cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-2 of 2 results.

A153130 Period 6: repeat [1, 2, 4, 8, 7, 5].

Original entry on oeis.org

1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, 5
Offset: 0

Views

Author

Paul Curtz, Dec 19 2008

Keywords

Comments

Digital root of 2^n.
A regular version of Pitoun's sequence: a(n) = A029898(n+1).
Also obtained from permutations of A141425, A020806, A070366, A153110, A153990, A154127, A154687, or A154815.
This sequence and its (again period 6) repeated differences produce the table:
1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, ...
1, 2, 4, -1, -2, -4, 1, 2, 4, -1, -2, ...
1, 2, -5, -1, -2, 5, 1, 2, -5, -1, -2, ...
1, -7, 4, -1, 7, -4, 1, -7, 4, -1, 7, ...
-8, 11, -5, 8,-11, 5, -8, 11, -5, 8,-11, ...
19,-16, 13,-19, 16,-13, 19,-16, 13,-19, 16, ...
-35, 29,-32, 35,-29, 32,-35, 29,-32, 35,-29, ...
64,-61, 67,-64, 61,-67, 64,-61, 67,-64, 61, ...
If each entry of this table is read modulo 9 we obtain the very regular table:
1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, ...
1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, ...
1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, ...
1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, ...
1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, ...
1, 2, 4, 8, 7, 5, 1, 2, 4, 8, 7, ...
Also the decimal expansion of the constant 125/1001. - R. J. Mathar, Jan 23 2009
Digital root of the powers of any number congruent to 2 mod 9. - Alonso del Arte, Jan 26 2014

References

  • Cecil Balmond, Number 9: The Search for the Sigma Code. Munich, New York: Prestel (1998): 203.

Crossrefs

Cf. digital roots of powers of c mod 9: c = 4, A100402; c = 5, A070366; c = 7, A070403; c = 8, A010689.

Programs

Formula

a(n) + a(n+3) = 9 = A010734(n).
G.f.: (1+x+2x^2+5x^3)/((1-x)(1+x)(1-x+x^2)). - R. J. Mathar, Jan 23 2009
a(n) = A082365(n) mod 9. - Paul Curtz, Mar 31 2009
a(n) = -1/2*cos(Pi*n) - 3*cos(1/3*Pi*n) - 3^(1/2)*sin(1/3*Pi*n) + 9/2. - Leonid Bedratyuk, May 13 2012
a(n) = A010888(A004000(n+1)). - Ivan N. Ianakiev, Nov 27 2014
From Wesley Ivan Hurt, Apr 20 2015: (Start)
a(n) = a(n-6) for n>5.
a(n) = a(n-1) - a(n-3) + a(n-4) for n>3.
a(n) = (2+3*(n-1 mod 3))*(n mod 2) + (1+3*(-n mod 3))*(n-1 mod 2). (End)
a(n) = 2^n mod 9. - Nikita Sadkov, Oct 06 2018
From Stefano Spezia, Mar 20 2025: (Start)
E.g.f.: 4*cosh(x) - exp(x/2)*(3*cos(sqrt(3)*x/2) + sqrt(3)*sin(sqrt(3)*x/2)) + 5*sinh(x).
a(n) = A007953(2*a(n-1)) = A010888(2*a(n-1)). (End)

Extensions

Edited by R. J. Mathar, Apr 09 2009

A358348 Numbers k such that k == k^k (mod 9).

Original entry on oeis.org

1, 4, 7, 9, 10, 13, 16, 17, 18, 19, 22, 25, 27, 28, 31, 34, 35, 36, 37, 40, 43, 45, 46, 49, 52, 53, 54, 55, 58, 61, 63, 64, 67, 70, 71, 72, 73, 76, 79, 81, 82, 85, 88, 89, 90, 91, 94, 97, 99, 100, 103, 106, 107, 108, 109, 112, 115, 117, 118, 121, 124, 125, 126
Offset: 1

Views

Author

Ivan Stoykov, Nov 11 2022

Keywords

Comments

Each multiple of 9 is in the sequence. Additionally, the squares are also present.

Examples

			4 is a term since 4^4 = 256 == 4 (mod 9).
		

References

  • M. Fujiwara and Y. Ogawa, Introduction to Truly Beautiful Mathematics. Tokyo: Chikuma Shobo, 2005.

Crossrefs

Programs

  • Maple
    A358348 := proc(n)
        2*(n+1)-op(modp(n,9)+1,[2,3,2,1,1,2,1,0,1]) ;
    end proc:
    seq(A358348(n),n=1..50) ; # R. J. Mathar, Mar 29 2023
  • Mathematica
    Select[Range[130], MemberQ[{0, 1, 4, 7, 9, 10, 13, 16, 17}, Mod[#, 18]] &] (* Amiram Eldar, Nov 12 2022 *)
  • PARI
    isok(k) = k == Mod(k,9)^k; \\ Michel Marcus, Nov 22 2022
    
  • Python
    def A358348(n):
        return ((0, 1, 4, 7, 9, 10, 13, 16, 17)[m := n % 9]
             + (n - m << 1))  # Chai Wah Wu, Feb 09 2023

Formula

G.f.: x*(x+1)*(x^7+3*x^5+x^3+x^2+2*x+1)/((1-x)^2*(1+x^3+x^6)*(1+x+x^2)). - Alois P. Heinz, Feb 08 2023
a(n) = 2*(n+1) - b(n) where b(n>=0) = 2,3,2,1,1,2,1,0,1,2,3,2,... has period 9. - Kevin Ryde, Mar 26 2023
Showing 1-2 of 2 results.