A136754 Leading digit of n! in base 3.
1, 1, 2, 2, 2, 1, 2, 2, 2, 2, 2, 2, 1, 1, 2, 1, 2, 1, 1, 2, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 1, 1, 1, 1, 2, 1, 1, 2, 1, 1, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 2, 1, 1, 2, 1, 1, 2, 2, 1, 1, 2, 2, 1, 1, 1, 1, 2, 2, 2, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1
Offset: 0
Examples
a(10) = 2 as 10! = 20211100210000_3 which has leading digit 2. - _David A. Corneth_, Jan 15 2021
Links
- David A. Corneth, Table of n, a(n) for n = 0..9999
Crossrefs
Programs
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Mathematica
Table[First[IntegerDigits[n!,3]],{n,0,87}] (* Stefano Spezia, Aug 25 2022 *)
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PARI
a(n, {b = 3}) = my(f = n!); f \ b^logint(f, b) \\ David A. Corneth, Jan 10 2021
Extensions
Missing a(0)=1 inserted by David A. Corneth, Jan 10 2021