cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

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A118404 Triangle T, read by rows, where all columns of T are different and yet all columns of the matrix square T^2 (A118407) are equal; also equals the matrix inverse of triangle A118400.

Original entry on oeis.org

1, 1, -1, -1, 0, 1, -1, 1, -1, -1, 1, 0, 0, 2, 1, 1, -1, 0, -2, -3, -1, -1, 0, 1, 2, 5, 4, 1, -1, 1, -1, -3, -7, -9, -5, -1, 1, 0, 0, 4, 10, 16, 14, 6, 1, 1, -1, 0, -4, -14, -26, -30, -20, -7, -1, -1, 0, 1, 4, 18, 40, 56, 50, 27, 8, 1, -1, 1, -1, -5, -22, -58, -96, -106, -77, -35, -9, -1, 1, 0, 0, 6, 27, 80, 154, 202, 183, 112, 44, 10, 1, 1, -1, 0, -6, -33, -107, -234, -356, -385, -295, -156, -54, -11, -1, -1, 0, 1, 6, 39, 140, 341, 590, 741, 680, 451, 210, 65, 12, 1, -1, 1, -1, -7, -45, -179, -481, -931, -1331, -1421, -1131, -661, -275, -77, -13, -1, 1, 0, 0, 8, 52, 224, 660, 1412, 2262, 2752, 2552, 1792, 936, 352, 90, 14, 1
Offset: 0

Views

Author

Paul D. Hanna, Apr 27 2006

Keywords

Comments

Appears to coincide with triangle (5.2) in Lee-Oh (2016), although there is no obvious connection! - N. J. A. Sloane, Dec 07 2016

Examples

			Triangle begins:
1;
1,-1;
-1, 0, 1;
-1, 1,-1,-1;
1, 0, 0, 2, 1;
1,-1, 0,-2,-3,-1;
-1, 0, 1, 2, 5, 4, 1;
-1, 1,-1,-3,-7,-9,-5,-1;
1, 0, 0, 4, 10, 16, 14, 6, 1;
1,-1, 0,-4,-14,-26,-30,-20,-7,-1;
-1, 0, 1, 4, 18, 40, 56, 50, 27, 8, 1;
-1, 1,-1,-5,-22,-58,-96,-106,-77,-35,-9,-1;
1, 0, 0, 6, 27, 80, 154, 202, 183, 112, 44, 10, 1;
1, -1, 0, -6, -33, -107, -234, -356, -385, -295, -156, -54, -11, -1;
-1, 0, 1, 6, 39, 140, 341, 590, 741, 680, 451, 210, 65, 12, 1;
-1, 1, -1, -7, -45, -179, -481, -931, -1331, -1421, -1131, -661, -275, -77, -13, -1;
1, 0, 0, 8, 52, 224, 660, 1412, 2262, 2752, 2552, 1792, 936, 352, 90, 14, 1;
1, -1, 0, -8, -60, -276, -884, -2072, -3674, -5014, -5304, -4344, -2728, -1288, -442, -104, -15, -1;
-1, 0, 1, 8, 68, 336, 1160, 2956, 5746, 8688, 10318, 9648, 7072, 4016, 1730, 546, 119, 16, 1; ...
The matrix square is A118407:
1;
0, 1;
-2, 0, 1;
2,-2, 0, 1;
0, 2,-2, 0, 1;
-2, 0, 2,-2, 0, 1;
4,-2, 0, 2,-2, 0, 1;
-6, 4,-2, 0, 2,-2, 0, 1;
4,-6, 4,-2, 0, 2,-2, 0, 1;
6, 4,-6, 4,-2, 0, 2,-2, 0, 1; ...
in which all columns are equal.
		

Crossrefs

Cf. A118405 (row sums), A118406 (unsigned row sums), A118407 (matrix square), A118400 (matrix inverse).
Columns or diagonals (modulo offsets): A219977, A011848, A212342, A007598, A005581, A007910.

Programs

  • Mathematica
    T[n_, k_] := SeriesCoefficient[(-1)^k/((1+x^2)(1+x)^(k-1)), {x, 0, n-k}];
    Table[T[n, k], {n, 0, 16}, {k, 0, n}] // Flatten (* Jean-François Alcover, Jul 26 2018 *)
  • PARI
    {T(n,k)=polcoeff(polcoeff((1+x)^2/(1+x^2)/(1+x+x*y +x*O(x^n)),n,x)+y*O(y^k),k,y)}
    for(n=0, 16, for(k=0, n, print1(T(n, k), ", ")); print(""))

Formula

G.f.: A(x,y) = (1+x)^2 / ( (1+x^2) * (1+x + x*y) ).
G.f. of column k: (-1)^k / ( (1+x^2) * (1+x)^(k-1) ) for k>=0.

A118405 Row sums of triangle A118404.

Original entry on oeis.org

1, 0, 0, -2, 4, -6, 12, -26, 52, -102, 204, -410, 820, -1638, 3276, -6554, 13108, -26214, 52428, -104858, 209716, -419430, 838860, -1677722, 3355444, -6710886, 13421772, -26843546, 53687092, -107374182, 214748364, -429496730, 858993460, -1717986918, 3435973836, -6871947674
Offset: 0

Views

Author

Paul D. Hanna, Apr 27 2006

Keywords

Crossrefs

Programs

  • Maple
    seq(coeff(series((1+x)^2/(1+x^2)/(1+2*x),x,n+1), x, n), n = 0 .. 35); # Muniru A Asiru, Oct 31 2018
  • Mathematica
    Total /@ Table[SeriesCoefficient[(-1)^k/((1 + x^2) (1 + x)^(k - 1)), {x, 0, n - k}], {n, 0, 35}, {k, 0, n}] (* Michael De Vlieger, Oct 31 2018 *)
    LinearRecurrence[{-2,-1,-2},{1,0,0},40] (* Harvey P. Dale, Aug 31 2020 *)
  • PARI
    a(n)=polcoeff((1+x)^2/(1+x^2)/(1+2*x+x*O(x^n)),n,x)
    
  • PARI
    a(n)=([0,1,0; 0,0,1; -2,-1,-2]^n*[1;0;0])[1,1] \\ Charles R Greathouse IV, Nov 06 2018

Formula

G.f.: A(x) = (1+x)^2/(1+x^2)/(1+2*x).
From Paul Curtz, Oct 31 2018: (Start)
a(n) + a(n+2) = 1, -2, 4, -8, ... = A122803(n).
a(2n+2) = -2*a(2n+1) = 4*A015521(n). (End)
a(n) = -2a(n-1) - a(n-2) - 2a(n-3). - Charles R Greathouse IV, Nov 06 2018
5*a(n) = (-2)^n + 2*A056594(n-1) + 4*A056594(n). - R. J. Mathar, Jan 27 2021
Showing 1-2 of 2 results.