = a(n-1) + 3*Sum_{k=0..n-1} a(k)*a(n-1-k). - Philippe Deléham, Oct 23 2007
G.f.: 1/(1-x-3*x/(1-x-3*x/(1-x-3*x/(1-x-3*x/(1-... (continued fraction). - Paul Barry, Nov 07 2009
D-finite with recurrence: (n+1)*a(n) = 7*(2*n-1)*a(n-1) - (n-2)*a(n-2). - Vaclav Kotesovec, Oct 17 2012
a(n) ~ sqrt(24+14*sqrt(3))*(7+4*sqrt(3))^n/(6*sqrt(Pi)*n^(3/2)). - Vaclav Kotesovec, Oct 17 2012
a(n) = Sum_{k=0..n} (-1)^(n-k) binomial(n,k)*hypergeom([k - n, n + 1], [k + 2], 4). - Peter Luschny, Jan 08 2018
G.f. A(x) satisfies: A(x) = (1 + 3*x*A(x)^2) / (1 - x). - Ilya Gutkovskiy, Jun 30 2020
From Michael Somos, Mar 15 2024: (Start)
a(n) = (4/3)*A131763(n) for n>0.
Given g.f. A(x) and y = -x*A(-x^2), then 3*y-1/y = x+1/x.
If a(n) := a(-1-n) for n<0, then 0 = a(n)*(+a(n+1) -35*a(n+2) +4*a(n+3)) +a(n+1)*(+7*a(n+1) +194*a(n+2) -35*a(n+3)) +a(n+2)*(+7*a(n+2) +a(n+3)) for all n in Z. (End)

A133305 a(n) = (1/n)*Sum_{i=0..n-1} C(n,i)*C(n,i+1)*4^i*5^(n-i), a(0) = 1.

Original entry on oeis.org

1, 5, 45, 505, 6345, 85405, 1204245, 17558705, 262577745, 4005148405, 62070886845, 974612606505, 15471084667545, 247876665109005, 4003225107031845, 65101209768055905, 1065128963164067745, 17520376884067071205, 289572455530026439245, 4806489064223483202905
Offset: 0

Views

Author

Philippe Deléham, Oct 18 2007

Keywords

Comments

Fifth column of array A103209.
The Hankel transform of this sequence is 20^C(n+1,2). - Philippe Deléham, Oct 28 2007

Crossrefs

Programs

  • Magma
    Q:=Rationals(); R:=PowerSeriesRing(Q, 40); Coefficients(R!((1-x-Sqrt(x^2-18*x+1))/(8*x))) // G. C. Greubel, Feb 10 2018
  • Mathematica
    a[n_] := Hypergeometric2F1[-n, n + 1, 2, -4];
    Table[a[n], {n, 0, 16}] (* Peter Luschny, Jan 08 2018 *)
    CoefficientList[Series[(1-x-Sqrt[x^2-18*x+1])/(8*x), {x, 0, 50}], x] (* G. C. Greubel, Feb 10 2018 *)
  • PARI
    x='x+O('x^30); Vec((1-x-sqrt(x^2-18*x+1))/(8*x)) \\ G. C. Greubel, Feb 10 2018
    

Formula

G.f.: (1-z-sqrt(z^2-18*z+1))/(8*z).
a(n) = Sum_{k=0..n} A088617(n,k)*4^k.
a(n) = Sum_{k=0..n} A060693(n,k)*4^(n-k).
a(n) = Sum_{k=0..n} C(n+k, 2k)*4^k*C(k), C(n) given by A000108.
a(0) = 1, a(n) = a(n-1) + 4*Sum_{k=0..n-1} a(k)*a(n-1-k). - Philippe Deléham, Oct 23 2007
Conjecture: (n+1)*a(n) + 9*(-2*n+1)*a(n-1) + (n-2)*a(n-2) = 0. - R. J. Mathar, May 23 2014
G.f.: 1/(1 - 5*x/(1 - 4*x/(1 - 5*x/(1 - 4*x/(1 - 5*x/(1 - ...)))))), a continued fraction. - Ilya Gutkovskiy, May 10 2017
a(n) = hypergeom([-n, n + 1], [2], -4). - Peter Luschny, Jan 08 2018
a(n) ~ 5^(1/4) * phi^(6*n + 3) / (2^(5/2) * sqrt(Pi) * n^(3/2)), where phi = A001622 is the golden ratio. - Vaclav Kotesovec, Nov 21 2021

A133306 a(n) = (1/n)*Sum_{i=0..n-1} C(n,i)*C(n,i+1)*5^i*6^(n-i), a(0)=1.

Original entry on oeis.org

1, 6, 66, 906, 13926, 229326, 3956106, 70572066, 1291183806, 24095736726, 456879955026, 8776867331706, 170459895028566, 3341423256586206, 66023812564384026, 1313634856606430226, 26295597219228901806, 529199848207277494566, 10701116421278640683106, 217317899302044152030826
Offset: 0

Views

Author

Philippe Deléham, Oct 18 2007

Keywords

Comments

Sixth column of array A103209.
The Hankel transform of this sequence is 30^C(n+1,2). - Philippe Deléham, Oct 28 2007

Crossrefs

Programs

  • Magma
    Q:=Rationals(); R:=PowerSeriesRing(Q, 40); Coefficients(R!((1-x-Sqrt(x^2-22*x+1))/(10*x))) // G. C. Greubel, Feb 10 2018
  • Mathematica
    CoefficientList[Series[(1-x-Sqrt[x^2-22*x+1])/(10*x), {x,0,50}], x] (* G. C. Greubel, Feb 10 2018 *)
  • PARI
    x='x+O('x^30); Vec((1-x-sqrt(x^2-22*x+1))/(10*x)) \\ G. C. Greubel, Feb 10 2018
    

Formula

G.f.: (1-z-sqrt(z^2-22*z+1))/(10*z).
a(n) = Sum_{k, 0<=k<=n} A088617(n,k)*5^k.
a(n) = Sum_{k, 0<=k<=n} A060693(n,k)*5^(n-k).
a(n) = Sum_{k, 0<=k<=n} C(n+k, 2*k) 5^k*C(k), C(n) given by A000108.
a(0)=1, a(n) = a(n-1) + 5*Sum_{k=0..n-1} a(k)*a(n-1-k). - Philippe Deléham, Oct 23 2007
Conjecture: (n+1)*a(n) + 11*(-2*n+1)*a(n-1) + (n-2)*a(n-2) = 0. - R. J. Mathar, May 23 2014
G.f.: 1/(1 - 6*x/(1 - 5*x/(1 - 6*x/(1 - 5*x/(1 - 6*x/(1 - ...)))))), a continued fraction. - Ilya Gutkovskiy, May 10 2017
a(n) ~ 3^(1/4) * (11 + 2*sqrt(30))^(n + 1/2) / (10^(3/4) * sqrt(Pi) * n^(3/2)). - Vaclav Kotesovec, Nov 29 2021

A133307 a(n) = (1/n)*Sum_{i=0..n-1} C(n,i)*C(n,i+1)*6^i*7^(n-i), a(0)=1.

Original entry on oeis.org

1, 7, 91, 1477, 26845, 522739, 10663471, 224939113, 4866571801, 107393779423, 2407939176643, 54700070934061, 1256249370578293, 29119953189833611, 680401905145643863, 16008309928027493713, 378930780842531820721, 9017843351806985482423, 215634517504141993966891
Offset: 0

Views

Author

Philippe Deléham, Oct 18 2007

Keywords

Comments

Seventh column of array A103209.
The Hankel transform of this sequence is 42^C(n+1,2). - Philippe Deléham, Oct 28 2007

Crossrefs

Programs

  • Magma
    Q:=Rationals(); R:=PowerSeriesRing(Q, 40); Coefficients(R!((1-x-Sqrt(x^2-26*x+1))/(12*x))) // G. C. Greubel, Feb 10 2018
  • Maple
    a := n -> hypergeom([-n, n+1], [2], -6);
    seq(round(evalf(a(n),32)),n=0..16); # Peter Luschny, May 23 2014
  • Mathematica
    CoefficientList[Series[(1-x-Sqrt[x^2-26*x+1])/(12*x), {x,0,50}], x] (* G. C. Greubel, Feb 10 2018 *)
  • PARI
    x='x+O('x^30); Vec((1-x-sqrt(x^2-26*x+1))/(12*x)) \\ G. C. Greubel, Feb 10 2018
    

Formula

G.f.: (1-z-sqrt(z^2-26*z+1))/(12*z).
a(n) = Sum_{k=0..n} A088617(n,k)*6^k .
a(n) = Sum_{k=0..n} A060693(n,k)*6^(n-k).
a(n) = Sum_{k=0..n} C(n+k, 2k)6^k*C(k), C(n) given by A000108.
a(0)=1, a(n) = a(n-1) + 6*Sum_{k=0..n-1} a(k)*a(n-1-k). - Philippe Deléham, Oct 23 2007
Conjecture: (n+1)*a(n) + 13*(-2*n+1)*a(n-1) + (n-2)*a(n-2) = 0. - R. J. Mathar, May 23 2014
a(n) = hypergeom([-n, n+1], [2], -6). # Peter Luschny, May 23 2014
G.f.: 1/(1 - 7*x/(1 - 6*x/(1 - 7*x/(1 - 6*x/(1 - 7*x/(1 - ...)))))), a continued fraction. - Ilya Gutkovskiy, May 10 2017
a(n) ~ 42^(1/4) * (13 + 2*sqrt(42))^(n + 1/2) / (12*sqrt(Pi)*n^(3/2)). - Vaclav Kotesovec, Nov 29 2021

A133308 a(n) = (1/n)*Sum_{i=0..n-1} C(n,i)*C(n,i+1)*7^i*8^(n-i), a(0)=1.

Original entry on oeis.org

1, 8, 120, 2248, 47160, 1059976, 24958200, 607693640, 15175702200, 386555020552, 10004252294520, 262321706465736, 6953918939056440, 186059575955360136, 5018045415643478520, 136276936332343342152, 3723442515218861494200, 102281105054908404972040
Offset: 0

Views

Author

Philippe Deléham, Oct 18 2007

Keywords

Comments

Eighth column of array A103209.
The Hankel transform of this sequence is 56^C(n+1,2). - Philippe Deléham, Oct 28 2007

Crossrefs

Programs

  • Magma
    Q:=Rationals(); R:=PowerSeriesRing(Q, 40); Coefficients(R!((1-x-Sqrt(x^2-30*x+1))/(14*x))) // G. C. Greubel, Feb 10 2018
  • Maple
    a := n -> hypergeom([-n, n+1], [2], -7);
    seq(round(evalf(a(n), 32)), n=0..15); # Peter Luschny, May 23 2014
  • Mathematica
    CoefficientList[Series[(1-x-Sqrt[x^2-30*x+1])/(14*x), {x,0,50}], x] (* G. C. Greubel, Feb 10 2018 *)
  • PARI
    x='x+O('x^30); Vec((1-x-sqrt(x^2-30*x+1))/(14*x)) \\ G. C. Greubel, Feb 10 2018
    

Formula

G.f.: (1-z-sqrt(z^2-30*z+1))/(14*z).
a(n) = Sum_{k, 0<=k<=n} A088617(n,k)*7^k.
a(n) = Sum_{k, 0<=k<=n} A060693(n,k)*7^(n-k).
a(n) = Sum_{k, 0<=k<=n} C(n+k, 2k)7^k*C(k), C(n) given by A000108.
a(0)=1, a(n) = a(n-1) + 7*Sum_{k=0..n-1} a(k)*a(n-1-k). - Philippe Deléham, Oct 23 2007
Conjecture: (n+1)*a(n) + 15*(-2*n+1)*a(n-1) + (n-2)*a(n-2) = 0. - R. J. Mathar, May 23 2014
a(n) = hypergeom([-n, n+1], [2], -7). - Peter Luschny, May 23 2014
G.f.: 1/(1 - 8*x/(1 - 7*x/(1 - 8*x/(1 - 7*x/(1 - 8*x/(1 - ...)))))), a continued fraction. - Ilya Gutkovskiy, May 10 2017

A133309 a(n) = (1/n)*Sum_{i=0..n-1} C(n,i)*C(n,i+1)*8^i*9^(n-i), a(0)=1.

Original entry on oeis.org

1, 9, 153, 3249, 77265, 1968633, 52546473, 1450365921, 41058670113, 1185580310121, 34783088255289, 1033907690362257, 31070005849929969, 942384250116160857, 28812102048874578249, 887007207177728561601, 27473495809057571051073, 855518113376312857290441
Offset: 0

Views

Author

Philippe Deléham, Oct 18 2007

Keywords

Comments

Ninth column of array A103209.
The Hankel transform of this sequence is 72^C(n+1,2). - Philippe Deléham, Oct 29 2007

Crossrefs

Programs

  • Magma
    Q:=Rationals(); R:=PowerSeriesRing(Q, 40); Coefficients(R!( (1-x-Sqrt(x^2-34*x+1))/16 )); // G. C. Greubel, Feb 10 2018
  • Mathematica
    Rest@ CoefficientList[ Series[(1-x-Sqrt[x^2-34*x+1])/16, {x, 0, 18}], x] (* Robert G. Wilson v, Oct 19 2007 *)
    Table[-((3 I LegendreP[n, -1, 2, 17])/(2 Sqrt[2])), {n, 0, 20}] (* Vaclav Kotesovec, Aug 13 2013 *)
  • PARI
    my(x='x+O('x^30)); Vec((1-x-sqrt(x^2-34*x+1))/16) \\ G. C. Greubel, Feb 10 2018
    

Formula

G.f.: (1-z-sqrt(z^2-34*z+1))/16.
a(n) = Sum_{k=0..n} A088617(n,k)*8^k.
a(n) = Sum_{k=0..n} A060693(n,k)*8^(n-k).
a(n) = Sum_{k=0..n} C(n+k, 2k)8^k*C(k), C(n) given by A000108.
a(0)=1, a(n) = a(n-1) + 8*Sum_{k=0..n-1} a(k)*a(n-1-k). - Philippe Deléham, Oct 23 2007
a(n) ~ sqrt(144+102*sqrt(2))*(17+12*sqrt(2))^n/(16*sqrt(Pi)*n^(3/2)). - Vaclav Kotesovec, Aug 13 2013
Recurrence: (n+1)*a(n) = 17*(2*n-1)*a(n-1) - (n-2)*a(n-2). - Vaclav Kotesovec, Aug 13 2013
G.f.: 1/(1 - 9*x/(1 - 8*x/(1 - 9*x/(1 - 8*x/(1 - 9*x/(1 - ...)))))), a continued fraction. - Ilya Gutkovskiy, May 10 2017

Extensions

More terms from Robert G. Wilson v, Oct 19 2007

A292798 a(n) = [x^n] 1/(1 - x - n*x/(1 - x - n*x/(1 - x - n*x/(1 - x - n*x/(1 - x - n*x/(1 - ...)))))), a continued fraction.

Original entry on oeis.org

1, 2, 15, 244, 6345, 229326, 10663471, 607693640, 41058670113, 3210853971610, 285387481699551, 28423216247375676, 3136023698489382025, 379743303818657805222, 50074394496591697023135, 7143088376895580682492176, 1096075604718147681983312001, 180030794404631168482202007090
Offset: 0

Views

Author

Ilya Gutkovskiy, Sep 23 2017

Keywords

Crossrefs

Main diagonal of A103209 (with offset 0).
Cf. A006318.

Programs

  • Mathematica
    Table[SeriesCoefficient[1/(1 - x + ContinuedFractionK[-n x, 1 - x, {i, 1, n}]), {x, 0, n}], {n, 0, 17}]
    Table[SeriesCoefficient[(1 - x + Sqrt[1 - 2 (2 n + 1) x + x^2])/(1 - 2 (n + 1) x + x^2 - (x - 1) Sqrt[1 - 2 (2 n + 1) x + x^2]), {x, 0, n}], {n, 0, 17}]
    Table[Hypergeometric2F1[-n, n + 1, 2, -n], {n, 0, 17}]
  • PARI
    {a(n) = polcoeff( (1+x)^(n+1) / (1 - n*x +x*O(x^n) )^(n+1), n) / (n+1)}
    for(n=0,30,print1(a(n),", ")) \\ Paul D. Hanna, May 07 2018

Formula

a(n) ~ exp(1/2) * 2^(2*n) * n^(n-3/2) / sqrt(Pi). - Vaclav Kotesovec, Sep 24 2017
a(n) = (1/(n+1)) * [x^n] (1+x)^(n+1) / (1 - n*x)^(n+1). - Paul D. Hanna, May 07 2018
From Fabian Pereyra, Sep 02 2024: (Start)
a(n) = Sum_{k=0..n} binomial(n,k)*binomial(n+k,k)*n^k/(k+1).
a(n) = [x^n] 2/(1 - x + sqrt(1 - 2*x*(1 + 2*n) + x^2)). (End)
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