A289139 -id:A289139 - cp's OEIS frontend

A289122 a(n) is number of odd integers divisible by 11 in the interval ]2(n-1)^2, 2n^2[.

0, 0, 0, 1, 0, 1, 1, 1, 2, 1, 2, 2, 2, 2, 3, 2, 3, 3, 3, 4, 3, 4, 4, 4, 4, 5, 4, 5, 5, 5, 6, 5, 6, 6, 6, 6, 7, 6, 7, 7, 7, 8, 7, 8, 8, 8, 8, 9, 8, 9, 9, 9, 10, 9, 10, 10, 10, 10, 11, 10, 11, 11, 11, 12, 11, 12, 12, 12, 12, 13, 12, 13, 13, 13, 14, 13, 14, 14, 14, 14, 15

Offset: 0

Ralf Steiner, Jun 25 2017

This sequence has the form (0+2k,0+2k,0+2k,1+2k,0+2k,1+2k,1+2k,1+2k,2+2k, 1+2k,2+2k) for k>=0.

Index entries for linear recurrences with constant coefficients, signature (1,0,0,0,0,0,0,0,0,0,1,-1).

Cf. A289120, A289133, A288156, A004523, A289139.

Table[Count[Mod[Table[2((n-1)^2 +k) -1,{k,1,2n-1}],11],0],{n,0,50}]
LinearRecurrence[{1,0,0,0,0,0,0,0,0,0,1,-1},{0,0,0,1,0,1,1,1,2,1,2,2},90] (* Harvey P. Dale, Aug 24 2017 *)

a(n) = sum(k=2*(n-1)^2, 2*n^2, ((k % 2) && ((k % 11) == 0))); \\ Michel Marcus, Jun 26 2017

a(n + 11*k) = a(n) + 2*k. - David A. Corneth, Jun 25 2017

G.f.: (x^10-x^9+x^8+x^5-x^4+x^3)/(x^12-x^11-x+1). - Alois P. Heinz, Jun 26 2017

A289133 a(n) is the number of odd integers divisible by 9 in ]2(n-1)^2, 2n^2[.

Original entry on oeis.org

0, 0, 0, 1, 1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 7, 7, 7, 7, 7, 8, 8, 8, 8, 9, 9, 9, 9, 9, 10, 10, 10, 10, 11, 11, 11, 11, 11, 12, 12, 12, 12, 13, 13, 13, 13, 13, 14, 14, 14, 14, 15, 15, 15, 15, 15, 16, 16, 16, 16, 17, 17, 17, 17, 17, 18

Offset: 0

Ralf Steiner, Jun 25 2017

This sequence has the form (0+2k,0+2k,0+2k,1+2k,1+2k,1+2k,1+2k,1+2k,2+2k) for k>=0.

Index entries for linear recurrences with constant coefficients, signature (1,0,0,0,0,0,0,0,1,-1).

Cf. A289120, A289122, A288156, A004523, A289139.

Table[Count[Mod[Table[2((n-1)^2 +k)-1,{k,1,2 n-1}],9],0],{n,0,50}]

a(n) = sum(k=2*(n-1)^2, 2*n^2, ((k % 2) && ((k % 9) == 0))); \\ Michel Marcus, Jun 26 2017

a(n + 9*k) = a(n) + 2*k.

G.f.: (x^8+x^3)/(x^10-x^9-x+1). - Alois P. Heinz, Jun 26 2017

More terms from Michel Marcus, Jun 26 2017

A289195 a(n) is the number of odd integers divisible by 5 in ]4(n-1)^2, 4n^2[.

Original entry on oeis.org

0, 0, 2, 2, 2, 4, 4, 6, 6, 6, 8, 8, 10, 10, 10, 12, 12, 14, 14, 14, 16, 16, 18, 18, 18, 20, 20, 22, 22, 22, 24, 24, 26, 26, 26, 28, 28, 30, 30, 30, 32, 32, 34, 34, 34, 36, 36, 38, 38, 38, 40, 40, 42, 42, 42, 44, 44, 46, 46, 46, 48, 48, 50, 50, 50, 52, 52, 54

Offset: 0

Ralf Steiner, Jun 28 2017

This sequence has the form (0+4k,0+4k,2+4k,2+4k,2+4k) for k>=0.

Colin Barker, Table of n, a(n) for n = 0..1000
Index entries for linear recurrences with constant coefficients, signature (1,0,0,0,1,-1).

Cf. A289199, A289139, A289120, A289133, A289122, A288156, A004523.

Table[Count[Mod[Table[2(2(n-1)^2+k)-1,{k,1,4 n-2}],5],0],{n,0,50}]

concat(vector(2), Vec(2*x^2*(1 + x)*(1 - x + x^2) / ((1 - x)^2*(1 + x + x^2 + x^3 + x^4)) + O(x^100))) \\ Colin Barker, Jul 04 2017

a(n + 5*k) = a(n) + 4*k.
From Colin Barker, Jul 04 2017: (Start)
G.f.: 2*x^2*(1 + x)*(1 - x + x^2) / ((1 - x)^2*(1 + x + x^2 + x^3 + x^4)).
a(n) = a(n-1) + a(n-5) - a(n-6) for n>5.
(End)

A289199 a(n) is the number of odd integers divisible by 13 in the open interval (12(n-1)^2, 12n^2).

Original entry on oeis.org

0, 0, 2, 2, 3, 5, 5, 6, 7, 7, 9, 10, 10, 12, 12, 14, 14, 15, 17, 17, 18, 19, 19, 21, 22, 22, 24, 24, 26, 26, 27, 29, 29, 30, 31, 31, 33, 34, 34, 36, 36, 38, 38, 39, 41, 41, 42, 43, 43, 45, 46, 46, 48, 48, 50, 50, 51, 53, 53, 54, 55, 55, 57, 58, 58, 60, 60, 62, 62, 63, 65

Offset: 0

Ralf Steiner, Jun 28 2017

This sequence has the form (0+12k, 0+12k, 2+12k, 2+12k, 3+12k, 5+12k, 5+12k, 6+12k, 7+12k, 7+12k, 9+12k, 10+12k, 10+12k) for k >= 0.
Theorems: A) Generally for an interval (2*m*(n-1)^2,2*m*n^2) and a divisor d with 2*m < d there is a unique d-length form (e_i+2*m*k)_{i=0..d-1, k>=0} with e_i in [0,2*m]; here m = 6, d = 13.
B) Sum_{i=0..d-1}e_i = m*(d-2); here 66 = 6*(13-2).
Proof:
A) In d consecutive intervals
(2*m*(n-1)^2,2*m*(n+2)^2) there are m*d*(2*k+d) consecutive odd numbers and therefore m*(2*k+d) multiples of d where k=floor((n-1)/d).
B) With initial value a(0)=0 we have a(d)=2*m and thus Sum_{i=0..d-1} e_i = Sum_{i=1..d}a(i)-a(d) = m(2*0+d)-2*m = m*(d-2). Q.E.D.

Colin Barker, Table of n, a(n) for n = 0..1000
Index entries for linear recurrences with constant coefficients, signature (1,0,0,0,0,0,0,0,0,0,0,0,1,-1).

Cf. A004523, A288156, A289120, A289122, A289133, A289139, A289195.

Table[Count[Mod[Table[2(6(n-1)^2 +k)-1,{k,12 n-6}],13],0],{n,0,70}]

a(n)=(12*n^2+12)\26 - (12*n^2-24*n+25)\26 \\ Charles R Greathouse IV, Jun 29 2017

concat(vector(2), Vec(x^2*(1 + x)*(1 - x + x^2)*(2 + x^2 + x^6 + 2*x^8) / ((1 - x)^2*(1 + x + x^2 + x^3 + x^4 + x^5 + x^6 + x^7 + x^8 + x^9 + x^10 + x^11 + x^12)) + O(x^100))) \\ Colin Barker, Jul 03 2017

a(n + 13*k) = a(n) + 12*k.
a(n) = 12n/13 + O(1). - Charles R Greathouse IV, Jun 29 2017
From Colin Barker, Jul 03 2017: (Start)
G.f.: x^2*(1 + x)*(1 - x + x^2)*(2 + x^2 + x^6 + 2*x^8) / ((1 - x)^2*(1 + x + x^2 + x^3 + x^4 + x^5 + x^6 + x^7 + x^8 + x^9 + x^10 + x^11 + x^12)).
a(n) = a(n-1) + a(n-13) - a(n-14) for n>13.
(End)

cp's OEIS Frontend

A289122 a(n) is number of odd integers divisible by 11 in the interval ]2*(n-1)^2, 2*n^2[.

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A289133 a(n) is the number of odd integers divisible by 9 in ]2*(n-1)^2, 2*n^2[.

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A289195 a(n) is the number of odd integers divisible by 5 in ]4*(n-1)^2, 4*n^2[.

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A289199 a(n) is the number of odd integers divisible by 13 in the open interval (12*(n-1)^2, 12*n^2).

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A289122 a(n) is number of odd integers divisible by 11 in the interval ]2(n-1)^2, 2n^2[.

A289133 a(n) is the number of odd integers divisible by 9 in ]2(n-1)^2, 2n^2[.

A289195 a(n) is the number of odd integers divisible by 5 in ]4(n-1)^2, 4n^2[.

A289199 a(n) is the number of odd integers divisible by 13 in the open interval (12(n-1)^2, 12n^2).