cp's OEIS Frontend

This is a front-end for the Online Encyclopedia of Integer Sequences, made by Christian Perfect. The idea is to provide OEIS entries in non-ancient HTML, and then to think about how they're presented visually. The source code is on GitHub.

Showing 1-10 of 12 results. Next

A324403 a(n) = Product_{i=1..n, j=1..n} (i^2 + j^2).

Original entry on oeis.org

1, 2, 400, 121680000, 281324160000000000, 15539794609114833408000000000000, 49933566483104048708063697937367040000000000000000, 19323883089768863178599626514889213871887405416448000000000000000000000000
Offset: 0

Views

Author

Vaclav Kotesovec, Feb 26 2019

Keywords

Comments

Next term is too long to be included.

Crossrefs

Programs

  • Maple
    a:= n-> mul(mul(i^2+j^2, i=1..n), j=1..n):
    seq(a(n), n=0..7);  # Alois P. Heinz, Jun 24 2023
  • Mathematica
    Table[Product[i^2+j^2, {i, 1, n}, {j, 1, n}], {n, 1, 10}]
  • PARI
    a(n) = prod(i=1, n, prod(j=1, n, i^2+j^2)); \\ Michel Marcus, Feb 27 2019
    
  • Python
    from math import prod, factorial
    def A324403(n): return (prod(i**2+j**2 for i in range(1,n) for j in range(i+1,n+1))*factorial(n))**2<Chai Wah Wu, Nov 22 2023

Formula

a(n) ~ 2^(n*(n+1) - 3/4) * exp(Pi*n*(n+1)/2 - 3*n^2 + Pi/12) * n^(2*n^2 - 1/2) / (Pi^(1/4) * Gamma(3/4)).
a(n) = 2*n^2*a(n-1)*Product_{i=1..n-1} (n^2 + i^2)^2. - Chai Wah Wu, Feb 26 2019
For n>0, a(n)/a(n-1) = A272244(n)^2 / (2*n^6). - Vaclav Kotesovec, Dec 02 2023
a(n) = exp(2*Integral_{x=0..oo} (n^2/(x*exp(x)) - (cosh(n*x) - cos(n*x))/(x*exp((n + 1)*x)*(cosh(x) - cos(x)))) dx)/2^(n^2). - Velin Yanev, Jun 30 2025

Extensions

a(0)=1 prepended by Alois P. Heinz, Jun 24 2023

A323540 a(n) = Product_{k=0..n} (k^2 + (n-k)^2).

Original entry on oeis.org

0, 1, 32, 2025, 204800, 30525625, 6307891200, 1727713080625, 606076928000000, 265058191985900625, 141409376995328000000, 90403125002859606705625, 68229510086445571768320000, 60026603304487418050791015625, 60893916244529680380723200000000
Offset: 0

Views

Author

Vaclav Kotesovec, Jan 17 2019

Keywords

Crossrefs

Cf. 2*A000330 and A006331 (with sum instead of product).

Programs

  • Magma
    m:=2; [(&*[k^m + (n-k)^m: k in [0..n]]): n in [0..20]]; // G. C. Greubel, Jan 18 2019
    
  • Mathematica
    Table[Product[k^2+(n-k)^2, {k, 0, n}], {n, 0, 20}]
  • PARI
    m=2; vector(20, n, n--; prod(k=0,n, k^m + (n-k)^m)) \\ G. C. Greubel, Jan 18 2019
    
  • Sage
    m=2; [product(k^m +(n-k)^m for k in (0..n)) for n in (0..20)] # G. C. Greubel, Jan 18 2019

Formula

a(n) ~ exp((Pi-4)*n/2) * n^(2*n+2).

A203475 a(n) = Product_{1 <= i < j <= n} (i^2 + j^2).

Original entry on oeis.org

1, 5, 650, 5525000, 5807194900000, 1226800120038480000000, 77092420109247492627600000000000, 2001314057760220784660590245696000000000000000, 28468550112906756205383102673584071297339520000000000000000000
Offset: 1

Views

Author

Clark Kimberling, Jan 02 2012

Keywords

Comments

Each term divides its successor, as in A203476.

Crossrefs

Programs

  • Magma
    [(&*[(&*[j^2 + k^2: k in [1..j]])/(2*j^2): j in [1..n]]): n in [1..20]]; // G. C. Greubel, Aug 28 2023
    
  • Maple
    a:= n-> mul(mul(i^2+j^2, i=1..j-1), j=2..n):
    seq(a(n), n=1..10);  # Alois P. Heinz, Jul 23 2017
  • Mathematica
    f[j_]:= j^2; z = 15;
    v[n_]:= Product[Product[f[k] + f[j], {j,k-1}], {k,2,n}]
    Table[v[n], {n,z}]           (* A203475 *)
    Table[v[n+1]/v[n], {n,z-1}]  (* A203476 *)
  • SageMath
    [product(product(j^2+k^2 for k in range(1,j)) for j in range(1,n+1)) for n in range(1,21)] # G. C. Greubel, Aug 28 2023

Formula

a(n) ~ c * 2^(n^2/2) * exp(Pi*n*(n+1)/4 - 3*n^2/2 + n) * n^(n*(n-1) - 3/4), where c = A323755 = sqrt(Gamma(1/4)) * exp(Pi/24) / (2*Pi)^(9/8) = 0.274528350333552903800408993482507428142383783773190451181... - Vaclav Kotesovec, Jan 26 2019

Extensions

Name edited by Alois P. Heinz, Jul 23 2017

A272246 a(n) = Product_{k=0..n} (n^3 + k^3).

Original entry on oeis.org

0, 2, 1152, 1428840, 3488808960, 15044494500000, 105235903511101440, 1119277024472896248960, 17216259547948971039129600, 368066786222106315186876633600, 10591209807103301277597696000000000, 399472472359100444604916002033020774400
Offset: 0

Views

Author

Vaclav Kotesovec, Apr 23 2016

Keywords

Crossrefs

Programs

  • Mathematica
    Table[Product[n^3+k^3,{k,0,n}],{n,0,12}]

Formula

a(n) ~ 2^(2*n + 1/2) * n^(3*n + 3) / exp((3 - Pi/sqrt(3))*n).

A272247 a(n) = Product_{k=0..n} (n^4 + k^4).

Original entry on oeis.org

0, 2, 8704, 104372388, 3087748038656, 194985808028125000, 23467500289618753093632, 4938279594477505466022892304, 1699491802948673617630927695904768, 907214902722906584628050661111614570016, 719684491044699824651608981274624000000000000
Offset: 0

Views

Author

Vaclav Kotesovec, Apr 23 2016

Keywords

Crossrefs

Programs

  • Mathematica
    Table[Product[n^4+k^4,{k,0,n}],{n,0,10}]

Formula

a(n) ~ 2^(n+1/2) * (1+sqrt(2))^(sqrt(2)*n) * n^(4*n + 4) / exp((4 - Pi/sqrt(2))*n).

A272248 a(n) = Product_{k=0..n} (n^5 + k^5).

Original entry on oeis.org

0, 2, 67584, 7924375800, 2876035930521600, 2693451205324687500000, 5648896640332217707816550400, 23819277009290664033936067933468800, 185754160490281505676324140907107450880000, 2507604631016507710974687639612411760216253760000
Offset: 0

Views

Author

Vaclav Kotesovec, Apr 23 2016

Keywords

Comments

In general, for p>=1, Product_{k=0..n} (n^p + k^p) ~ sqrt(2) * n^(p*(n+1)) * exp(n*Sum_{j>=1} (-1)^(j+1) / (j*(1 + j*p))).

Crossrefs

Programs

  • Mathematica
    Table[Product[n^5+k^5,{k,0,n}],{n,0,10}]

Formula

a(n) ~ 2^(2*n+1/2) * phi^(sqrt(5)*n) * n^(5*n+5) / exp((5-sqrt(phi)*Pi/5^(1/4))*n), where phi = A001622 = (1+sqrt(5))/2 is the golden ratio.

A367823 a(n) = Product_{k=0..n} (n^6 + k^6).

Original entry on oeis.org

0, 2, 532480, 615291760980, 2759348178649088000, 38607000141072009765625000, 1421393314362014000255258433945600, 120987688662917113214734283836109985530000, 21538956798613753302336535534471908360548515840000, 7407676630843157974199152503244776880017496531101658740000
Offset: 0

Views

Author

Vaclav Kotesovec, Dec 02 2023

Keywords

Crossrefs

Programs

  • Mathematica
    Table[Product[n^6 + k^6, {k, 0, n}], {n, 0, 10}]
  • PARI
    a(n) = prod(k=0, n, n^6 + k^6); \\ Michel Marcus, Dec 02 2023

Formula

a(n) ~ 2^(n + 1/2) * (2 + sqrt(3))^(sqrt(3)*n) * n^(6*n + 6) / exp((6 - Pi)*n).

A367833 a(n) = Product_{k=0..n} (n^8 + k^8).

Original entry on oeis.org

0, 2, 33685504, 3851231199376068, 2670340833224951538384896, 8442437541556000328575439453125000, 96982590530284083757788173242580213780447232, 3406021755102121469537208768079471859185253483110025744
Offset: 0

Views

Author

Vaclav Kotesovec, Dec 02 2023

Keywords

Crossrefs

Programs

  • Mathematica
    Table[Product[n^8 + k^8, {k, 0, n}], {n, 0, 10}]

Formula

a(n) ~ 2^(n + 1/2) * ((2 + sqrt(2 + sqrt(2)))/(2 - sqrt(2 + sqrt(2))))^(sqrt(2 + sqrt(2))*n/2) * (sqrt(2) - 1 + sqrt(4 - 2*sqrt(2)))^(sqrt(2 - sqrt(2))*n) * exp((Pi/sqrt(2 - sqrt(2)) - 8)*n) * n^(8*(n + 1)).

A368622 a(n) = Product_{j=1..n, k=1..n} (j^2 + k^2 + n^2).

Original entry on oeis.org

1, 3, 5832, 172907569296, 419358815743567702818816, 267800543010963952830647446563000000000000, 110831581527076064529150462985910455129725821244148698662830080000
Offset: 0

Views

Author

Vaclav Kotesovec, Jan 01 2024

Keywords

Comments

The limit has a closed form. In Mathematica: Exp[Integrate[Log[x^2 + y^2 + 1], {x,0,1}, {y,0,1}]]. The output is extremely large.

Crossrefs

Programs

  • Mathematica
    Table[Product[j^2 + k^2 + n^2, {j, 1, n}, {k, 1, n}], {n, 0, 10}]

Formula

Limit_{n->oo} a(n)^(1/(n^2)) / n^2 = exp(Integral_{x=0..1, y=0..1} log(x^2 + y^2 + 1) dy dx) = 1.6143980185761253961882683158432481977126507900460725431661...

A367927 a(n) = Product_{k=1..n} (n^2 + k^2)^k.

Original entry on oeis.org

1, 2, 320, 9856080, 111411200000000, 758912215744345000000000, 4641055652546245989752776320614400000, 35539706227151665491451514343890494014992000000000000, 453355203871266077337924186645041169745278527392553369600000000000000000
Offset: 0

Views

Author

Vaclav Kotesovec, Dec 05 2023

Keywords

Crossrefs

Cf. A272244.

Programs

  • Mathematica
    Table[Product[(k^2 + n^2)^k, {k, 1, n}], {n, 0, 10}]

Formula

a(n) ~ 2^(n^2 + n/2 + 1/12) * n^(n*(n+1)) / exp(n^2/2 - 1/12).
Showing 1-10 of 12 results. Next